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Evaluate the definite integral. \(\int_{-1}^{1}\left(e^{x}-e^{-x}\right) d x\)

Short Answer

Expert verified
The definite integral of the given function from -1 to 1 is 0

Step by step solution

01

Identify the Function and its Limits

The function given is \(f(x) = e^{x} - e^{-x}\). The limits of the integral are from -1 to 1, expressed as \(\int_{-1}^{1}\)
02

Apply the Definite Integral

The integral of \(e^{x}\) is \(e^{x}\) and the integral of \(e^{-x}\) is \(-e^{-x}\). Therefore, the definite integral from -1 to 1 of the function \(f(x)\) is \(\int_{-1}^{1}\left(e^{x}-e^{-x}\right) d x = [e^{x} + e^{-x}]_{-1}^{1}\)
03

Substitute the Limits

Now we substitute the upper and lower limits, i.e, substitute 1 for x first, then -1 for x. It has to be in the form (at x=1) - (at x=-1). This results in \((e^{1} + e^{-1}) - (e^{-1} + e^{1})\)
04

Simplify the Expression

After substituting, simplify the expression. This gives us 0 because \(e - \frac{1}{e} - e - \frac{1}{e} = 0\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are one of the most common types of mathematical functions that involve the constant "e". This constant, approximately equal to 2.71828, is particularly special due to its unique properties related to growth and decay processes.
Exponential functions usually appear in the form of \(e^{x}\), where "x" is the variable. Here, the function grows exponentially as "x" increases. Another variant of exponential functions is \(e^{-x}\), which represents a similar growth pattern but in the decreasing direction as "x" increases.
When working with exponential functions in calculus, it’s important to recognize that their derivatives and integrals also involve exponential functions, making them particularly neat and predictable to calculate. Focusing on these properties allows for simplification during integration and differentiation processes, which is a significant part of solving calculus problems involving exponential functions.
Integral Calculus
Integral calculus is a crucial part of calculus that focuses on the concept of integration. While differential calculus is concerned with finding rates of change, integral calculus is all about summing up parts to find a whole, often referred to as the "antidifferentiation" process.
Definite integrals, like the one in our example \(\int_{-1}^{1}(e^{x} - e^{-x})\, dx\), help determine the net accumulation of quantities, which can be considered the "total" change between specific limits. The process of evaluating a definite integral involves calculating the antiderivative (or the indefinite integral) and then using the limits to find the numerical value. This process quantifies the net change, taking into account both positive and negative contributions.
Understanding integral calculus is fundamental for solving a wide range of problems in physics, engineering, and other fields, as it provides insights into areas such as total distance traveled, area under curves, and accumulated growth.
Integration Techniques
Integration can be more straightforward if one uses specific techniques that simplify the process. One common technique is recognizing and using known integral formulas, such as those for exponential functions.
In our given problem, the integration of \(e^{x}\) over a certain interval is straightforward, as it simply results in \(e^{x}\), while \(e^{-x}\) integrates to \(-e^{-x}\). By applying these integral formulas, we can directly substitute and evaluate the integral over the given range effectively. This approach, known as the Fundamental Theorem of Calculus, connects differentiation and integration, allowing us to compute definite integrals by evaluating antiderivatives at the boundaries of the interval.
It's crucial to be familiar with various integration techniques, such as substitution, integration by parts, and partial fraction decomposition, although they are not always necessary. These techniques become significantly useful when dealing with more complex integrands that are not immediately solvable using basic formulas. Understanding and practicing these techniques enhance one's ability to solve various integrals efficiently.

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Most popular questions from this chapter

The table gives the marginal benefit and marginal cost of producing \(x\) units of a product for a given company. Plot the points in each column and use the regression feature of a graphing utility to find a linear model for marginal benefit and a quadratic model for marginal cost. Then use integration to find the benefit \(B\) and cost \(C\) equations. Assume \(B(0)=0\) and \(C(0)=425 .\) Finally, find the intervals in which the benefit exceeds the cost of producing \(x\) units, and make a recommendation for how many units the company should produce based on your findings. (Source: Adapted from Taylor, Economics, Fifth Edition) \(\begin{array}{|l|c|c|c|c|}\hline \text { Number of units } & {1} & {2} & {3} & {4} & {5} \\ \hline \text { Marginal benefit } & {330} & {320} & {290} & {270} & {250} \\ \hline \text { Marginal cost } & {150} & {120} & {100} & {110} & {120} \\ \hline\end{array}\) \(\begin{array}{|l|l|l|l|l|}\hline \text { Number of units } & {6} & {7} & {8} & {9} & {10} \\ \hline \text { Marginal benefit } & {230} & {210} & {190} & {170} & {160} \\ \hline \text { Marginal cost } & {140} & {160} & {190} & {250} & {320} \\ \hline\end{array}\)

Find the change in cost \(C\), revenue \(R,\) or profit \(P,\) for the given marginal. In each case, assume that the number of units \(x\) increases by 3 from the specified value of \(x .\) Marginal \(\quad\) Number of Units, \(x\) \(\frac{d P}{d x}=12.5(40-3 \sqrt{x}) \quad x=125\)

The growth rate of Horry County in South Carolina can be modeled by dP/d \(t=105.46 t+2642.7,\) where \(t\) is the time in years, with \(t=0\) corresponding to \(1970 .\) The county's population was \(226,992\) in 2005. (Source: U.S. Census Bureau) (a) Find the model for Horry County's population. (b) Use the model to predict the population in 2012 . Does your answer seem reasonable? Explain your reasoning.

Evaluate the definite integral. \(\int_{-1}^{0}\left(t^{1 / 3}-t^{2 / 3}\right) d t\)

Sketch the region whose area is represented by the definite integral. Then use a geometric formula to evaluate the integral. \(\int_{-3}^{3} \sqrt{9-x^{2}} d x\)

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