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Find the rates of change of total revenue, cost, and profit with respect to time. Assume that \(R(x)\) and \(C(x)\) are in dollars. $$ \begin{aligned} &R(x)=280 x-0.4 x^{2}\\\ &C(x)=5000+0.6 x^{2}\\\ &\text { when } x=200 \text { and } d x / d t=300 \text { units per day } \end{aligned} $$

Short Answer

Expert verified
Revenue increases by $12,000 per day, cost increases by $72,000 per day, and profit decreases by $60,000 per day.

Step by step solution

01

Find the Rate of Change of Revenue

The total revenue function is given by \(R(x) = 280x - 0.4x^2\). To find the rate of change of revenue with respect to time, differentiate \(R(x)\) with respect to \(x\): \[\frac{dR}{dx} = 280 - 0.8x\] Then, use the chain rule to find \(\frac{dR}{dt}\): \[\frac{dR}{dt} = \frac{dR}{dx} \times \frac{dx}{dt} = (280 - 0.8x) \times 300\] Substitute \(x = 200\) to find \(\frac{dR}{dt}\): \[\frac{dR}{dt} = (280 - 0.8 \times 200) \times 300 = 12000 \text{ dollars per day}\]
02

Find the Rate of Change of Cost

The total cost function is given by \(C(x) = 5000 + 0.6x^2\). Differentiate \(C(x)\) with respect to \(x\): \[\frac{dC}{dx} = 1.2x\] Using the chain rule, find \(\frac{dC}{dt}\): \[\frac{dC}{dt} = \frac{dC}{dx} \times \frac{dx}{dt} = 1.2x \times 300\] Substitute \(x = 200\) to calculate \(\frac{dC}{dt}\): \[\frac{dC}{dt} = 1.2 \times 200 \times 300 = 72000 \text{ dollars per day}\]
03

Find the Rate of Change of Profit

Profit is defined as the difference between revenue and cost: \(P(x) = R(x) - C(x)\). The rate of change of profit \(\frac{dP}{dt}\) is given by: \[\frac{dP}{dt} = \frac{dR}{dt} - \frac{dC}{dt}\] Substitute \(\frac{dR}{dt} = 12000 \text{ dollars per day}\) and \(\frac{dC}{dt} = 72000 \text{ dollars per day}\) to find \(\frac{dP}{dt}\): \[\frac{dP}{dt} = 12000 - 72000 = -60000 \text{ dollars per day}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Total Revenue
Total revenue represents the total income generated from selling a certain number of units of a product. It plays a crucial role in understanding a business's financial health.

For our exercise, the total revenue function is given as:
  • \( R(x) = 280x - 0.4x^2 \)
This formula signifies that total revenue depends on two factors: a linearly increasing part, seen in \( 280x \), and a diminishing return effect, represented by \( -0.4x^2 \).
To find how revenue changes with respect to time, we need to use calculus. Differentiating the revenue function with respect to \( x \) gives us the rate of change of revenue per unit sold:
  • \( \frac{dR}{dx} = 280 - 0.8x \)
Next, applying the chain rule allows us to convert this rate into a time-dependent rate:
  • \( \frac{dR}{dt} = (280 - 0.8x) \times \frac{dx}{dt} \)
When evaluated at \( x = 200 \) with \( \frac{dx}{dt} = 300 \), it results in:
  • \( \frac{dR}{dt} = 12000 \) dollars per day
This indicates that at 200 units, the revenue increases by $12,000 every day as production increases by 300 units a day.
Total Cost
Total cost is the complete expense incurred in producing a set number of goods. Understanding cost trends is essential to maintaining operational efficiency.

For this case, the total cost function is:
  • \( C(x) = 5000 + 0.6x^2 \)
This expression includes a base cost of \(5,000, plus a variable component growing quadratically with production, \( 0.6x^2 \).
Differentiating the cost function with respect to \( x \) reveals the cost change per additional unit:
  • \( \frac{dC}{dx} = 1.2x \)
Utilizing the chain rule allows conversion to a time-dependent cost change:
  • \( \frac{dC}{dt} = 1.2x \times \frac{dx}{dt} \)
When you substitute \( x = 200 \) and \( \frac{dx}{dt} = 300 \), this becomes:
  • \( \frac{dC}{dt} = 72000 \) dollars per day
So, the cost increases by \)72,000 each day given a production rate increase of 300 units per day.
Profit
Profit represents the net earnings of a business after subtracting all costs from the revenue. Studying the rate of change of profit helps businesses anticipate financial trends.

In this context, profit is simply revenue minus cost:
  • \( P(x) = R(x) - C(x) \)
The rate of profit change over time is therefore determined by:
  • \( \frac{dP}{dt} = \frac{dR}{dt} - \frac{dC}{dt} \)
With previously calculated values for revenue and cost rates:
  • \( \frac{dR}{dt} = 12000 \) dollars per day
  • \( \frac{dC}{dt} = 72000 \) dollars per day
The result for the profit rate of change becomes:
  • \( \frac{dP}{dt} = 12000 - 72000 = -60000 \) dollars per day
This negative value indicates a loss rate of $60,000 per day, suggesting a need to reassess production costs or pricing strategies to achieve profitability.

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