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In Problems 5 through 8 , estimate \(f^{\prime}(c)\) by calculating the difference quotient \(\frac{f(c+h)-f(c)}{h}\) for successively smaller values of \(|h| .\) Use both positive and negative values of \(h .\). $$ f(x)=\sqrt{x} \text { . Approximate } f^{\prime}(9) \text { . } $$

Short Answer

Expert verified
The approximate value of the derivative of the function \(f(x) = \sqrt{x}\) at \(x = 9\), denoted as \(f'(9)\), can be estimated by considering positive and negative differences of \(h\) approaching 0. You will compute \(\frac{\sqrt{9 + h} - 3}{h}\) and \(\frac{\sqrt{9 - h} - 3}{h}\) while letting \(h\) approach 0 from both positive and negative directions respectively.

Step by step solution

01

Compute f(c+h) and f(c)

First, calculate the values of \(f(c+h)\) and \(f(c)\). Here, \(c = 9\), and \(h\) is a small number, which can be positive or negative. To calculate \(f(c+h)\), replace \(x\) in \(f(x) = \sqrt{x}\) by \(9 + h\), and calculate \(f(9 + h) = \sqrt{9 + h}\). Similarly, \(f(9) = \sqrt{9} = 3\).
02

Compute the Difference Quotient

The difference quotient is defined as \(\frac{f(c+h)-f(c)}{h}\). So, substitute the previously calculated values into the formula. For positive \(h\), the difference quotient would be \(\frac{\sqrt{9 + h} - 3}{h}\), and for negative \(h\) it would be \(\frac{\sqrt{9 - h} - 3}{h}\).
03

Approximate f'(c)

Estimate \(f'(9)\) by choosing smaller and smaller absolute values of \(h\) (both positive and negative), and calculating the difference quotient for each value. The limit as \(h\) approaches 0 of these difference quotients would give the approximation of \(f'(9)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Approximation
The concept of derivative approximation involves calculating the derivative of a function at a certain point by using numerical methods instead of exact calculations. When dealing with functions like square roots, finding the derivative directly might seem challenging at first. Instead, one useful approach is to use the **difference quotient**. This quotient is given by the formula:
  • \( \frac{f(c+h) - f(c)}{h} \)
Here, \( f(c+h) \) is the function value close to \( c \), and \( f(c) \) is the function value at \( c \). By computing this difference quotient for progressively smaller values of \(|h|\), and using values both above and below \( c \), we can get a good approximation for the derivative. As \( h \) becomes minuscule, this quotient approaches the actual derivative, \( f'(c) \). This is crucial for functions where calculating the derivative is not straightforward analytically.
Limits
The concept of limits is fundamental when you're dealing with derivatives and especially when finding them through approximation. In the case of the difference quotient approach, as \( h \) gets closer and closer to zero, the quotient
  • \( \frac{f(c+h) - f(c)}{h} \)
begins to converge to the function's true derivative at that point. Limits allow us to make sense of these values trending towards something meaningful, even though \( h \) is not zero. This is because division by zero isn't defined. But with limits, we don't need \( h \) to be zero, just very close! This makes limits a powerful tool in calculus. In exercises where you approximate derivatives, thinking of the difference quotient's behavior as \( h \) shrinks helps you understand how we arrive at the derivative. This gives insight into how the tangent line's slope at \( c \) is "born" from these values farming "infinitely" near \( c \).
Square Roots
In this problem, the function in question includes a square root, \( f(x) = \sqrt{x} \). Functions with square roots can appear daunting, particularly when differentiating. They require special attention, considering their domain limits, since you can't take square roots of negative numbers in real-number analysis. When calculating a derivative or a difference quotient, it's important to ensure that the values set for \( c+h \) remain non-negative.What's particularly useful about square root functions in derivatives is understanding their behavior: they grow steadily slower as \( x \) increases. This slowing slope can often be easily sensed if you imagine the curve flattening out. By focusing on approximating derivatives at specific points, like \( c = 9 \), we can get a sense of this slowdown via numerical differences from slightly adjusted points surrounding \( c \). Understanding these subtleties is part of why calculus can feel like both an art and a science, revealing the subtleties of how functions change and develop.

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Most popular questions from this chapter

For Problems 21 through 24 use the limit definition of \(f^{\prime}(a)\) to find the derivative of \(f\) at the point indicated. $$ f(x)=\frac{3}{2-x} \text { at } x=1 $$

We showed that the derivative of \(\sqrt{x}\) (or \(x^{\frac{1}{2}}\) ) is \(\frac{1}{2} \frac{1}{\sqrt{x}}\) (or \(\left.\frac{1}{2} x^{-\frac{1}{2}}\right) .\) Here we focus on \(f(x)=\sqrt{x-1}\) (a) How is the graph of \(\sqrt{x-1}\) related to that of \(\sqrt{x}\) ? (b) How is the graph of the derivative of \(\sqrt{x-1}\) related to that of the derivative of \(\sqrt{x} ?\) Illustrate with a rough sketch. (c) Given your answer to part (b) explain why \(\left.\frac{d}{d x} \sqrt{x}\right|_{x=4}=\left.\frac{d}{d x} \sqrt{x-1}\right|_{x=5}\). In other words, explain why the derivative of \(\sqrt{x}\) at \(x=4\) is equal to the derivative of \(\sqrt{x-1}\) evaluated at \(x=5\) (d) Show that \(f^{\prime}(5)=\frac{1}{4}\) using the limit de nition of derivative: $$ f^{\prime}(5)=\lim _{x \rightarrow 5} \frac{f(x)-f(5)}{x-5} $$

For Problems 7 through 13, find \(f^{\prime}(x), f^{\prime}(0), f^{\prime}(2)\), and \(f^{\prime}(-1) .\) $$ f(x)=x^{2} $$

Suppose that \(C(s)\) gives the number of calories that an average adult burns by walking at a steady speed of \(s\) miles per hour for one hour. (a) What are the units of \(\frac{d C}{d s}\) ? (b) Do you expect \(\frac{d C}{d s}\) to be positive? Why or why not? (c) Interpret the statement \(C^{\prime}(3)=25\). Hint: If you are having difficulties with this problem, consider sketching a graph. What are the labels on the axes? (That is, what are the independent and dependent variables?) Thinking about these variables, what should the graph look like? How do your assumptions about the graph relate to the questions posed above?

Use the limit de nition of derivative to nd the derivative of \(f(x)=x^{3}\).

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