/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Determine whether the improper i... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the improper integral diverges or converges. Evaluate the integral if it converges, and check your results with the results obtained by using the integration capabilities of a graphing utility. $$ \int_{0}^{2} \frac{1}{\sqrt[3]{x-1}} d x $$

Short Answer

Expert verified
The result of the evaluation depends on the calculation. The final result will be given by the sum of the two evaluated integrals if they form a finite number. If not, then the integral diverges. This is confirmed by checking the integral using a graphing utility.

Step by step solution

01

Identify the function

This is an integral of the function \(f(x) = \frac{1}{\sqrt[3]{x-1}}\) from 0 to 2.
02

Break the integral at the points of discontinuity

Since x = 1 is a point of discontinuity, we can break the integral into two, from 0 to 1 and from 1 to 2. So, \(\int_{0}^{2} \frac{1}{\sqrt[3]{x-1}} d x = \int_{0}^{1} \frac{1}{\sqrt[3]{x-1}} d x + \int_{1}^{2} \frac{1}{\sqrt[3]{x-1}} d x\)
03

Solve the integral using limit

Now we take the limit approach to solve this integral. For the first integral, we can rewrite as \(\lim_{{t \to 1^-}} \int_{0}^{t} \frac{1}{\sqrt[3]{x-1}} d x\). For the second integral, we can rewrite as \(\lim_{{t \to 1^+}} \int_{t}^{2} \frac{1}{\sqrt[3]{x-1}} d x\)
04

Evaluate the integral

Now evaluate these integrals and add them. If they form a finite number then the integral converges and the finite value would be that value. If the result is undefined or infinite, the integral would diverge.
05

Check with graphing utility

Plug the integral into a graphing utility to confirm your results.

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