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Use a symbolic integration utility to evaluate the definite integral. \(\int_{1 / 2}^{1}(x+1) \sqrt{1-x} d x\)

Short Answer

Expert verified
The definite integral \(\int_{1 / 2}^{1}(x+1) \sqrt{1-x} d x\) will be evaluated by breaking the problem into two smaller integrals. Those integrals will then be evaluated separately and the results combined to obtain the final answer.

Step by step solution

01

Start with the given integral

Start with the given integral \(\int_{1/2}^{1}(x+1)\sqrt{1-x} dx\). Begin by breaking down the original integral into two separate integrals.
02

Break down the integral

First break down the integral into \( \int_{1/2}^{1}x\sqrt{1-x} dx \) + \(\int_{1/2}^{1}\sqrt{1-x} dx\)
03

Solving the first integral

The first integral \( \int_{1/2}^{1}x\sqrt{1-x} dx \) can be solved through substitution. Take \(u = 1-x\) and find the derivative \(du = -dx\), and then substitute \(x\) from \(u\) and integrate. The limits needs to be changed accordingly
04

Solving the second integral

The second integral \(\int_{1/2}^{1}\sqrt{1-x} dx\) is of standard form and can directly be applied with the power law of integrals (integration of \(x^n\)) to get the result. The limits needs to be applied here.
05

Adding and Finalizing Result

After calculating both integrals, add the result of both the integrals back together and simplify to achieve the final result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Symbolic Integration
Symbolic integration involves finding the analytical expression that represents the area under a curve for a given mathematical function. Unlike numerical integration, which approximates the area using numerical methods, symbolic integration yields an exact expression.

In the context of our definite integral \(\int_{1 / 2}^{1}(x+1) \sqrt{1-x} d x\), symbolic integration allows us to determine the precise area bounded by the curve of the function \(x+1)\sqrt{1-x}\), the x-axis, and the vertical lines \(x=1/2\) and \(x=1\). To carry out the integration symbolically, one may decompose the integrand into simpler parts, employ various integration techniques like substitution or integration by parts, and apply integration rules, such as the power rule, to find the indefinite integral. Finally, the definite integral is calculated by evaluating this indefinite integral at the upper and lower limits of integration and subtracting the latter from the former.
Integral Substitution Method
The integral substitution method, also known as u-substitution, is a technique used to simplify the process of finding indefinite integrals, particularly when the integrand is a composite function. It involves identifying a part of the integrand to substitute with a new variable \(u\), thus transforming the integral into something easier to evaluate.

For example, when dealing with the integral \(\int_{1/2}^{1}x\sqrt{1-x} dx\), by taking \(u = 1-x\), the term inside the square root becomes simpler (\(u\)) and the differential \(dx\) is expressed in terms of \(du\) as \(dx = -du\). This changes the limits of integration and the integral becomes easier to evaluate using the power rule. After integrating, you reverse the substitution by replacing \(u\) with the original terms to revert to the variable of the original integral, \(x\). This allows for straightforward evaluation of the definite integral by plugging in the new limits of integration.
Power Rule for Integration
The power rule for integration is a fundamental technique for finding antiderivatives of power functions. In essence, for any real number \(n \eq -1\), the indefinite integral of \(x^n\) with respect to \(x\) is given by \(\int x^n dx = \frac{x^{n+1}}{n+1} + C\), where \(C\) represents the constant of integration.

In practice, to evaluate the integral \(\int_{1/2}^{1}\sqrt{1-x} dx\), one would first rewrite the integrand in power form as \( (1-x)^{1/2} \) and apply the power rule. After integration, the result is \(\frac{2}{3}(1-x)^{3/2}\), acknowledging that the exponent increased by one and we divided by the new exponent. When computing a definite integral, we then evaluate this expression at \(x=1\) and \(x=1/2\), subtracting one from the other to achieve the numerical value of the area under the curve between these two points. Understanding and applying the power rule is crucial for any student of calculus, as it simplifies the process of finding integrals for a wide range of functions.

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