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Differentiate the function given. $$ f(x)=3 e^{-x} $$

Short Answer

Expert verified
The derivative of the function is \(-3e^{-x}\).

Step by step solution

01

Identify the outer and inner functions

In the function \(f(x) = 3e^{-x}\), the outer function is the exponential function and the inner function is \(-x\). In the chain rule, the derivative is found by first differentiating the outer function while leaving the inner function alone, then multiplying by the derivative of the inner function.
02

Apply the Chain Rule

The derivative of an exponential function of the form \(e^u\) where \(u\) is any function of \(x\), is \(e^u\cdot u'\). Thus, differentiating the outer function while leaving the inner function alone gives \(e^{-x}\). Next, differentiate the inner function \(-x\), which gives -1.
03

Combine the results

From the previous steps, we combine our results to complete the differentiation. Multiply the derivative of the outer function \(e^{-x}\) with -1 (the derivative of the inner function) and 3 (the constant factor), which gives the final result: \(-3e^{-x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
Understanding the chain rule is crucial when differentiating compositions of functions. The chain rule states that to differentiate a composite function, you need to take the derivative of the outer function with respect to the inner function, and then multiply that by the derivative of the inner function with respect to the variable.

For the function in our example, which is of the form 3 times the exponential of -x, denoted as \(f(x) = 3e^{-x}\), we see that the outer function is the exponential part, \(e^{-x}\), and the inner function is the linear part, \(-x\). The chain rule guides us to first differentiate \(e^{-x}\) as if \(-x\) were just a variable, and then multiply by the derivative of \(-x\) with respect to x, which simplifies to -1.
Exponential Function Differentiation
Differentiating exponential functions follows specific rules that set them apart from other functions. In general, the derivative of \(e^x\) is unique because it is the only function whose derivative is itself. However, when dealing with an exponential function with a power other than x, say \(e^{u(x)}\) where u(x) is a function of x, the derivative changes.

To differentiate such a function, you would use the chain rule and end up with the derivative \(e^{u(x)}\) multiplied by u'(x), the derivative of the power function with respect to x. In our exercise, \(e^{-x}\) is differentiated to \(e^{-x}(-1)\), where \(-1\) is the derivative of the inner function \(-x\).
Calculus Problem Solving
Approaching problems in calculus methodically can lead to easier and more accurate solutions. When differentiating functions, especially complex ones, it is best to break them down into their simpler components, as was done in the step-by-step solution for our function \(f(x) = 3e^{-x}\).

By identifying the components involved, such as constants, inner functions, and outer functions, you allow for a clear application of differentiation rules, such as the product rule, quotient rule, and, as in our case, the chain rule. This strategy prevents common errors and fosters a better understanding of the differentiation process.
Derivative of Exponential Functions
The derivative of an exponential function can often be found quickly and easily by applying the appropriate rules. Exponential functions, specifically those with base e, are particularly straightforward because their derivatives remain proportional to the original function.

In our exercise, we leverage the fact that the derivative of \(e^x\) is \(e^x\) itself, and when multiplied by the derivative of the power (which is a function of x), we obtain the derivative of the entire function. The result for the exercise \(-3e^{-x}\) tells us how rapidly the function \(f(x) = 3e^{-x}\) changes at any point x. Such derivatives are incredibly useful in fields such as physics, economics, and biology where exponential growth or decay patterns are common.

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Most popular questions from this chapter

Simplify as much as possible: (a) \(\frac{x^{2 y}+x^{y+2}}{x^{y}}\) (b) \(\frac{\frac{\sqrt{x}}{x^{-1 / 2} y}-1}{y-\frac{x^{2}}{y}}\) (c) \(\frac{A^{B+4}-A^{3 B}}{A^{B}\left(A^{2}-A^{B}\right)}\) (d) \(\frac{y^{3 w}-y^{w+4}}{y^{w}\left(y^{w}+y^{2}\right)}\)

In the middle of the \(1994-95\) academic year, in the middle of the week, in the middle of the day, there was a bank robbery and subsequent shootout in the middle of Harvard Square. Throughout the afternoon the news spread by word-of- mouth. Suppose that at the time of the occurrence 30 people know the story. Every 15 minutes each person who knows the news passes it along to one other person. Let \(N(t)\) be the number of people who know at time \(t\). (a) Make a table with time in one column and \(N(t)\) in the other. Identify the pattern and write \(N\) as a function of \(t\). (b) If you've written your equation for \(N(t)\) with \(t\) in minutes, convert to hours. If you've done it in hours, convert to minutes. Make a table to check your answers. (It's easy to make a mistake the first time you do this.)

Differentiate the function given. $$ f(x)=\frac{e^{2 x}}{x} $$

True or False: If the statement is always true, write "True;" if the statement is not always true, produce a counterexample. (a) \(\left(a^{2}+b^{2}\right)^{1 / 2}=a+b\) (b) \((a+b)^{-1}=\frac{1}{a+b}, \quad a, b \neq 0\) (c) \((a+b)^{-1}=\frac{1}{a}+\frac{1}{b}, \quad a, b \neq 0\) (d) \(R^{-1 / 2}=-\frac{1}{\sqrt{R}}, \quad R>0\) (e) \(x^{z}+x^{z}=2 x^{z}\) (f) \(x^{z} x^{z}=x^{\left(z^{2}\right)}\) (g) \(x^{z} x^{z}=x^{2 z}\)

For Problems 1 through 9, simplify the following expressions. $$ \frac{\sqrt{2 x^{3}}+\sqrt{12 y^{3} x^{4}}}{\sqrt{6 y^{2} x^{5}}} $$

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