Chapter 0: Problem 83
Use the TABLE feature to construct \(a\) table for the function under the given conditions. $$ f(x)=\frac{3}{x^{2}-4} ; \text { TblStart }=-3 ; \Delta \mathrm{Tbl}=1 $$
Short Answer
Expert verified
Create a table for \( x = -3 \) to \( 3 \) and note that \( f(x) \) is undefined at \( x = -2 \) and \( 2 \).
Step by step solution
01
Understand the Function
We are given the function \( f(x) = \frac{3}{x^2 - 4} \). This is a rational function where the denominator is \( x^2 - 4 \). We need to evaluate this function for different values of \( x \).
02
Determine the Range of x-Values
Since TblStart is given as -3 and \( \Delta \)Tbl is 1, we will evaluate the function at \( x = -3, -2, -1, 0, 1, 2, 3 \). These values are in an arithmetic sequence starting from -3 and increasing by 1 each time.
03
Handle Undefined Values
In the function \( f(x) = \frac{3}{x^2 - 4} \), the denominator becomes zero when \( x^2 - 4 = 0 \). Solving gives \( x^2 = 4 \) or \( x = \pm 2 \). Therefore, the function is undefined for \( x = -2 \) and \( 2 \). We need to make note of these points.
04
Fill the Table
Now, calculate \( f(x) \) for each value of \( x \) in the range:- If \( x = -3 \), \( f(-3) = \frac{3}{(-3)^2 - 4} = \frac{3}{9 - 4} = \frac{3}{5} \).- If \( x = -2 \), the function is undefined.- If \( x = -1 \), \( f(-1) = \frac{3}{(-1)^2 - 4} = \frac{3}{1 - 4} = -1 \).- If \( x = 0 \), \( f(0) = \frac{3}{0^2 - 4} = -\frac{3}{4} \).- If \( x = 1 \), \( f(1) = \frac{3}{1^2 - 4} = -1 \).- If \( x = 2 \), the function is undefined.- If \( x = 3 \), \( f(3) = \frac{3}{3^2 - 4} = \frac{3}{5} \).
05
Construct the Table
Create a table with \( x \) values and their corresponding \( f(x) \) values:| x | f(x) ||---|-----------|| -3 | \(\frac{3}{5}\) || -2 | Undefined || -1 | -1 || 0 | -\(\frac{3}{4}\) || 1 | -1 || 2 | Undefined || 3 | \(\frac{3}{5}\) |
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
Determining the domain of a function is an important step in understanding its behavior. The domain of a function includes all the possible input values (x-values) for which the function is defined. For rational functions, such as \( f(x) = \frac{3}{x^2 - 4} \), the denominator cannot be zero as it would make the function undefined.
To find when \( f(x) \) is undefined, set the denominator equal to zero and solve for \( x \):
\[ x^2 - 4 = 0 \]
Solving this gives \( x^2 = 4 \), therefore \( x = \pm 2 \). This means the function is undefined when \( x = -2 \) and \( x = 2 \).
So, the domain of \( f(x) \) is all real numbers except \( x = -2 \) and \( x = 2 \), which we can express as:
\[ \text{Domain of } f(x): \{ x \in \mathbb{R} \mid x eq -2, 2 \} \]
Understanding these domain restrictions helps to avoid calculation errors and gives a clearer picture of how the function behaves across different values.
To find when \( f(x) \) is undefined, set the denominator equal to zero and solve for \( x \):
\[ x^2 - 4 = 0 \]
Solving this gives \( x^2 = 4 \), therefore \( x = \pm 2 \). This means the function is undefined when \( x = -2 \) and \( x = 2 \).
So, the domain of \( f(x) \) is all real numbers except \( x = -2 \) and \( x = 2 \), which we can express as:
\[ \text{Domain of } f(x): \{ x \in \mathbb{R} \mid x eq -2, 2 \} \]
Understanding these domain restrictions helps to avoid calculation errors and gives a clearer picture of how the function behaves across different values.
Arithmetic Sequence
An arithmetic sequence is a series of numbers where the difference between consecutive terms is constant. This difference is known as the common difference. In the context of our exercise, the sequence of \( x \) values follows an arithmetic sequence.
The given sequence starts at \( -3 \) and increases by \( 1 \) (the common difference) each time, forming the sequence \( -3, -2, -1, 0, 1, 2, 3 \). This arithmetic progression organizes the way we evaluate the rational function \( f(x) \) across a range of \( x \) values.
Identifying the arithmetic sequence in tasks like this assists in calculating values efficiently and ensuring all relevant x-values are considered.
The given sequence starts at \( -3 \) and increases by \( 1 \) (the common difference) each time, forming the sequence \( -3, -2, -1, 0, 1, 2, 3 \). This arithmetic progression organizes the way we evaluate the rational function \( f(x) \) across a range of \( x \) values.
Identifying the arithmetic sequence in tasks like this assists in calculating values efficiently and ensuring all relevant x-values are considered.
- The first term is \( -3 \)
- The common difference is \( +1 \)
- Subsequent terms are created by adding \( 1 \) to the previous term
Table of Values
A table of values is a simple but vital tool to visualize how a function behaves over a set of inputs, helping you observe patterns, calculate function outputs, and identify undefined points.
For the function \( f(x) = \frac{3}{x^2 - 4} \), we use a table to calculate the output \( f(x) \) for each input \( x \) value in the series \(-3\) to \(3\).
Here's how you fill the table:
For the function \( f(x) = \frac{3}{x^2 - 4} \), we use a table to calculate the output \( f(x) \) for each input \( x \) value in the series \(-3\) to \(3\).
Here's how you fill the table:
- Start with the first \( x \): if \( x = -3 \), calculate \( f(-3) = \frac{3}{5} \)
- If a calculated \( x \) (like \( -2 \)) makes the denominator zero, note that \( f(x) \) is undefined there
- Continue this for each \( x \) value until \( 3 \)