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If \(M(t)=M_{0} e^{r t}\), find \(\frac{d M}{d t}\) and show that \(\frac{d M}{d t}=r M\). \(\left(\frac{d M}{d t}=r M\right.\) is called a differential equation because it is an equation with a derivative in it. You have just shown that \(M(t)=M_{0} e^{r t}\) is a solution to this differential equation.)

Short Answer

Expert verified
The derivative \(\frac{dM}{dt} = r \cdot M(t)\), confirming that \(M(t) = M_{0} e^{r t}\) is a solution to this differential equation.

Step by step solution

01

Differentiating the function

We start by finding derivative of function \(M(t)\) with respect to \(t\). This involves using the chain rule of differentiation, which states that the derivative of a composition of functions is the derivative of the outer function multiplied by the derivative of the inner function.\n\nLet's differentiate \(M(t) = M_0 \cdot e^{rt}\). Using the chain rule, the 'outer function' here is the exponential function and the 'inner function' is \(rt\).\n\nSo, \(\frac{dM}{dt} = M_0 \cdot e^{rt} \cdot \frac{d(rt)}{dt} = M_0 \cdot e^{rt} \cdot r = r \cdot M_0 \cdot e^{rt}\)
02

Simplifying the derivative

The derivative \(\frac{dM}{dt} = r \cdot M_0 \cdot e^{rt}\) from Step 1 is correct but it can be simplified by recognizing that \(M_0 \cdot e^{rt} = M(t)\) (which is given in the problem), leading to: \(\frac{dM}{dt} = r \cdot M(t)\)
03

Verifying the differential equation

Checking whether the derivative expression found in Step 2 fits the form \(\frac{dM}{dt}=r \cdot M(t)\) required by the differential equation. Since our result from Step 2 is exactly this, we have confirmed that \(M(t)=M_{0} e^{r t}\) is indeed a solution to this differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule of Differentiation
Understanding the chain rule of differentiation is crucial in calculus as it provides a method for taking the derivative of composite functions. In essence, the chain rule states that if you have a function that can be expressed as one function inside another, the derivative of that composite function is the product of the derivative of the outer function and the derivative of the inner function with respect to the outer function's variable.Let's consider a composite function like \( f(g(x)) \). To apply the chain rule, we'd designate \(g(x)\) as the inner function and \(f(u)\), where \(u=g(x)\), as the outer function. The chain rule tells us that the derivative of \(f\) with respect to \(x\) is \(f'(g(x)) \times g'(x)\).

Application to Exponential Functions

When you're working with an exponential function where the exponent is itself a function of the variable—like \( e^{r t} \) where \( r t \) depends on \( t \)—the chain rule is essential. In the expression \(M(t) = M_0 e^{r t}\), to find \(\frac{dM}{dt}\), you must recognize that the 'inner function' is \(r t\) and the 'outer function' is the exponential part \(e^u\), where \(u = r t\). The chain rule simplifies the process greatly, making the solution neat and more understandable.
Exponential Growth
Exponential growth is a concept in mathematics where a quantity increases at a rate proportional to its current value. This pattern can be observed in various natural and social phenomena such as population growth, the spread of diseases, and in finance through compound interest. In mathematical terms, exponential growth is described by functions of the form \(M(t) = M_0 e^{r t}\), where \(M_0\) is the initial quantity, \(t\) is time, and \(r\) is a positive constant representing the rate of growth. This \(r\) makes all the difference—it determines how fast the quantity grows over time.The key characteristic of exponential growth is that the rate of growth is always changing and it's always proportional to the current size. This sets exponential growth apart from linear growth, where the rate of increase is constant. The ability to determine the rate of growth and understand its implications is particularly important, not just in solving mathematical problems, but in real-world applications where predicting future trends is valuable.
Derivative of Exponential Functions
The derivative of an exponential function is unique because the function’s derivative is directly proportional to the function itself. Specifically, if you have an exponential function with base \(e\), like \(f(t) = e^{rt}\), its derivative with respect to \(t\) is \(f'(t) = r \times e^{rt}\), assuming \(r\) is constant. The elegance of exponential functions like these is that the process of differentiation streamlines them, preserving their form while introducing the proportionality constant \(r\).

