Chapter 2: Problem 11
Find the derivative of the function. $$ g(x)=x^{2}+5 x $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 2: Problem 11
Find the derivative of the function. $$ g(x)=x^{2}+5 x $$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Dow Jones Industrial Average The table shows the year-end closing prices \(p\) of the Dow Jones Industrial Average (DJIA) from 1992 through \(2006,\) where \(t\) is the year, and \(t=2\) corresponds to \(1992 .\) $$ \begin{array}{|c|c|c|c|c|c|}\hline t & {2} & {3} & {4} & {5} & {6} \\ \hline p & {3301.11} & {3754.09} & {3834.44} & {5117.12} & {6448.26} \\\ \hline\end{array} $$ $$ \begin{array}{|c|c|c|c|c|c|}\hline t & {7} & {8} & {9} & {10} & {11} \\\ \hline p & {7908.24} & {9181.43} & {11,497.12} & {10,786.85} & {10,021.50} \\\ \hline\end{array} $$ $$ \begin{array}{|c|c|c|c|c|c|}\hline t & {12} & {13} & {14} & {15} & {16} \\\ \hline p & {8341.63} & {10,453.92} & {10,783.01} & {10,717.50} & {12,463.15} \\\ \hline\end{array} $$ (a) Determine the average rate of change in the value of the DJIA from 1992 to 2006 . (b) Estimate the instantaneous rate of change in 1998 by finding the average rate of change from 1996 to 2000 . (c) Estimate the instantaneous rate of change in 1998 by finding the average rate of change from 1997 to 1999 . (d) Compare your answers for parts (b) and (c). Which interval do you think produced the best estimate for the instantaneous rate of change in \(1998 ?\)
Find the marginal profit for producing units. (The profit is measured in dollars.) $$ P=-0.5 x^{3}+30 x^{2}-164.25 x-1000 $$
Use a graphing utility to graph the function and find its average rate of change on the interval. Compare this rate with the instantaneous rates of change at the endpoints of the interval. $$ f(x)=\frac{1}{\sqrt{x}} ;[1,4] $$
Find the derivative of the function. $$ f(x)=4 x+1 $$
Find the value of the derivative of the function at the given point. $$ f(x)=-\frac{1}{2} x\left(1+x^{2}\right) \quad(1,-1) $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.