Chapter 2: Problem 50
Differentiate implicitly to find dy/dx. $$y^{3}=\frac{x-1}{x+1}$$
Short Answer
Expert verified
The derivative \( \frac{dy}{dx} = \frac{2}{3y^2 (x+1)^2} \).
Step by step solution
01
- Differentiate both sides with respect to x
Start by differentiating both sides of the equation implicitly with respect to x. Recall that when differentiating implicitly, \(y\) is a function of \(x\). Therefore, apply the chain rule when differentiating terms involving \(y\).\[\frac{d}{dx}(y^3) = \frac{d}{dx}\left( \frac{x-1}{x+1} \right)\]
02
- Apply the chain rule to the left side
Using the chain rule on the left side, we get:\[\frac{d}{dx}(y^3) = 3y^2 \frac{dy}{dx}\]
03
- Differentiate the right side using the quotient rule
Apply the quotient rule to differentiate \( \frac{x-1}{x+1} \):\[\frac{d}{dx} \left( \frac{x-1}{x+1} \right) = \frac{(1)(x+1) - (x-1)(1)}{(x+1)^2} = \frac{x+1 - (x-1)}{(x+1)^2} = \frac{x+1 - x+1}{(x+1)^2} = \frac{2}{(x+1)^2}\]
04
- Set the differentiated expressions equal
Since we have the differentiated expressions for both sides, set them equal to each other:\[3y^2 \frac{dy}{dx} = \frac{2}{(x+1)^2}\]
05
- Solve for dy/dx
Isolate \( \frac{dy}{dx} \) by solving the equation:\[\frac{dy}{dx} = \frac{2}{3y^2 (x+1)^2}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus used to differentiate composite functions. In other words, it's a technique for finding the derivative of a function that is wrapped inside another function. This is important when dealing with implicit differentiation, as you often need to differentiate terms involving a variable that itself is a function of another variable.
For example, in the equation \(y^3 = \frac{{x-1}}{{x+1}}\), we recognize that \(y\) is a function of \(x\). Therefore, when differentiating \(y^3\) with respect to \(x\), we apply the chain rule: \[ \frac{{d}}{{dx}}(y^3) = 3y^2 \frac{{dy}}{{dx}} \]
Here’s a breakdown to understand it better:
For example, in the equation \(y^3 = \frac{{x-1}}{{x+1}}\), we recognize that \(y\) is a function of \(x\). Therefore, when differentiating \(y^3\) with respect to \(x\), we apply the chain rule: \[ \frac{{d}}{{dx}}(y^3) = 3y^2 \frac{{dy}}{{dx}} \]
Here’s a breakdown to understand it better:
- Differentiate the outer function: The outer function is \(y^3\), so the derivative is \( 3y^2 \).
- Multiply by the derivative of the inner function: Since \(y\) is a function of \(x\), its derivative is \( \frac{{dy}}{{dx}} \).
Quotient Rule
The quotient rule is another crucial differentiation technique used when dealing with the ratio of two functions. Whenever you have a function divided by another, you will use the quotient rule to find its derivative.
For the function given by \( \frac{{x-1}}{{x+1}} \), we apply the quotient rule to differentiate it. The quotient rule states: \[\frac{{d}}{{dx}}\left( \frac{{u}}{{v}} \right) = \frac{{u'v - uv'}}{{v^2}} \]
Here, \(u = x-1\) and \(v = x+1\). Let’s apply the rule step by step:
For the function given by \( \frac{{x-1}}{{x+1}} \), we apply the quotient rule to differentiate it. The quotient rule states: \[\frac{{d}}{{dx}}\left( \frac{{u}}{{v}} \right) = \frac{{u'v - uv'}}{{v^2}} \]
Here, \(u = x-1\) and \(v = x+1\). Let’s apply the rule step by step:
- Calculate the derivative of the numerator: u' = 1
- Calculate the derivative of the denominator: v' = 1
- Apply the quotient rule formula: \[\frac{{(1)(x+1) - (x-1)(1)}}{{(x+1)^2}} = \frac{{x + 1 - (x-1)}}{{(x+1)^2}} = \frac{{2}}{{(x+1)^2}} \]
Derivative
Finally, let's delve into derivatives. A derivative represents the rate of change of a function concerning one of its variables. In simpler terms, it's a measure of how a function's output value changes as the input value changes.
To differentiate implicitly and find \(\frac{{dy}}{{dx}}\), follow these steps:
In the given problem, after differentiating both sides and applying the necessary rules, we found the derivative: \[ 3y^2 \frac{dy}{dx} = \frac{2}{(x+1)^2} \]
By isolating \(\frac{dy}{dx}\), we get: \[ \frac{dy}{dx} = \frac{2}{3y^2 (x+1)^2} \]
Derivatives are integral for understanding how functions change, and using rules like the chain and quotient rules simplifies the differentiation process.
To differentiate implicitly and find \(\frac{{dy}}{{dx}}\), follow these steps:
- Differentiate both sides of the given equation with respect to \(x\).
- Use the chain rule for any terms involving \(y\) since \(y\) is a function of \(x\).
- Apply the quotient rule for differentiating a fraction like \(\frac{x-1}{x+1}\).
- Set the differentiated expressions equal.
- Solve for \(\frac{dy}{dx}\).
In the given problem, after differentiating both sides and applying the necessary rules, we found the derivative: \[ 3y^2 \frac{dy}{dx} = \frac{2}{(x+1)^2} \]
By isolating \(\frac{dy}{dx}\), we get: \[ \frac{dy}{dx} = \frac{2}{3y^2 (x+1)^2} \]
Derivatives are integral for understanding how functions change, and using rules like the chain and quotient rules simplifies the differentiation process.