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Find the four second-order partial derivatives. $$f(x, y)=x^{5} y^{4}+x^{3} y^{2}$$

Short Answer

Expert verified
The second-order partial derivatives are: \( f_{xx} = 20x^{3} y^{4} + 6x y^{2} \), \( f_{yy} = 12x^{5} y^{2} + 2x^{3} \), \( f_{xy} = f_{yx} = 20x^{4} y^{3} + 6x^{2} y \).

Step by step solution

01

- Find the first-order partial derivatives

First, find the partial derivative of the function with respect to each variable. Start with the partial derivative with respect to x: \( f_{x}(x, y) = \frac{\text{d}}{\text{d}x}(x^{5} y^{4} + x^{3} y^{2}) = 5x^{4} y^{4} + 3x^{2} y^{2} \) Now, find the partial derivative with respect to y: \( f_{y}(x, y) = \frac{\text{d}}{\text{d}y}(x^{5} y^{4} + x^{3} y^{2}) = 4x^{5} y^{3} + 2x^{3} y \)
02

- Find the second-order partial derivatives with respect to x

Next, differentiate \( f_{x} \) with respect to x to find \( f_{xx} \): \( f_{xx}(x, y) = \frac{\text{d}}{\text{d}x}(5x^{4} y^{4} + 3x^{2} y^{2}) = 20x^{3} y^{4} + 6x y^{2} \)
03

- Find the second-order partial derivatives with respect to y

Differentiate \( f_{y} \) with respect to y to find \( f_{yy} \): \( f_{yy}(x, y) = \frac{\text{d}}{\text{d}y}(4x^{5} y^{3} + 2x^{3} y) = 12x^{5} y^{2} + 2x^{3} \)
04

- Find the mixed second-order partial derivatives

Differentiate \( f_{x} \) with respect to y to find \( f_{xy} \): \( f_{xy}(x, y) = \frac{\text{d}}{\text{d}y}(5x^{4} y^{4} + 3x^{2} y^{2}) = 20x^{4} y^{3} + 6x^{2} y \) Similarly, differentiate \( f_{y} \) with respect to x to find \( f_{yx} \): \( f_{yx}(x, y) = \frac{\text{d}}{\text{d}x}(4x^{5} y^{3} + 2x^{3} y) = 20x^{4} y^{3} + 6x^{2} y \)
05

- Confirm equality of mixed partial derivatives

To verify correctness, confirm that the mixed partial derivatives are equal: \( f_{xy} = 20x^{4} y^{3} + 6x^{2} y \) \( f_{yx} = 20x^{4} y^{3} + 6x^{2} y \) Hence, \( f_{xy} = f_{yx} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives measure how a function changes as its input variables change. When dealing with a function of multiple variables, such as \( f(x, y) \), we can consider how the function changes with respect to one variable while keeping the other constant.
For instance, the partial derivative of \( f(x, y) \) with respect to \( x \) evaluates the rate of change of \( f \) as \( x \) varies, holding \( y \) fixed. Similarly, the partial derivative with respect to \( y \) examines the rate of change of \( f \) as \( y \) changes, holding \( x \) fixed.
The notation for the partial derivative of \( f \) with respect to \( x \) is \( f_x(x,y) \) or \( \frac{\partial f}{\partial x} \), and with respect to \( y \), it is \( f_y(x, y) \) or \( \frac{\partial f}{\partial y} \). In the given function, we found:
\[ f_x(x, y) = 5x^4 y^4 + 3x^2 y^2 \] \[ f_y(x, y) = 4x^5 y^3 + 2x^3 y \] These calculations help understand how \( f \) changes in each direction independently.
Second-Order Derivatives
Second-order derivatives provide even deeper insights into the behavior of a function. They measure the rate of change of the first-order derivatives.
The second-order derivative with respect to the same variable multiple times can be denoted as \( f_{xx} \) or \( \frac{\partial^2 f}{\partial x^2} \), and \( f_{yy} \) or \( \frac{\partial^2 f}{\partial y^2} \).
For our function, the second-order partial derivative with respect to \( x \) came out as:
\[ f_{xx}(x,y) = 20x^3 y^4 + 6x y^2 \] While the second-order partial derivative with respect to \( y \) is:
\[ f_{yy}(x, y) = 12x^5 y^2 + 2x^3 \] These derivatives help us understand the concavity or convexity of the function in each direction.
Mixed Partial Derivatives
Mixed partial derivatives involve differentiating the function first with respect to one variable and then with respect to another.
We denote these as \( f_{xy} \) or \( \frac{\partial^2 f}{\partial y \partial x} \) and \( f_{yx} \) or \( \frac{\partial^2 f}{\partial x \partial y} \). For most well-behaved functions, these mixed partial derivatives are equal. This property is known as Schwarz's theorem.
In the context of our example, we computed:
\[ f_{xy}(x, y) = 20x^4 y^3 + 6x^2 y \] \[ f_{yx}(x, y) = 20x^4 y^3 + 6x^2 y \] Here, we see that \( f_{xy} = f_{yx} \), which confirms the equality of mixed partial derivatives. This verification is an important step in ensuring the correctness of our calculations.
Calculus
Calculus is the mathematical study of continuous change, encompassing both derivatives and integrals.
Derivatives, including partial derivatives, measure how functions change, providing insight into function behavior like rates of change and slopes of curves. They are crucial for understanding and solving real-world problems in physics, engineering, and economics.
The exercise involves using fundamental calculus concepts to find and interpret derivatives of a function of multiple variables, demonstrating not just the computational techniques but also the reasoning behind them. It's essential to recognize that these derivatives can describe complex phenomena such as optimizing functions, finding critical points, and understanding dynamic systems.

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