Chapter 2: Problem 10
find the second derivative of the function. $$ f(x)=x \sqrt[3]{x} $$
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Chapter 2: Problem 10
find the second derivative of the function. $$ f(x)=x \sqrt[3]{x} $$
These are the key concepts you need to understand to accurately answer the question.
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Find \(f^{\prime}(x)\) $$ f(x)=x\left(x^{2}+1\right) $$
Find the marginal revenue for producing units. (The revenue is measured in dollars.) $$ R=30 x-x^{2} $$
Use Example 6 as a model to find the derivative. $$ y=\frac{\sqrt{x}}{x} $$
Use a graphing utility to graph the function and find its average rate of change on the interval. Compare this rate with the instantaneous rates of change at the endpoints of the interval. $$ f(x)=x^{2}-6 x-1 ;[-1,3] $$
\(M A K E A D E C I S I O N: F U E L\) COST \(\quad\) A car is driven \(15,000\) miles a year and gets \(x\) miles per gallon. Assume that the average fuel cost is \(\$ 2.95\) per gallon. Find the annual cost of fuel \(C\) as a function of \(x\) and use this function to complete the table. $$ \begin{array}{|c|c|c|c|c|c|c|c|}\hline x & {10} & {15} & {20} & {25} & {30} & {35} & {40} \\ \hline C & {} & {} & {} & {} & {} & {} \\ \hline d C / d x & {} & {} & {} & {} & {} & {} & {} \\ \hline\end{array} $$ Who would benefit more from a 1 mile per gallon increase in fuel efficiency - the driver who gets 15 miles per gallon or the driver who gets 35 miles per gallon? Explain.
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