Chapter 4: Problem 5
Find the derivative of the function. \(y=e^{5 x}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 4: Problem 5
Find the derivative of the function. \(y=e^{5 x}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Use the given information to write an equation for \(y .\) Confirm your result analytically by showing that the function satisfies the equation \(d y / d t=C y .\) Does the function represent exponential growth or exponential decay? $$ \frac{d y}{d t}=5.2 y, \quad y=18 \text { when } t=0 $$
Solve for \(x\) or \(t\) $$ \frac{10}{1+4 e^{-0.01 x}}=2.5 $$
Solve for \(x\) or \(t\) $$ \ln 2 x=2.4 $$
\$ 3000\( is invested in an account at interest rate \)r,$ compounded continuously. Find the time required for the amount to (a) double and (b) triple. $$ r=0.12 $$
Demand The demand function for a product is given by $$p=10,000\left(1-\frac{3}{3+e^{-0.001 x}}\right)$$ where \(p\) is the price per unit and \(x\) is the number of units sold. Find the numbers of units sold for prices of (a) \(p=\$ 500\) and (b) \(p=\$ 1500\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.