/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A hyena is loping down a straigh... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A hyena is loping down a straight path away from a stream. The hyena is \(6 \mathrm{~m}\) from the stream, moving at a rate of \(2 \mathrm{~m} / \mathrm{s}\) and decelerating at a rate of \(0.1 \mathrm{~m} / \mathrm{s}^{2}\). Use a second degree Taylor polynomial to estimate its distance from the stream 1 second later.

Short Answer

Expert verified
The hyena's distance from the stream after 1 second can be found by adding the initial distance (6m) to the change in distance calculated using the second degree Taylor polynomial: \(6 + (2 - 0.05) = 7.95 m\). Therefore, the hyena will be roughly 7.95 meters away from the stream.

Step by step solution

01

Identify Initial Values

Here, the initial velocity (v0) of the hyena is \(2 m/s\), the initial position (s0) is \(6 m\) from the stream and constant acceleration (a) is \(-0.1 m/s^2\) (decelerating means acceleration is negative). The time interval (t) for which we're estimating the distance is 1 second.
02

Apply Second Degree Taylor Polynomial to determine Position Change

Based on the formula of second degree Taylor polynomial \(s(t) = s(0) + v(0)*t + 0.5*a*t^{2}\), the position change in one second can be calculated as: \(s(1) = s0 + v0*1+ 0.5*(-0.1)*1^{2} = s0 + v0 - 0.05\)
03

Calculate Distance from the Stream

The distance from the stream at t=1 second will be the initial distance plus the change that happened in one second.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Deceleration
Deceleration refers to the rate at which an object slows down over time. When an object is decelerating, it means that its velocity is decreasing.In the case of the hyena, deceleration is experienced as it moves away from the stream. The given rate of deceleration for the hyena is \(0.1 \mathrm{~m/s^2}\). This means that every second, the hyena's velocity reduces by \(0.1 \mathrm{~m/s}\). Understanding deceleration is important because it affects predictions of movement using mathematical models, such as the Taylor polynomial. In physics, deceleration is technically just a negative acceleration, and this is why it is represented with a negative sign in equations. Calculating the impact of deceleration accurately helps to determine how far the hyena will travel within a certain time frame.
Initial Velocity
Initial velocity is the speed at which an object is moving when first observed or measured. For the hyena running from the stream, the initial velocity \(v_0\) is \(2 \mathrm{~m/s}\).This initial velocity is an essential component of the Taylor polynomial used to estimate future positions of the hyena on the path. Knowing the initial velocity allows us to predict how far the hyena would travel without any forces acting on it, making it a crucial starting point for further calculations.For the hyena's situation, this speed combined with the deceleration will affect how quickly it will reduce its distance from the stream. The formula for calculating the position includes this initial velocity and how it changes over time.
Time Interval
Time interval refers to the duration over which changes in velocity and position are measured or estimated. In this example, the time frame is specified as \(1\) second.This is the period over which the deceleration affects the hyena's velocity and subsequently its position.Understanding the time interval is crucial as it sets the bounds for calculations that involve changes in speed and position. Knowing this time period helps to plug values into the formulas accurately, providing reliable estimates.In motion problems, the time interval guides the evaluation of future positions by dividing entire motion into manageable segments for analysis.
Second Degree Polynomial
The second degree Taylor polynomial is a mathematical tool used to approximate the position of moving objects when they experience constant acceleration or deceleration. The polynomial is written as: \[ s(t) = s(0) + v(0) \cdot t + 0.5 \cdot a \cdot t^2 \]This formula calculates the hyena's position after a certain period, considering initial velocity, initial location, and constant deceleration. For this problem, analyzing motion with a second degree polynomial enables us to represent changes in both velocity and position without direct experimentation.Taylor polynomials offer a simplified, yet precise way to model changes for practical applications, predicting movement in real-life scenarios based on given initial conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the series converges or diverges. In this set of problems knowledge of the Limit Comparison Test is assumed. \(\sum_{n=2}^{\infty} \frac{n+1}{\ln n}\)

Determine whether the series converges or diverges. It is possible to solve Problems 4 through 19 without the Limit Comparison, Ratio, and Root Tests. \(\sum_{k=2}^{\infty} 2 k^{-10 / 9}\)

In Problems 25 through 32, determine whether the series converges or diverges. In this set of problems knowledge of the Limit Comparison Test is assumed. \(\sum_{k=1}^{\infty} \frac{3}{2^{k}-1}\)

Determine whether the series converges or diverges. It is possible to solve Problems 4 through 19 without the Limit Comparison, Ratio, and Root Tests. \(\sum_{k=1}^{\infty} \frac{k+2}{3 k^{2}}\)

The hyperbolic functions, hyperbolic cosine, abbreviated cosh, and hyperbolic sine, abbreviated sinh, are defined as follows. $$\cosh x=\frac{e^{x}+e^{-x}}{2} \quad \sinh x=\frac{e^{x}-e^{-x}}{2}$$ (a) Graph \(\cosh x\) and \(\sinh x\), each on its own set of axes. Do this without using a computer or graphing calculator, except possibly to check your work. (b) Find the Maclaurin series for \(\cosh x\). (c) Find the MacLaurin series for \(\sinh x\). Remark: From the graphs of \(\cosh x\) and \(\sinh x\) one might be surprised by the choice of names for these functions. After finding their Maclaurin series the choice should seem more natural. (d) Do some research and find out how these functions, known as hyperbolic functions, are used. The arch in St. Louis, the shape of many pottery kilns, and the shape of a hanging cable are all connected to hyperbolic trigonometric functions.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.