Chapter 1: Problem 57
Is the function given by \(f(x)=\left\\{\begin{array}{ll}\frac{1}{3} x+4 & \text { for } x<3, \\ 2 x-1 & \text { for } x \geq 3.\end{array}\right.\) continuous at \(x=3 ?\) Why or why not?
Short Answer
Expert verified
The function is continuous at \( x = 3 \) because the left-hand limit, right-hand limit, and the function's value at 3 are all equal to 5.
Step by step solution
01
- Understand the given function
The function provided is a piecewise function defined by two expressions: For \( x < 3 \), \( f(x) = \frac{1}{3}x + 4 \). For \( x \geq 3 \), \( f(x) = 2x - 1 \).
02
- Find the limit as x approaches 3 from the left
Calculate the left-hand limit: \[ \lim_{x \to 3^-} f(x) = \lim_{x \to 3^-} \left( \frac{1}{3}x + 4 \right) = \frac{1}{3}(3) + 4 = 1 + 4 = 5 \]
03
- Find the limit as x approaches 3 from the right
Calculate the right-hand limit: \[ \lim_{x \to 3^+} f(x) = \lim_{x \to 3^+} \left( 2x - 1 \right) = 2(3) - 1 = 6 - 1 = 5 \]
04
- Check the function's value at x = 3
Evaluate the function at \( x = 3 \): \[ f(3) = 2(3) - 1 = 6 - 1 = 5 \]
05
- Compare limits and function value
The function is continuous at \( x = 3 \) if the left-hand limit, right-hand limit, and the value of the function at \( x = 3 \) are all equal. Here, \[ \lim_{x \to 3^-} f(x) = \lim_{x \to 3^+} f(x) = f(3) = 5 \].
06
Conclusion
Since the left-hand limit, the right-hand limit, and the value of the function at \( x = 3 \) are all equal to 5, the function \( f(x) \) is continuous at \( x = 3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
Limits help us understand the behavior of functions as they approach a certain point. Imagine driving towards a stop sign. The limit describes what happens to your speed as you get closer to the stop sign.
In mathematical terms, the limit of a function \(f(x)\) as \(x\) approaches some value \(c\) is written as \(\lim_{{x \to c}} f(x)\). This tells us the value that \(f(x)\) gets closer to as \(x\) gets closer to \(c\).
There are two types of limits—left-hand limit and right-hand limit. When \(x\) approaches \(c\) from the left (or smaller values), it's called the left-hand limit, written as \(\lim_{{x \to c^-}} f(x)\). When \(x\) approaches \(c\) from the right (or larger values), it's called the right-hand limit, written as \(\lim_{{x \to c^+}} f(x)\).
In mathematical terms, the limit of a function \(f(x)\) as \(x\) approaches some value \(c\) is written as \(\lim_{{x \to c}} f(x)\). This tells us the value that \(f(x)\) gets closer to as \(x\) gets closer to \(c\).
There are two types of limits—left-hand limit and right-hand limit. When \(x\) approaches \(c\) from the left (or smaller values), it's called the left-hand limit, written as \(\lim_{{x \to c^-}} f(x)\). When \(x\) approaches \(c\) from the right (or larger values), it's called the right-hand limit, written as \(\lim_{{x \to c^+}} f(x)\).
Piecewise functions
Piecewise functions are those defined by different expressions in different intervals of their domain. Think of a road that changes speed limits in different sections. Likewise, a piecewise function uses different equations in different parts of its domain.
For example, the piecewise function given in the exercise is defined as follows:
For example, the piecewise function given in the exercise is defined as follows:
- For \(x < 3\): \(f(x) = \frac{1}{3}x + 4\)
- For \(x \geq 3\): \(f(x) = 2x - 1\)
Continuous functions
A function is continuous if you can draw its graph without lifting your pencil. More formally, a function \(f(x)\) is continuous at a point \(x = c\) if the following three conditions are satisfied:
- The limit of \(f(x)\) as \(x\) approaches \(c\) from the left exists and is equal to \(L\): \(\lim_{{x \to c^-}} f(x) = L\)
- The limit of \(f(x)\) as \(x\) approaches \(c\) from the right exists and is equal to \(L\): \(\lim_{{x \to c^+}} f(x) = L\)
- The value of the function at \(x = c\) exists and is equal to \(L\): \(f(c) = L\)
Evaluating limits
Evaluating limits involves calculating the value that \(f(x)\) approaches as \(x\) gets closer to a certain point. For piecewise functions, it's important to check the limit from both sides of the point.
In the exercise:
In the exercise:
- We first calculated the left-hand limit as \(x\) approached 3 using the expression \(\frac{1}{3}x + 4\). We found \(\lim_{{x \to 3^-}} f(x) = 5\).
- Next, we calculated the right-hand limit from the expression \(2x - 1\), giving \(\lim_{{x \to 3^+}} f(x) = 5\).
- Then, we checked the value of \(f(x)\) at \(x = 3\), which was also 5.