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For Problems , determine whether the series converges or diverges. Explain your reasoning. $$ \frac{-1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}-\cdots-\frac{1}{n}-\cdots $$

Short Answer

Expert verified
The series \( \frac{-1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}-\cdots-\frac{1}{n}-\cdots \) converges according to the Alternating Series Test.

Step by step solution

01

Identify the series

Identify the series \( \frac{-1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}-\cdots-\frac{1}{n}-\cdots \) as an alternating series since the signs of the terms alternate between positive and negative.
02

Determine the nth term

Determine the nth term of the series, which is \( -\frac{1}{n} \).
03

Apply the Alternating Series Test

Apply the Alternating Series Test for convergence. The test states that an alternating series converges if the sequences of absolute terms is monotonically decreasing and the limit as n goes to infinity of the absolute nth term is zero. -The sequence here is \( \frac{1}{n} \), and is monotonically decreasing since, as n increases, the terms get smaller. -The limit of the nth term as n goes to infinity is 0. \( \lim_{n \to \infty} \frac{1}{n} = 0 \). So the given series converges by the Alternating Series Test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alternating Series Test
The Alternating Series Test is a handy tool when dealing with series that change signs between terms. In simple words, an alternating series is a series whose terms alternate in sign. For instance, when you see a series like \( \frac{-1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}-\cdots \), you can spot that it alternates between negative and positive terms.
To use the Alternating Series Test for this kind of series, you must check two conditions:
  • The sequence of absolute terms \( b_n = \frac{1}{n} \) must be monotonically decreasing. This means as \( n \) grows larger, each term \( b_n \) should get smaller.
  • The limit of \( b_n \) from this sequence as \( n \to \infty \) should be zero. In our case, \( \lim_{n \to \infty} \frac{1}{n} = 0 \).
If both conditions are met, the series converges. This works because, even though the terms are alternating in sign, they are getting smaller in absolute value and these smaller differences "settle down" to some finite sum over infinite terms.
The series in our problem meets these conditions and hence is convergent because of the Alternating Series Test.
Convergent Series
A convergent series is a series where the sum of its terms approaches a specific finite number. With each added term, the sum gets closer and closer to this number. It's like continually trying to hit a target, getting closer each time but never quite going beyond that target value.
To understand convergence better, consider our original series: \( \frac{-1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}-\cdots \). With the Alternating Series Test, we've confirmed it converges because each term is getting smaller and is approaching zero.
Convergent series are essential in calculus and mathematics because they ensure that infinite processes lead to finite results. This also tells us that even infinite sequences can sometimes "sum up" to a real number under certain conditions, such as alternating signs and decreasing term sizes as in this example.
Divergent Series
In contrast, a divergent series is one where the sum of its terms does not approach any specific number. As terms are added, the overall sum could increase indefinitely, decrease indefinitely, or simply alternate without settling to any limit. This lack of a finite sum means we cannot pinpoint a number it approaches.
For an illustrative divergence example, consider the harmonic series: \( 1 + \frac{1}{2} + \frac{1}{3} + \cdots \).Even though its terms also get smaller, they don't alternate, and the sum of this series diverges, which means it increases without bound.
Divergent series are quite different from convergent series. They remind us that not all infinite sums behave nicely. A series divergence implies that, despite possibly having diminishing terms, the sum still "escapes" reaching a finite result.
This understanding helps in clearly distinguishing between series that converge to a finite number from those that don't, playing a crucial role in mathematical analysis and applications.

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Most popular questions from this chapter

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