Chapter 1: Problem 53
Find the simplified difference quotient for each function listed. $$ f(x)=\frac{1}{1-x} $$
Short Answer
Expert verified
The simplified difference quotient is \( \frac{-1}{(1-x-h)(1-x)} \).
Step by step solution
01
Understand the Difference Quotient
The difference quotient for a function \( f(x) \) is given by the formula: \[\frac{f(x+h) - f(x)}{h}\]where \( h \) is not equal to zero. This represents the average rate of change of the function \( f(x) \) over the interval from \( x \) to \( x+h \).
02
Substitute into the Difference Quotient
First, find \( f(x+h) \) for the function \( f(x) = \frac{1}{1-x} \). Replace \( x \) with \( x+h \) in the function: \[f(x+h) = \frac{1}{1-(x+h)} = \frac{1}{1-x-h}\]Now, substitute \( f(x) \) and \( f(x+h) \) into the difference quotient:\[\frac{\frac{1}{1-x-h} - \frac{1}{1-x}}{h}\]
03
Simplify the Numerator
To simplify \( \frac{1}{1-x-h} - \frac{1}{1-x} \), find a common denominator. The common denominator is \((1-x-h)(1-x)\).Express each fraction with the common denominator and simplify:\[\frac{(1-x) - (1-x-h)}{(1-x-h)(1-x)} = \frac{-h}{(1-x-h)(1-x)}\]
04
Simplify the Difference Quotient
Substitute back the simplified numerator into the difference quotient:\[\frac{-h}{(1-x-h)(1-x)} \times \frac{1}{h} = \frac{-1}{(1-x-h)(1-x)}\]This is the simplified form of the difference quotient.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Average Rate of Change
The average rate of change is a concept that helps us understand how a function's value changes over a certain interval. Imagine driving a car. The distance you cover over a period of time gives you an average speed. In the case of functions, this is represented through the difference quotient formula:
- \( \frac{f(x+h) - f(x)}{h} \)
Function Simplification
Function simplification makes complex algebraic expressions easier to handle. Consider the expression you had earlier: the difference quotient with \( f(x) = \frac{1}{1-x} \) and \( f(x+h) = \frac{1}{1-x-h} \).First, you find the common denominator, which in this case is \((1-x-h)(1-x)\). It allows you to combine two fractions into one by aligning their denominators, simplifying what initially might appear as a messy algebraic expression.
- For \( \frac{1}{1-x-h} - \frac{1}{1-x} \), you express both fractions in terms of this common denominator.
- This grants you \( \frac{-h}{(1-x-h)(1-x)} \) as the simplified numerator.
Rational Functions
Rational functions are expressions formed by the ratio of two polynomials. In our example, the function \( f(x) = \frac{1}{1-x} \) is a simple rational function.
- The numerator is \(1\), and the denominator is \(1-x\).
- They typically have vertical asymptotes, places where the function isn't defined, like \( x = 1 \) for this function.