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Identify the probability density function. Then find the mean, variance, and standard deviation without integrating. $$ f(x)=\frac{1}{8} e^{-x / 8},[0, \infty) $$

Short Answer

Expert verified
For the given function \( f(x)=\frac{1}{8} e^{-x / 8} \), the identified distribution is an Exponential Distribution. The mean value is 8, the variance is 64, and the standard deviation is 8.

Step by step solution

01

Identify the Distribution

Recognize \( f(x) = \frac{1}{8} e^{-x / 8} \) as an Exponential Distribution. Here the lambda \(\lambda\), the rate parameter, is given as \( \frac{1}{8} \). This distribution is characterized by its constant failure rate.
02

Calculate the Mean

The mean, or expected value, of an exponential distribution is given by \( \frac{1}{\lambda} \). Substituting our value of \( \lambda \) into this gives: Mean = \( \frac{1}{\lambda} = \frac{1}{\frac{1}{8}} = 8 \).
03

Calculate the Variance

The variance of an exponential distribution is given by \( \frac{1}{\lambda^2} \). Substituting our value of \( \lambda \) into this gives: Variance = \( \frac{1}{\lambda^2} = \frac{1}{(\frac{1}{8})^2} = 64 \).
04

Calculate the Standard Deviation

The standard deviation is the square root of the variance. So, Standard Deviation = \( \sqrt{Variance} = \sqrt{64} = 8 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
Understanding the probability density function (PDF) is essential for grasping how probabilities are distributed across different values in a continuous random variable. The PDF for the exponential distribution, represented as \( f(x) = \frac{1}{\lambda}e^{-\frac{x}{\lambda}} \), describes the time between events in a Poisson process, where events occur continuously and independently at a constant average rate.

For the exercise in question, the PDF is identified as \( f(x) = \frac{1}{8} e^{-\frac{x}{8}} \), where the rate parameter \( \lambda \) is \( \frac{1}{8} \). This function tells us the probability of an event occurring within a small interval at a certain distance \( x \) from a starting point. It is important to note that the area under the entire curve of the PDF equals 1, symbolizing the certitude that some outcome will occur.
Mean of Exponential Distribution
The mean, or the expected value, of an exponential distribution gives us a measure of the central tendency or the average wait time for the first event to occur. In mathematical terms, the mean is the reciprocal of the rate parameter \( \lambda \), expressed as \( \frac{1}{\lambda} \).

In our exercise, with \( \lambda = \frac{1}{8} \), the mean is computed as 8. This result translates to an average wait of 8 units of time (be it seconds, minutes, etc.) for the event of interest to happen. This core concept is vital as it allows us to set expectations for the timing of events in a real-world scenario modeled by this distribution.
Variance and Standard Deviation
Variance and standard deviation are two closely related statistical measures that tell us about the spread of a probability distribution. In the case of the exponential distribution, the variance is given by \( \frac{1}{\lambda^2} \), indicating how much the values deviate from the mean on average.

In our case, the variance is 64, which suggests a wide spread around the mean wait time of 8 units. Moreover, the standard deviation is the square root of the variance, providing a measure in the same units as the original data. Hence, with a standard deviation of 8, we can interpret it as a typical deviation from the mean time between events for this particular exponential distribution. A larger standard deviation implies a greater unpredictability in the timing of the events.
Exponential Distribution Properties
The exponential distribution possesses unique properties that make it a valuable model for certain real-world situations. Firstly, it is memoryless, meaning the probability of an event occurring is independent of how much time has already passed. It’s a defining quality that allows the distribution to be used for modeling scenarios without aftereffects.

Secondly, the exponential distribution is skewed to the right, meaning the tail of the distribution extends to the right, indicating more large values or longer wait times are possible. This characteristic is reflective of certain random processes where shorter wait times are more common, and longer wait times, while less likely, are still possible.

Lastly, this distribution only has one parameter, \( \lambda \), which greatly simplifies statistical modeling and analysis, as it controls both the mean and variance. Understanding these properties helps in accurately applying the exponential distribution to appropriate scenarios, like calculating the life expectancy of machinery, the time until the next earthquake, or the wait time in a queue.

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