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Find a formula for \(\frac{d y}{d x}\) if \(y=f(g(h(x)))\), where \(f, g\), and \(h\) are differentiable everywhere.

Short Answer

Expert verified
The derivative of \(y = f(g(h(x)))\) is \(\frac{d y}{d x}=f'(g(h(x))) \cdot g'(h(x) \cdot h'(x).\).

Step by step solution

01

Apply Chain Rule to Outer Functions

First apply the chain rule to the outer functions, \(f\) and \(g\). This will result in: \(\frac{d y}{d x}=f'(g(h(x))) \cdot g'(h(x))\). Here, \(f'(g(h(x)))\) represents the derivative of \(f\) with respect to \(g(h(x))\) and \(g'(h(x))\) represents the derivative of \(g\) with respect to \(h(x)\).
02

Apply Chain Rule to Inner Function

Apply the chain rule once more to the innermost function \(h(x)\). This requires multiplying the previous result by the derivative of \(h(x)\). The final derivative is: \(\frac{d y}{d x}=f'(g(h(x))) \cdot g'(h(x) \cdot h'(x).\)
03

Conclusion

This concludes the calculation. The resulting formula expresses the derivative of \(y\) with respect to \(x\) in terms of the derivatives of the functions \(f, g, h\) at the respective points \(g(h(x)), h(x), x\). This is consistent with the expected result from applying the chain rule twice to a composition of three functions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative of a Function
In calculus, the derivative of a function represents the rate at which the function value changes as its input changes. If we have a function 'y' that depends on 'x', denoted as 'y = f(x)', its derivative is represented as \( \frac{dy}{dx} \) or \( f'(x) \). It tells us how 'y' moves when 'x' is nudged slightly. The derivative can also be understood as the slope of the tangent line to the function at any given point.

For example, if 's(t)' is a function representing the position of an object over time 't', then \( \frac{ds}{dt} \) describes its velocity—how position changes with time. The concept of derivatives is fundamental in physics, engineering, and many other fields that model dynamic systems.
Differentiable Functions
A function is said to be differentiable at a point if its derivative exists at that point. This means that the function has a defined slope at that point, and it behaves nicely - without sharp corners or discontinuities. For a function to be differentiable everywhere, it must have a derivative at every point in its domain.

When working with differentiable functions like 'f', 'g', and 'h' in the context of chain rule, we can smoothly determine the derivative of a composition of these functions. Being differentiable does not only mean having a derivative; it also ensures that the function is continuous, which is vital when we're chaining functions together.
Composite Functions
A composite function is a function created by combining two or more functions. If we have functions 'f', 'g', and 'h', a composite function might be 'y = f(g(h(x)))', which is the case in our exercise. Here, 'h' is first applied to 'x', then 'g' is applied to the result of 'h(x)', and finally, 'f' is applied to 'g(h(x))'.

It's like nesting dolls, where each function contains another. Understanding composite functions is essential for mastering the chain rule, as it dictates that we take derivatives in the outer-to-inner function order. This way, each function is differentiated in turn, allowing us to handle more complex scenarios where functions are blended together.
Calculus Techniques
There are several calculus techniques critical for solving different types of problems, and one of the most powerful among these is the chain rule. It's a method used to find the derivative of composite functions. The chain rule can be applied multiple times when dealing with several layers of nested functions, as seen in our exercise.

Other important techniques include the product rule, for multiplying functions; quotient rule, for dividing them; and integration by parts, for integrating products of functions. Mastering each technique is like acquiring a new tool that helps you tackle diverse problems in calculus, ensuring you're well-equipped to deal with the varying challenges that mathematical functions present.

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Most popular questions from this chapter

Consider the function \(f(x)=e^{-x^{2}}\left(-x^{2}+1\right)\). You must give exact answers for all of the following questions. Show your work. Your work must stand independent of your calculator. (a) Find all the \(x\) -intercepts. (b) Identify the local extrema of \(f(x)\). (c) Sketch a graph of \(f\), labeling the \(x\) -coordinates of all local and global extrema. (d) Now consider the function \(g(x)=|f(x)|\). i. What are the critical points of \(g\) ? ii. Classify the critical points of \(g(x)\).

Draw a semicircle of radius \(2 .\) Inscribe a rectangle as shown. What are the dimensions of the rectangle of the largest area? What is the largest area?

In Problems 23 through 29, differentiate. In Problems 23 through 25, assume \(f\) is differentiable. Your answers may be in terms of \(f\) and \(f^{\prime} .\) Let \(f(x)=x^{x}\). (a) Use numerical methods to approximate \(f^{\prime}(2)\). (b) Refer to your answer to part (a) to show that \(f^{\prime}(x) \neq x \cdot x^{x-1} .\) What is it about \(f\) that makes it not a power function? (c) Refer to your answer to part (a) to show that \(f^{\prime}(x) \neq \ln x \cdot x^{x} .\) What is it about \(f\) that makes it not an exponential function? (d) Challenge: Figure out how to rewrite \(x^{x}\) so you can use the Chain Rule to differentiate it

Just outside Newburgh, the New York State Thruway (I-87), running north-south, intersects Interstate 84, which runs east-west. At noon a car is at this intersection and traveling north at a constant speed of 55 miles per hour. At this moment a Greyhound bus is 150 miles west of the intersection and traveling east at a steady pace of 65 miles per hour. (a) When will the bus and the car be closest to one another? (b) What is the minimum distance between the two vehicles? (c) How far away from the intersection is the bus at this time?

Find \(f^{\prime}(x) .\) Do these problems without using the Quotient Rule. $$ f(x)=x 5^{\frac{1-1}{2}} $$

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