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Evaluate using integration by parts or substitution. Check by differentiating. $$\int(x+1) \ln x \, d x$$

Short Answer

Expert verified
The integral is \[ \frac{x^2}{2} \ln x + x \ln x - \frac{x^2}{4} - x + C \].

Step by step solution

01

- Choose the Method

Choose whether to use integration by parts or substitution. For this integral, integration by parts will be effective because it involves a product of functions, \(x+1\) and \ln x\.
02

- Identify Parts

In integration by parts, use the formula: \[\int u \, dv = uv - \int v \, du\]. Let \u = \ln x\ and \dv = (x+1) \, dx\.
03

- Differentiate and Integrate

Find \du\ and \v\. \du = \frac{1}{x} \, dx\. Now integrate \dv\ to get \v\. \[v = \int (x+1) \, dx = \frac{x^2}{2} + x\].
04

- Apply Integration by Parts

Substitute back into the integration by parts formula: \[\int(x+1) \, \ln x \, dx = \left( \ln x \left(\frac{x^2}{2} + x \right) \right) - \int \left( \frac{x^2}{2} + x \right) \, \frac{1}{x} \, dx\].
05

- Simplify the Integral

Simplify and solve the remaining integral: \[\left( \ln x \left(\frac{x^2}{2} + x \right) \right) - \int \left( \frac{x}{2} + 1 \right) \, dx\].
06

- Integrate Remaining Terms

Integrate the remaining terms separately: \[\int \left( \frac{x}{2} + 1 \right) \, dx = \frac{x^2}{4} + x\].
07

- Combine Results

Combine all parts: \[\int (x+1) \ln x \, dx = \ln x \left(\frac{x^2}{2} + x \right) - \left( \frac{x^2}{4} + x \right) + C\].
08

- Simplify Final Expression

Simplify the expression to reach the final answer: \[\int (x+1) \ln x \, dx = \frac{x^2}{2} \ln x + x \ln x - \frac{x^2}{4} - x + C\].
09

- Differentiate to Verify

Differentiate the result with respect to \(x\) to verify correctness. If correct, the derivative should match the original integrand \( (x+1) \, \ln x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

definite integral
A definite integral calculates the area under a curve between two specific points, known as the limits of integration. It provides a numerical value representing the total accumulated value between these points.

An important aspect of the definite integral is its ability to handle signed areas. This means that areas above the x-axis contribute positively, while areas below the x-axis contribute negatively to the result.

Mathematically, a definite integral from point \(a\) to \(b\) of function \(f(x)\) is represented as:

\[ \int_{a}^{b} f(x) \, dx \]

When evaluating a definite integral, it's crucial to:
  • Find the antiderivative of the integrand.
  • Apply the Fundamental Theorem of Calculus to the antiderivative at the upper and lower limits.
  • Subtract the value at the lower limit from the value at the upper limit.
This process transforms the integral into a simple algebraic calculation, yielding a precise numerical answer.
differentiation
Differentiation is the process of finding the derivative of a function. The derivative measures the rate at which a function's value changes with respect to change in its input (independent variable). In simple terms, it gives the slope or steepness of the function at any given point.

The differentiation rules can make this process straightforward:
  • Power Rule: \[ \frac{d}{dx} x^n = nx^{n-1} \]
  • Product Rule: \[ \frac{d}{dx} [u(x)v(x)] = u'(x)v(x) + u(x)v'(x) \]
  • Quotient Rule: \[ \frac{d}{dx} \frac{u(x)}{v(x)} = \frac{u'(x)v(x) - u(x)v'(x)}{v(x)^2} \]
  • Chain Rule: \[ \frac{d}{dx} f(g(x)) = f'(g(x))g'(x) \]
Differentiation is not only a tool for finding slopes but is also essential in optimization problems, physics for motion analysis, and in many other applications.

In the context of verifying an integral, differentiation is used to check if the derivative of the result matches the original integrand. This confirms that the integration was done correctly.
natural logarithm
The natural logarithm, denoted as \(\ln(x)\), is a logarithmic function with the base \(e\) (where \(e\) ≈ 2.71828). It plays a crucial role in various fields of mathematics and science due to its unique properties related to growth and decay processes.

Some key characteristics of \(\ln(x)\) are:
  • The domain of \(\ln(x)\) is \(x > 0\).
  • It is the inverse of the exponential function: \[e^{\ln(x)} = x\]
  • The derivative is \[ \frac{d}{dx} \ln(x) = \frac{1}{x} \].
When integrating functions involving \(\ln(x)\), it is often useful to use the technique of integration by parts. This technique rearranges the integral into simpler parts that can be managed more easily.

Integration by parts is given by the formula:

\[ \int u \, dv = uv - \int v \, du \]

This method is particularly effective when we have the product of a function and \(\ln(x)\).

In the solution \[ \int (x+1) \, \ln x \, dx, \] integration by parts simplifies the integral by breaking it into more manageable pieces. Thus, understanding \(\ln(x)\) and its properties is vital for solving such integrals efficiently.

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