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Express each of the sums in closed form. Wherever possible, give a numerical approximation of the sum, rounded off to 3 decimal places. $$ 1+\frac{9}{10}+\left(\frac{9}{10}\right)^{2}+\left(\frac{9}{10}\right)^{3}+\cdots+\left(\frac{9}{10}\right)^{n} $$

Short Answer

Expert verified
The closed form of the sum is \(S = 10 - 10 \cdot \left(\frac{9}{10}\right)^{n+1}\). The numerical approximation can be obtained by substituting a specific value of \(n\) into the function and rounding off the result to 3 decimal places.

Step by step solution

01

Identify the components

The provided series is geometric. The first term (a) is 1, and the common ratio (r) is \(\frac{9}{10}\). The n-th term is \(\left(\frac{9}{10}\right)^{n}\) and there are (n+1) terms.
02

Apply the formula

The formula for the sum (S) of a finite geometric series is \(S = a \cdot \frac{1 - r^n}{1 - r}\). Substituting the identified components into this formula, the sum in closed form becomes \(S = \frac{1 - \left(\frac{9}{10}\right)^{n+1}}{1 - \frac{9}{10}}\).
03

Simplify the expression

Simplify the denominator of the expression to get \(S = \frac{1 - \left(\frac{9}{10}\right)^{n+1}}{\frac{1}{10}}\), which simplifies further to \(S = 10 - 10 \cdot \left(\frac{9}{10}\right)^{n+1}\).
04

Numerical approximation

Exact numerical approximation cannot be given as it's dependent on the value of \(n\). However, for a entered specific value of \(n\), one can round off to 3 decimal places to get the numerical approximation. To do this, substitute the value of \(n\) into the function and evaluate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sum of Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. For the series you're working with, the first term, denoted as **a**, is 1, and the common ratio, **r**, is \(\frac{9}{10}\). This pattern continues up to \(\left(\frac{9}{10}\right)^{n}\).

The formula for the sum of a geometric series is crucial. It's given by:

\[ S = a \cdot \frac{1 - r^{n+1}}{1 - r} \]

For this specific series, substituting the values, the formula simplifies to:

\[ S = \frac{1 - \left(\frac{9}{10}\right)^{n+1}}{\frac{1}{10}} \]

This formula efficiently calculates the total sum by accounting for all terms in the series.
Closed Form Expression
A closed form expression provides a way to write a complex mathematical expression simply and compactly. For a geometric series, this means expressing the entire sum without listing out each term individually. We achieve this with the formula:

\[ S = 10 - 10 \cdot \left(\frac{9}{10}\right)^{n+1} \]

This representation encompasses all elements of the series and allows for easy computation. Understanding closed forms helps in quickly evaluating sums without manual repetition of terms.

It's a more elegant and less labor-intensive approach that leverages mathematical properties to simplify processes.
Numerical Approximation
Sometimes, we need an actual numerical value rather than just a formula. This is where numerical approximation comes into play. With the closed form already at hand, you simply plug in the value of **n** into:

\[ S = 10 - 10 \cdot \left(\frac{9}{10}\right)^{n+1} \]

Then, the computation gives you a specific numerical result based on your chosen **n**. After calculation, you can round this value to three decimal places for precision.

For instance, by setting **n=5** in the equation, you'll find an approximate sum of 9.411. Experimenting with different values of **n** will show how the sum converges closer to 10 as **n** increases.

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