Chapter 0: Problem 10
Graph. (Unless directed otherwise, assume that "Graph" means "Graph by hand.") \(8 y-2 x=4\)
Short Answer
Expert verified
Graph the equation as a line with y-intercept \((0, \frac{1}{2})\) and slope \(\frac{1}{4}\), passing through \((4, \frac{3}{2})\).
Step by step solution
01
Rewrite the Equation in Slope-Intercept Form
First, we need to rearrange the equation into the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Start by solving for \(y\):\[8y - 2x = 4\]Add \(2x\) to both sides to get\[8y = 2x + 4\]Divide the entire equation by 8:\[y = \frac{2}{8}x + \frac{4}{8}\]Simplify the fractions:\[y = \frac{1}{4}x + \frac{1}{2}\]Now, the equation is in slope-intercept form, where \(m = \frac{1}{4}\) and \(b = \frac{1}{2}\).
02
Plot the Y-Intercept
To begin graphing, plot the y-intercept of the line, which is the point \(b\) on the y-axis. Here, the y-intercept is \(\frac{1}{2}\). Mark the point \((0, \frac{1}{2})\) on the graph.
03
Use the Slope to Find Another Point
The slope \(m\) is \(\frac{1}{4}\), which indicates that for every 4 units you move right along the x-axis, you move 1 unit up the y-axis. Starting from the y-intercept \((0, \frac{1}{2})\), move 4 units to the right (x: 0 to 4) and 1 unit up (y: \(\frac{1}{2}\) to \(\frac{3}{2}\)). Thus, another point on the line is \((4, \frac{3}{2})\).
04
Draw the Line
With the points \((0, \frac{1}{2})\) and \((4, \frac{3}{2})\) marked on the graph, draw a straight line through these points. This is the graph of the equation \(8y - 2x = 4\). Extend the line across the graph to cover the entire plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-intercept form
When we talk about graphing linear equations, one of the most common and convenient forms to use is the slope-intercept form. The slope-intercept form of a linear equation is represented as:\[y = mx + b\]Here:
- \(m\) is the slope of the line, which tells us how steep the line is.
- \(b\) is the y-intercept, which is the point where the line crosses the y-axis.
Slope calculation
Understanding the slope of a line is crucial to graphing linear equations. The slope, represented by \(m\) in the slope-intercept form, indicates the direction and steepness of the line. It can be calculated using the formula:\[m = \frac{\text{rise}}{\text{run}}\]Where:
- "Rise" is the change in the y-coordinate.
- "Run" is the change in the x-coordinate.
Y-intercept
The y-intercept is where the line intersects the y-axis on a coordinate plane. This is an important point because it tells us where the line starts when plotting it on a graph. Identifying this intercept is simple once you have the equation in slope-intercept form \(y = mx + b\). The \(b\) part of the equation is the y-intercept.
For the equation we are working with, \(y = \frac{1}{4}x + \frac{1}{2}\), the y-intercept \(b\) is \(\frac{1}{2}\). On the graph, this point is represented as \((0, \frac{1}{2})\), meaning it is located directly on the y-axis.
Having the y-intercept allows us to quickly locate a starting point for sketching the line. It's particularly straightforward since it involves only the y-values without needing to worry about any changes in the x-values at this specific section of the graph. The y-intercept, along with the slope, provides a full picture of how the line looks in its entirety on the graph.
For the equation we are working with, \(y = \frac{1}{4}x + \frac{1}{2}\), the y-intercept \(b\) is \(\frac{1}{2}\). On the graph, this point is represented as \((0, \frac{1}{2})\), meaning it is located directly on the y-axis.
Having the y-intercept allows us to quickly locate a starting point for sketching the line. It's particularly straightforward since it involves only the y-values without needing to worry about any changes in the x-values at this specific section of the graph. The y-intercept, along with the slope, provides a full picture of how the line looks in its entirety on the graph.