Chapter 1: Problem 48
Find \(y^{\prime}\) $$ y=\frac{2}{x}-\frac{x}{2} $$
Short Answer
Expert verified
\( y' = -\frac{2}{x^2} - \frac{1}{2} \)
Step by step solution
01
Differentiate the First Term
The first term of the function is \( \frac{2}{x} \), which can be rewritten as \( 2x^{-1} \) for differentiation purposes. Using the power rule, \( \frac{d}{dx}(x^n) = nx^{n-1} \), the derivative of \( 2x^{-1} \) is \( -2x^{-2} \).
02
Differentiate the Second Term
The second term of the function is \( -\frac{x}{2} \). Applying the constant rule and the fact that the derivative of \( x \) is 1, we get \( \frac{d}{dx}\left(-\frac{x}{2}\right) = -\frac{1}{2} \).
03
Combine the Derivatives
Combine the derivatives obtained in Steps 1 and 2 to find \( y' \). Thus, \( y' = -2x^{-2} - \frac{1}{2} \).
04
Write the Answer in Fraction Form
Express \( -2x^{-2} \) as \( -\frac{2}{x^2} \). Thus, the final form of the derivative is: \[ y' = -\frac{2}{x^2} - \frac{1}{2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The Power Rule is a fundamental tool in calculus for finding the derivative of a function that is in the form of a power. Whenever you have a term like \(x^n\), the Power Rule comes into play. It tells us that the derivative of \(x^n\) with respect to \(x\) is \(n \cdot x^{n-1}\). This means you bring down the exponent as a multiplier and decrease the exponent by one.
In our original exercise, we started with the term \(2x^{-1}\), which initially looks complex with the negative exponent. However, by applying the Power Rule, the differentiation becomes straightforward:
\(-1\) (the exponent) \,\cdot\, 2 (constant) = \(-2\)
\(x^{-1-1} = x^{-2}\)
Thus, the derivative of \(2x^{-1}\) is \(-2x^{-2}\). This showcases the efficiency of the Power Rule in simplifying differentiation.
Understanding and practicing this rule will significantly enhance your problem-solving capabilities in calculus.
In our original exercise, we started with the term \(2x^{-1}\), which initially looks complex with the negative exponent. However, by applying the Power Rule, the differentiation becomes straightforward:
\(-1\) (the exponent) \,\cdot\, 2 (constant) = \(-2\)
\(x^{-1-1} = x^{-2}\)
Thus, the derivative of \(2x^{-1}\) is \(-2x^{-2}\). This showcases the efficiency of the Power Rule in simplifying differentiation.
Understanding and practicing this rule will significantly enhance your problem-solving capabilities in calculus.
Constant Rule
The Constant Rule is another essential rule in calculus which states that the derivative of a constant multiplied by a function is just the constant multiplied by the derivative of the function. In simpler terms, if you have a term where a constant is multiplied by a variable (like \(-\frac{x}{2}\)), you can pull the constant out and then differentiate the remaining variable separately.
Let's apply the Constant Rule to our function. The term \(-\frac{x}{2}\) can be seen as \(-\frac{1}{2} \cdot x\). According to the Constant Rule, it becomes:
Let's apply the Constant Rule to our function. The term \(-\frac{x}{2}\) can be seen as \(-\frac{1}{2} \cdot x\). According to the Constant Rule, it becomes:
- The constant \(-\frac{1}{2}\) stays the same.
- The derivative of \(x\) is simply \(1\).
Differentiation Steps
Differentiating a function with multiple terms involves handling each term independently before combining the results. This process is crucial for solving derivatives accurately.
Here's how we applied these steps:
Here's how we applied these steps:
- **Step 1:** For the term \(\frac{2}{x}\), write it as \(2x^{-1}\). Apply the Power Rule to find its derivative, which became \(-2x^{-2}\).
- **Step 2:** For the term \(-\frac{x}{2}\), apply the Constant Rule and find that its derivative is \(-\frac{1}{2}\).
- **Step 3:** After finding the derivatives of each term, combine these results to get the overall derivative of the function.
- **Step 4:** Simplify the answer if possible, such as converting \(-2x^{-2}\) into \(-\frac{2}{x^2}\).