Chapter 2: Problem 86
Graph the function $$f(x)=\frac{x^{2}-3}{2 x-4}$$ a) Find all the \(x\) -intercepts. b) Find the \(y\) -intercept. c) Find all the asymptotes.
Short Answer
Expert verified
x-intercepts: \(\sqrt{3}, -\sqrt{3}\) y-intercept: \(\frac{3}{4}\) vertical asymptote: \(x=2\) no horizontal asymptote
Step by step solution
01
Understanding the Function
The given function is in rational form: i.e., \(f(x) = \frac{x^2 - 3}{2x - 4}\). It consists of a numerator in quadratic form and a linear denominator. To solve the exercise, we will flow through intercepts and asymptotes.
02
- Find the x-intercepts
To find the \(x\)-intercepts, we need to solve the equation when \(f(x) = 0 \). This implies solving the numerator: \(x^2 - 3 = 0\) Factor the numerator as follows: \(x = \pm \sqrt{3} = \pm 1.732 \). Thus, the \(x\)-intercepts are: \(x = \sqrt{3}\) and \(x = -\sqrt{3}\).
03
- Find the y-intercept
The \(y\)-intercept is found by evaluating \(f(x)\) at \(x = 0\). So, substitute \(x = 0\) into the function: \(f(0) = \frac{0^2 - 3}{2(0) - 4} = \frac{-3}{-4} = \frac{3}{4} = 0.75\). Thus, the \(y\)-intercept is: \(y = \frac{3}{4}\).
04
- Find the vertical asymptote
A vertical asymptote occurs where the denominator is zero, this implies solving the equation: \(2x - 4 = 0\). Solve for \(x\): \(x = 2\), so, there is a vertical asymptote at: \(x = 2\).
05
- Find the horizontal asymptote
As \(x\) approaches infinity or negative infinity, observe the degrees of the numerator and denominator. The degree of the numerator is 2 and the degree of the denominator is 1. Since the degree of the numerator is higher than the degree of the denominator, there is no horizontal asymptote.
06
- Summary of Findings
To summarize, the function has x-intercepts at \(x = \sqrt{3} \ \text{and} \ x = -\sqrt{3}\), y-intercept at \(y = \frac{3}{4}\), and a vertical asymptote at \(x = 2\). There is no horizontal asymptote.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Finding x-intercepts
To find the x-intercepts of a rational function like \( f(x) = \frac{x^{2} - 3}{2x - 4} \), we need to determine where the function equals zero. This happens when the numerator is zero because a fraction is zero only if its numerator is zero (as long as the denominator isn't zero at the same time). For \( f(x) \), we set the numerator \( x^{2} - 3 \) equal to zero and solve for \( x \). This gives us the equation \( x^{2} - 3 = 0 \). Solving this, we find \( x = \pm \sqrt{3} \). These solutions indicate our x-intercepts are at \( x = \sqrt{3} \) and \( x = -\sqrt{3} \). Adding this to our graph, the function crosses the x-axis at two points: \( (\sqrt{3}, 0) \) and \( (-\sqrt{3}, 0) \).
Finding y-intercepts
To find the y-intercept of a rational function, we simply evaluate the function at \( x = 0 \). For the function \( f(x) = \frac{x^{2} - 3}{2x - 4} \), this means substituting 0 for \( x \):\( f(0) = \frac{0^{2} - 3}{2(0) - 4} = \frac{-3}{-4} = \frac{3}{4} \). The y-intercept is therefore at \( y = \frac{3}{4} \). On a graph, this is represented as the point \( (0, \frac{3}{4}) \). It’s important to always remember that the y-intercept represents where the graph crosses the y-axis, and this happens at \( x = 0 \).
Asymptotes Analysis
Asymptotes in rational functions can be vertical or horizontal, and they represent lines that the graph approaches but never touches. For \( f(x) = \frac{x^{2} - 3}{2x - 4} \), vertical asymptotes occur where the denominator is zero, because the function becomes undefined there. Setting the denominator equal to zero: \( 2x - 4 = 0 \), we solve for \( x \) and get \( x = 2 \). Therefore, there is a vertical asymptote at \( x = 2 \). This forms a vertical line in the graph that the function approaches but never crosses.
Horizontal asymptotes depend on the degrees of the numerator and the denominator. Here, the numerator \( x^{2} \) has a degree of 2, and the denominator \( 2x \) has a degree of 1. Since the numerator’s degree is greater than the denominator’s, the function does not have a horizontal asymptote. Instead, the graph will increase or decrease without bound as \( x \) approaches infinity or negative infinity.
Horizontal asymptotes depend on the degrees of the numerator and the denominator. Here, the numerator \( x^{2} \) has a degree of 2, and the denominator \( 2x \) has a degree of 1. Since the numerator’s degree is greater than the denominator’s, the function does not have a horizontal asymptote. Instead, the graph will increase or decrease without bound as \( x \) approaches infinity or negative infinity.
Rational Functions
A rational function is any function represented as the quotient of two polynomials. In this context, \( f(x) = \frac{x^{2} - 3}{2x - 4} \) is a rational function because it is the division of the polynomial \( x^{2} - 3 \) by another polynomial \( 2x - 4 \). These functions can have interesting features such as intercepts and asymptotes which provide a lot of insight into their behavior.
The most crucial aspects of graphing rational functions involve finding these key features, which include:
The most crucial aspects of graphing rational functions involve finding these key features, which include:
- x-intercepts: where the graph crosses the x-axis
- y-intercept: where the graph crosses the y-axis
- vertical asymptotes: lines of x values where the function becomes undefined
- horizontal asymptotes: lines the function approaches as \( x \) tends to infinity or negative infinity