/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 84 $$ \begin{aligned} &\tex... [FREE SOLUTION] | 91Ó°ÊÓ

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$$ \begin{aligned} &\text { A function } f \text { is given by }\\\ &f(x)=|x-2|+|x+1|-5\\\ &\text { Find } f(-3), f(-2), f(0), \text { and } f(4) \end{aligned} $$

Short Answer

Expert verified
The values are: \( f(-3) = 2 \), \( f(-2) = 0 \), \( f(0) = -2 \), and \( f(4) = 2 \).

Step by step solution

01

Understand the Absolute Function

The function given is \( f(x) = |x-2| + |x+1| - 5 \). The absolute value, \(|a|\), defines the distance of \(a\) from zero on the number line and is always non-negative.
02

Evaluate \(f(-3)\)

Substitute \(x = -3\) into the function: \[ f(-3) = |-3 - 2| + |-3 + 1| - 5 \] Simplify: \[ = | -5 | + | -2 | - 5 \] \[ = 5 + 2 - 5 \] \[ = 7 - 5 = 2 \].
03

Evaluate \(f(-2)\)

Substitute \(x = -2\) into the function: \[ f(-2) = |-2 - 2| + |-2 + 1| - 5 \] Simplify: \[ = | -4 | + | -1 | - 5 \] \[ = 4 + 1 - 5 \] \[ = 5 - 5 = 0 \].
04

Evaluate \(f(0)\)

Substitute \(x = 0\) into the function: \[ f(0) = |0 - 2| + |0 + 1| - 5 \] Simplify: \[ = | -2 | + | 1 | - 5 \] \[ = 2 + 1 - 5 \] \[ = 3 - 5 = -2 \].
05

Evaluate \(f(4)\)

Substitute \(x = 4\) into the function: \[ f(4) = |4 - 2| + |4 + 1| - 5 \] Simplify: \[ = |2| + |5| - 5 \] \[ = 2 + 5 - 5 \] \[ = 7 - 5 = 2 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Value
The absolute value is a key concept in mathematics. It refers to the distance a number is from zero on the number line. This value is always non-negative, because distance cannot be negative. In mathematical terms, the absolute value of a number \( a \), denoted as \( |a| \), can be defined as:
  • \( |a| = a \) if \( a \geq 0 \)
  • \( |a| = -a \) if \( a < 0 \)
This means if you have a negative value inside the absolute value, you multiply by \(-1\) to make it positive. For example, \(|-5| = 5\) and \(|3| = 3\). When dealing with expressions inside absolute values, always solve the expression first and then apply the absolute condition. For example, \(|x - 2|\) means to subtract 2 from \(x\) first, and then take the absolute value of that result.
Evaluating Functions
Evaluating functions is about finding out what a function equals for specific input values. For the given function \( f(x) = |x-2| + |x+1| - 5 \), our task is to substitute different \( x \) values into the function to solve for \( f(x) \). The steps are simple:
  • Substitute the value of \( x \) into the function.
  • Calculate the result of each expression inside the absolute value.
  • Apply the absolute value rule to any negative results.
  • Add or subtract according to the function's operations.
For example, when evaluating \( f(-3) \), substitute \( x = -3 \):
\[ f(-3) = |-3 - 2| + |-3 + 1| - 5 \]
Simplify to get:
\[ = | -5 | + | -2 | - 5 \]
\[ = 5 + 2 - 5 = 2 \]
Each step involves clear computation and application of absolute value properties for accurate results.
Piecewise Functions
A piecewise function is a function composed of several sub-functions, each applying to a particular interval of the main function's domain. It allows a function to behave differently based on the input value. Although our given function isn't explicitly a piecewise function, it's beneficial to understand the concept when dealing with complex absolute value functions, as they can sometimes be broken into cases.In the function \( f(x) = |x-2| + |x+1| - 5 \), breaking down the absolute value expressions can resemble analyzing a piecewise function. For example, for \(|x-2|\), we consider:
  • \(x-2 \geq 0\) which simplifies to \(x \geq 2\), yielding \(|x-2| = x-2\)
  • \(x-2 < 0\) which simplifies to \(x < 2\), yielding \(|x-2| = 2-x\)
Applying similar logic to \(|x+1|\), the function can be approached as dependent on the value of \(x\). Recognizing these intervals helps in accurately computing the given value, ensuring precise evaluation across different sub-ranges.

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