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91Ó°ÊÓ

In a large class, students' test scores had a mean of \(\mu=76\) and a standard deviation \(\sigma=7\) a) The top \(12 \%\) of students got an A. Find the minimum score needed to get an \(A\) (round to the appropriate integer). b) The top \(30 \%\) (excluding those who got an A) got a B. Find the minimum score needed to get a \(B\) (round to the appropriate integer).

Short Answer

Expert verified
The minimum score needed for an A is 84. The minimum score needed for a B is 80.

Step by step solution

01

- Understand the Problem

We need to determine the minimum scores needed to be in the top 12% (for an A) and the top 30% (for a B, excluding those who got an A). We have the mean \(\mu = 76\) and the standard deviation \(\sigma = 7\).
02

- Find the Z-Score for the Top 12%

The top 12% corresponds to the 88th percentile. Use the Z-table or a calculator to find the Z-score that corresponds to the 88th percentile, which is approximately 1.175.
03

- Calculate the Minimum Score for an A

Use the Z-score formula to find the minimum score for an A: \(X = \mu + Z \cdot \sigma = 76 + 1.175 \cdot 7 \). This gives us \(X \approx 84.225\). Round to the nearest integer to get 84.
04

- Find the Z-Score for the Top 30%

The top 30% (excluding those who got an A) corresponds to the 70th percentile. Use the Z-table or a calculator to find the Z-score that corresponds to the 70th percentile, which is approximately 0.524.
05

- Calculate the Minimum Score for a B

Use the Z-score formula to find the minimum score for a B: \(X = \mu + Z \cdot \sigma = 76 + 0.524 \cdot 7 \). This gives us \(X \approx 79.668\). Round to the nearest integer to get 80.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-score
The z-score is a crucial concept in statistics. It measures how many standard deviations a data point (or score) is from the mean. The z-score formula is: ewline ewline \[ z = \frac{(X - \mu)}{\sigma} \] ewline Where:
  • \(X\) is the individual score
  • \(\mu\) is the mean of the dataset
  • \(\sigma\) is the standard deviation
To find a z-score, subtract the mean from the individual score and then divide by the standard deviation. In our exercise, we use z-scores to determine which exam scores fall within certain percentiles. Understanding z-scores helps us see how extreme a score is and compare scores from different datasets.
percentile rank
Percentile rank informs us about the relative standing of a score within a dataset by indicating the percentage of scores below it. For instance, if a score is in the 88th percentile, 88% of the scores are lower. In our exercise, this concept allows us to find out which students are in the top 12% (those getting an A) and the next 30% (those getting a B). To determine these ranks, we use z-scores to translate between raw scores and their related percentiles.

We found out the z-scores for the 88th and 70th percentiles were approximately 1.175 and 0.524, respectively.

Percentile ranks are essential for grading curves and understanding distributions.
mean and standard deviation
The mean, also known as the average, is calculated by adding all the scores together and dividing by the total number of scores. It is a measure of central tendency that gives us the general idea of where the middle of our data lies. In our exercise, the mean score was 76.

The standard deviation measures the dispersion or spread of the scores around the mean. It tells us how much scores deviate from the average score. A small standard deviation means that scores are close to the mean, while a larger standard deviation indicates a wider spread. The standard deviation in our exercise was 7.

These two values, the mean and standard deviation, are used heavily in calculating the z-scores and understanding the overall distribution of scores.
calculating minimum scores
To calculate minimum scores needed for different grades, we start with our known z-scores (obtained from percentile ranks) and apply the z-score formula in reverse. Here's how:
  • First, identify the desired percentile.
  • Look up the corresponding z-score using a z-table or calculator.
  • Apply the formula:

    \(X = \mu + Z \sigma\)

In our exercise, to find the minimum score for an A (top 12%), we used the z-score of 1.175:

\(X ≈ 76 + 1.175 \cdot 7 = 84.225\), rounded to 84. For a B (top 30%, excluding A's), we used the z-score of 0.524:

\(X ≈ 76 + 0.524 \cdot 7 = 79.668\), rounded to 80. This method translates z-scores back into meaningful test scores.

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