Understanding Through the Exercise

In our exercise, \(M(t)\) represents an exponential function where the rate of change itself is an exponential function. With the factor of \(r\), the derivative of \(M\) with respect to \(t\) reflects how change in \(M\) is directly proportional to \(M\) itself. Hence, the equation \(\frac{dM}{dt} = rM\) is not only the derivative but also the fundamental definition of exponential growth—the rate of change at any time is proportional to the current amount. This deepens our understanding of exponential functions and their derivatives, showing how the calculus of exponential growth mirrors the concept of growth in the real world.

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Most popular questions from this chapter

A wet dish towel is put on the back of a kitchen chair to dry. It dries at a rate proportional to the difference in moisture content between the dishtowel and the kitchen air. Assume that the moisture content in the air is fixed and is given by \(M\). (a) Set up the differential equation involving \(W=W(t)\), the amount of water in the dish towel at time \(t\). (b) Find and sketch the solution.

Newton's law of cooling in its more general form tells us that the rate at which the temperature between an object and its environment changes is proportional to the difference in temperatures. In other words, if \(D(t)\) is the temperature difference, then \(\frac{d D}{d t}=k D\) (a) Solve the differential equation \(\frac{d D}{d t}=k D\) for \(D(t)\). (b) Suppose a hot object is placed in a room whose temperature is kept constant at \(R\) degrees. Let \(T(t)\) be the temperature of the object. Newton's law says that the hot object will cool at a rate proportional to the difference in temperature between the object and its environment. Write a differential equation reflecting this statement and involving \(T\). Explain why this differential equation is equivalent to the previous one. (c) What is the sign of the constant of proportionality in the equation you wrote in part (b)? Explain. (d) Suppose that instead of a hot object we now consider a cold object. Suppose that we are interested in the temperature of a cold cup of lemonade as it warms up to room temperature. Let \(L(t)\) represent the temperature of the lemonade at time \(t\) and assume that it sits in a room that is kept at 65 degrees. At time \(t=0\), the lemonade is at 40 degrees. 15 minutes later it has warmed to 50 degrees. i. Sketch a graph of \(L(t)\) using your intuition and the information given. ii. Is \(L(t)\) increasing at an increasing rate, or a decreasing rate?

(a) Is \(y=e^{t}+\ln t\) a solution to the differential equation \(\frac{d y}{d t}=y-\frac{y}{t}\) ? (b) Is \(y=t e^{t}\) a solution to the differential equation \(\frac{d y}{d t}=y-\frac{y}{t}\) ?

Which is a better deal, an account offering \(4 \%\) annual interest compounded continuously or an account offering \(4.2 \%\) interest compounded annually? What is the effective annual yield of the former account?

When a population has unlimited resources and is free from disease and strife, the rate at which the population grows is proportional to the population. Assume that both the bee and the mosquito populations described below behave according to this model. In both scenarios you are given enough information to find the proportionality constant \(k\). In one case, the information allows you to find \(k\) solely using the differential equation, without requiring that you solve it. In the other scenario, you must actually solve the differential equation in order to find \(k\). (a) Let \(M=M(t)\) be the mosquito population at time \(t, t\) in weeks. At \(t=0\), there are 1000 mosquitoes. Suppose that when there are 5000 mosquitoes, the population is growing at a rate of 250 mosquitoes per week. Write a differential equation reflecting the situation. Include a value for \(k\), the proportionality constant. (b) Let \(B=B(t)\) be the bee population at time \(t, t\) in weeks. At \(t=0\), there are 600 bees. When \(t=10\), there are 800 bees. Write a differential equation reflecting the situation. Include a value for \(k\), the proportionality constant.

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