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Assume the function \(f\) is differentiable over the interval \((-\infty, \infty)\) : that is, it is smooth and continuous for all real numbers \(x\) and has no corners or vertical tangents. Classify each of the following statements as cither true or false. If you choose false, explain why. If \(f\) has exactly two critical values at \(x=a\) and \(x=b\) where \(a

Short Answer

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False. Critical points do not necessarily imply a point of inflection between them.

Step by step solution

01

Understand Critical Points

Critical points of a function are where its derivative is zero or undefined. Since the function is smooth, we consider the critical points where the derivative is zero. Here, the given critical points are at x = a and x = b.
02

Understand Points of Inflection

Points of inflection occur where the second derivative changes sign, indicating a change in the concavity of the function. For a point of inflection to exist at x = c, the second derivative must be zero or undefined at that point, and it must change sign around x = c.
03

Analyze the Statement

The statement claims that if a function has exactly two critical points at x = a and x = b, then there must be exactly one point of inflection at x = c such that a < c < b. To assess its truth, recall that critical points are not necessarily related to points of inflection in a fixed way. A function can have critical points without having points of inflection, and vice versa.
04

Provide a Counterexample

Consider the function f(x) = x^4. The critical points are at x = 0, but there are no points of inflection because the second derivative f''(x) = 12x^2 is always non-negative and never changes sign. This indicates that it's possible to have critical points without points of inflection between them.
05

Conclude the Argument

Since a function can exist where there are critical points without an inflection point between them, the statement 'there must exist exactly one point of inflection at x=c such that a

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

critical points
A critical point of a function occurs where its first derivative is zero or undefined. Imagine you're trying to find the top or bottom of a hill on a graph. The top (peak) or bottom (valley) are examples of critical points. At these points, the slope of the tangent to the curve is horizontal. This means the derivative is zero.

For example, if you have the function \(f(x) = x^3\), its derivative is \(f'(x) = 3x^2\). Setting this derivative to zero, you find that the critical point is at \(x = 0\). Here, the function neither increases nor decreases at this specific point.

Remember: Not all critical points are maxima or minima. They can also be saddle points where the function changes direction.
second derivative
The second derivative, denoted as \(f''(x)\), tells whether a function is concave up or concave down at a particular point. To find it, you simply take the derivative of the first derivative.

Here's why it's important:
  • If \(f''(x) > 0\), the function is concave up (shaped like a cup).
  • If \(f''(x) < 0\), the function is concave down (shaped like a cap).
A function can change from concave up to concave down or vice versa. These points are known as points of inflection.

Let's take an example. For the function \(f(x) = x^4\), the first derivative is \(f'(x) = 4x^3\) and the second derivative is \(f''(x) = 12x^2\). Notice that \(f''(x)\) is never negative. This means the function is always concave up and has no points of inflection.
concavity
Concavity describes how the graph of a function bends or curves. Think of concavity like a bowl.
  • Concave up: If you imagine pouring water into the curve and it holds water, it's concave up.
  • Concave down: If the curve can't hold water and instead spills it, it's concave down.
Concavity gives important insights into the behavior of a function between critical points.

A real-world example is the trajectory of a ball thrown in the air. Initially, it follows a concave down path (rising and then reaching a peak) and then switches to a concave up path (falling downwards). Identifying concavity helps predict changes in direction and acceleration of the function's graph.

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Most popular questions from this chapter

The total-cost and total-revenue functions for producing \(x\) items are $$ C(x)=5000+600 x \text { and } R(x)=-\frac{1}{2} x^{2}+1000 x $$ where \(0 \leq x \leq 600 .\) a) Find the total-profit function \(P(x)\) b) Find the number of items, \(x,\) for which the total profit is a maximum.

Marginal average cost. In Section \(1.6,\) we defined the average cost of producing \(x\) units of a product in terms of the total cost \(C(x)\) by \(A(x)=C(x) / x .\) Find a general expression for marginal average cost, \(A^{\prime}(x)\)

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