Chapter 4: Problem 12
Evaluate. Assume \(u>0\) when In \(u\) appears. (Be sure to check by differentiating!) $$\int e^{7 x} d x$$
Short Answer
Expert verified
The integral is \[ \frac{1}{7} e^{7x} + C. \]
Step by step solution
01
- Identify the Integral
The integral given is \( \int e^{7x} \, dx. \)
02
- Use Substitution
Let \( u = 7x. \) Then, the differential \( du = 7 \, dx, \) implying that \( dx = \frac{du}{7} \).
03
- Substitute and Simplify
Substitute \( 7x \) with \( u \) and \( dx \) with \frac{du}{7} \ in the integral to get: \[ \int e^{7x} \, dx = \int e^u \frac{du}{7} = \frac{1}{7}\int e^u \, du. \]
04
- Integrate
The integral of \( e^u \) with respect to \( u \) is \( e^u \). Thus, \(\frac{1}{7} \int e^u \, du = \frac{1}{7} e^u + C \).
05
- Substitute Back
Substitute \( u = 7x \) back to get the final result: \[ \frac{1}{7} e^u + C = \frac{1}{7} e^{7x} + C. \]
06
- Verification through Differentiation
Differentiate \(\frac{1}{7} e^{7x} + C \) to check the answer: \[ \frac{d}{dx} \left( \frac{1}{7} e^{7x} + C \right) = \frac{1}{7} \cdot 7 e^{7x} = e^{7x}.\] The differentiation confirms the solution since it matches the original integrand.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
definite and indefinite integrals
Integrals can be broadly classified into two types: definite and indefinite. An indefinite integral is an anti-derivative function, essentially representing a family of functions. It is denoted without upper or lower limits and includes an arbitrary constant (denoted by C). For example, \(\frac{1}{7} e^{7x} + C\) is an indefinite integral.
Alternatively, a definite integral computes the area under the curve of a function between two specified bounds, providing a scalar value. The notation includes upper and lower limits, like so: \[\int_{a}^{b} f(x) \ dx\].
When solving integrals, make sure to understand if you are dealing with a definite or an indefinite integral as it affects the method and the final answer.
Alternatively, a definite integral computes the area under the curve of a function between two specified bounds, providing a scalar value. The notation includes upper and lower limits, like so: \[\int_{a}^{b} f(x) \ dx\].
When solving integrals, make sure to understand if you are dealing with a definite or an indefinite integral as it affects the method and the final answer.
substitution method in integration
The substitution method in integration is a popular technique to simplify integrals. It involves substituting part of the integral with a new variable, making the integral easier to evaluate.
In our example, we have the integral \(\int e^{7x} \ dx\).
Here's how to apply the substitution method step by step:
In our example, we have the integral \(\int e^{7x} \ dx\).
Here's how to apply the substitution method step by step:
- Identify a part of the integral to substitute. Here, let \(u = 7x\).
- Differentiate the substitution to find \(du\), which gives \(du = 7 \ dx\), and solve for \(dx = \frac{du}{7}\).
- Substitute both \(u\) and \(dx\) back into the original integral: \[ \int e^{7x} \ dx = \int e^u \frac{du}{7} = \frac{1}{7}\ \int e^u \ du.\]
- Integrate \(e^u\), yielding \(\frac{1}{7} e^u + C\).
- Substitute back \(u = 7x\) to return to the original variable: \(\frac{1}{7} e^{7x} + C\).
differentiation to verify integrals
One essential step after solving an integral is to verify your solution through differentiation. This ensures your anti-derivative function correctly translates back to the original function.
Let's verify our integral \(\frac{1}{7} e^{7x} + C\).
Let's verify our integral \(\frac{1}{7} e^{7x} + C\).
- Differentiate \(\frac{1}{7} e^{7x} + C\):
\(\frac{d}{dx} \left( \frac{1}{7} e^{7x} + C\right) = \frac{1}{7} \cdot 7 e^{7x} = e^{7x}\).
The differentiation matches the original integrand \(e^{7x}\), confirming our solution.