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Identify the probability density function. Then find the mean, variance, and standard deviation without integrating. $$ f(x)=\frac{1}{10},[0,10] $$

Short Answer

Expert verified
The probability density function is a Uniform Distribution. The mean is 5, the variance is 8.33 and the standard deviation is 2.89.

Step by step solution

01

Identify the Probability Density Function

The given function fits the description of a Uniform Distribution. A Uniform Distribution is a type of probability distribution in which all outcomes are equally likely. A deck of cards has within it uniform distributions, because the likelihood of drawing a heart, a club, a diamond or a spade is equally likely. This is a continuous distribution. The function \(f(x) = \frac{1}{10}\) for \(x\) in the range \([0,10]\) describe a Uniform Distribution.
02

Find the Mean

The mean, or expected value, of a continuous uniform distribution in the range \(a\) to \(b\) is given by the formula \(\mu = \frac{1}{2}(a + b)\). Plugging in our values: \(\mu = \frac{1}{2}(0 + 10) = 5\).
03

Find the Variance

The variance for a uniform distribution is given by the formula \(\sigma^2 = \frac{(b - a)^2}{12}\). Plugging in our values gives: \(\sigma^2 = \frac{(10 - 0)^2}{12} = \frac{100}{12} = 8.33.\)
04

Find the Standard Deviation

The standard deviation is the square root of the variance. So the standard deviation, \(\sigma\), is \(\sqrt{8.33} = 2.89.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
A Probability Density Function (PDF) in probability theory is a mathematical function that describes the likelihood of different outcomes in a continuous random variable. In simple terms, it shows how probable different values of a random variable are. For a function to qualify as a PDF, the area under the curve described by the function over the entire range of possible outcomes must equal 1. In a uniform distribution, like the one given by the function \(f(x) = \frac{1}{10}\) when \(x\) is between 0 and 10, the value of the PDF is constant. This means every outcome in the range is equally likely, which defines the characteristic flat-line graph of a uniform distribution PDF. It's perfect for situations where every outcome is equally probable.
Mean of Uniform Distribution
The mean of a uniform distribution, also known as the expected value, is the average outcome you'd predict if you randomly selected many values from the distribution. For a continuous uniform distribution that spreads from \(a\) to \(b\), the mean is calculated as \( \mu = \frac{1}{2}(a + b) \). This formula expresses the mean as the midpoint between the smallest and largest values of the distribution. So if you look at the middle of the distribution's range, you'll find the mean. For our example, where \(a = 0\) and \(b = 10\), the mean is \( \mu = 5 \). This makes sense because, in a uniform distribution, you expect the central value to be the most representative of your outcomes.
Variance of Uniform Distribution
Variance measures how much the values in a distribution spread out compared to the mean. In the case of a uniform distribution, variance helps us understand how the outcomes deviate from the mean across the distribution's range. The variance for a uniform distribution is given by the formula \( \sigma^2 = \frac{(b - a)^2}{12} \). This formula stems from the fact that the distribution is spread out evenly over the interval \([a, b]\). Applying this to our example of \(a = 0\) and \(b = 10\), the variance comes out to be approximately \(8.33 \). This variance value indicates a moderate spread around the mean of 5 for this distribution.
Standard Deviation of Uniform Distribution
The standard deviation is a statistical measurement that reflects the average amount each number in a set differs from the mean. In practical terms, it tells you how spread out the numbers are in your distribution. For a uniform distribution, the standard deviation is the square root of the variance and is calculated with the formula \( \sigma = \sqrt{\sigma^2} \). In our case, using our previously determined variance \( \sigma^2 = 8.33 \), the standard deviation is approximately \( \sigma = 2.89 \). This value provides us with an intuitive measure of spread—most outcomes are within a range of about 3 units from the mean of 5. Therefore, with a uniform distribution, even though all outcomes are equally likely, they still show a typical distance from the center, called the mean.

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Most popular questions from this chapter

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