/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 99 Find the interval(s) for which \... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the interval(s) for which \(f^{\prime}(x)\) is positive. Use the derivative to help explain why \(f(x)=x^{5}+x^{3}\) increases for all \(x\) in \((-\infty, \infty)\).

Short Answer

Expert verified
The derivative \( f'(x) = 5x^4 + 3x^2 \) is positive for all \( x \in (-\infty, \infty) \), so \( f(x) \) increases everywhere.

Step by step solution

01

Find the Derivative

To determine where the function is increasing, we need the derivative. Start by finding the derivative of \( f(x) = x^5 + x^3 \) using the power rule. The power rule states that \( \frac{d}{dx}[x^n] = nx^{n-1} \), so apply it to each term separately. The derivative \( f'(x) \) is \( 5x^4 + 3x^2 \).
02

Analyze the Sign of the Derivative

To determine where \( f'(x) \) is positive, analyze the expression \( 5x^4 + 3x^2 \). Notice that both terms are positive for any real \( x \), because squares of real numbers are non-negative. Therefore, \( 5x^4 + 3x^2 \) is always positive.
03

Identify the Interval

Since \( 5x^4 + 3x^2 \) is positive for all \( x \in (-\infty, \infty) \), the derivative \( f'(x) \) is positive for this entire interval. Thus, \( f(x) \) increases for all real numbers \( x \).
04

Conclusion

Since there are no critical points or intervals where the derivative is zero or negative, \( f(x) = x^5 + x^3 \) increases for all \( x \) in \( (-\infty, \infty) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
In calculus, a derivative is a measure of how a function changes as its input changes. Think of it as the "rate of change" or the "slope" of the function at any given point. For example, if you have a function that describes the position of a car over time, the derivative of this function will tell you the speed of the car at any particular moment.
To find the derivative of a function, we apply rules such as the power rule, among others. These rules help us understand how the function behaves. For the function given here, \(f(x) = x^5 + x^3\), the derivative \(f'(x) = 5x^4 + 3x^2\) provides valuable information about the nature of the function's increase or decrease across its domain.
Power Rule
One of the most frequently used formulas in calculus is the power rule. It's a handy tool for finding the derivative of functions in the form \( x^n \). According to the power rule, the derivative of \( x^n \) is \( nx^{n-1} \). This rule is simple yet powerful, making the process of finding derivatives straightforward.
When applying the power rule to \(f(x) = x^5 + x^3\), we treat each term separately:
  • For \(x^5\), the derivative is \(5x^4\) (since 5 times \(x^{5-1}\) is \(5x^4\)).
  • For \(x^3\), the derivative is \(3x^2\) (since 3 times \(x^{3-1}\) is \(3x^2\)).
This gives us a complete derivative of \(5x^4 + 3x^2\). The power rule simplifies the task and ensures accuracy, facilitating a deeper understanding of how the function behaves over its domain.
Increasing Functions
An increasing function is one where, as the input or \(x\) value increases, the output or \(f(x)\) value also increases. This concept is visually observable on a graph as it slopes upwards from left to right. A function is considered increasing on an interval if its derivative is positive for every point within that interval.
For the function \(f(x) = x^5 + x^3\) we discussed, we found its derivative to be \(f'(x) = 5x^4 + 3x^2\). To understand where the function is increasing, look at the sign of the derivative. Here, both \(5x^4\) and \(3x^2\) are never negative for any real number. Both terms become positive for any real value of \(x\), ensuring that \(f'(x)\) is always greater than zero.
Since \(f'(x) > 0\) for all values of \(x\) in \((-\infty, \infty)\), \(f(x) = x^5 + x^3\) is increasing on this entire interval. This tells us that as \(x\) continues to grow, \(f(x)\) keeps getting larger, thus confirming that \(f(x)\) is an increasing function across its whole domain.

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Most popular questions from this chapter

Use GRAPH and TRACE to find each limit. When necessary, state that the limit does not exist. $$ \begin{array}{l} \text { For } g(x)=\frac{20 x^{2}}{x^{3}+2 x^{2}+5 x} \\ \text { find } \lim _{x \rightarrow \infty} g(x) \text { and } \lim _{x \rightarrow-\infty} g(x) . \end{array} $$

Let \(f\) and \(g\) be differentiable over an open interval containing \(x=a\). If $$ \lim _{x \rightarrow a}\left(\frac{f(x)}{g(x)}\right)=\frac{0}{0} \quad \text { or } \quad \lim _{x \rightarrow a}\left(\frac{f(x)}{g(x)}\right)=\frac{\pm \infty}{\pm \infty} $$ and if \(\lim _{x \rightarrow a}\left(\frac{f^{\prime}(x)}{g^{\prime}(x)}\right)\) exists, then $$ \lim _{x \rightarrow a}\left(\frac{f(x)}{g(x)}\right)=\lim _{x \rightarrow a}\left(\frac{f^{\prime}(x)}{g^{\prime}(x)}\right) $$ The forms \(0 / 0\) and \(\pm \infty / \pm \infty\) are said to be indeterminate. In such cases, the limit may exist, and l'Hôpital's Rule offers a way to find the limit using differentiation. For example, in Example 1 of Section \(1.1,\) we showed that $$ \lim _{x \rightarrow 1}\left(\frac{x^{2}-1}{x-1}\right)=2 $$ Since, for \(x=1,\) we have \(\left(x^{2}-1\right)(x-1)=0 / 0,\) we differentiate the numerator and denominator separately, and reevaluate the limit: $$ \lim _{x \rightarrow 1}\left(\frac{x^{2}-1}{x-1}\right)=\lim _{x \rightarrow 1}\left(\frac{2 x}{1}\right)=2 $$ Use this method to find the following limits. Be sure to check that the initial substitution results in an indeterminate form. $$ \lim _{x \rightarrow-\infty}\left(\frac{3 x^{3}+x+11}{6 x^{3}+x+2}\right) $$

Then estimate the \(x\) -values at which tangent lines are horizontal. $$ f(x)=x^{4}-3 x^{2}+1 $$

For each function, find the points on the graph at which the tangent line has slope 1 . $$ y=-0.025 x^{2}+4 x $$

Find dy/dx. Each function can be differentiated using the rules developed in this section, but some algebra may be required beforehand. $$ y=(x+1)^{3} $$

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