Chapter 10: Problem 39
Verify that the Ratio Test is inconclusive for the \(p\)-series. \(\sum_{n=1}^{\infty} \frac{1}{n^{3}}\)
Short Answer
Expert verified
The Ratio Test for the series \(\sum_{n=1}^{\infty} \frac{1}{n^{3}}\) is indeed inconclusive, as the limit of the ratio of subsequent terms is 1.
Step by step solution
01
Understanding The Ratio Test
The Ratio Test states that given a series \(\sum_{n=1}^{\infty} a_n\), the series is absolutely convergent if \(\lim_{n \to \infty} |\frac{a_{n+1}}{a_n}|= L < 1\), inconclusive if \(L = 1\), and divergent if \(L > 1\) or does not exist.
02
Apply The Ratio Test
Apply the Ratio Test to the \(p\)-series. \(\lim_{n \to \infty} |\frac{a_{n+1}}{a_n}| = \lim_{n \to \infty} |\frac{1/(n+1)^3}{1/n^3}| = \lim_{n \to \infty} |\frac{n^3}{(n+1)^3}| = \lim_{n \to \infty} |\frac{1}{(1+1/n)^3}| = 1\)
03
Conclusion
As the limit is 1, the Ratio Test for the series is inconclusive according to the definition from step 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergence
Convergence is a central idea in calculus and mathematical analysis that describes how a sequence or series behaves as its terms extend towards infinity. When a series converges, the sum of its terms moves closer to a specific value, meaning that as you add more terms, the total stabilizes. The series doesn't explode to infinity or oscillate wildly; instead, it "settles down." For instance, if you have a sequence and its limit, as you progress indefinitely, is a real number, the sequence converges.
- A convergent series ensures that further addition of terms will not affect the result significantly.
- The process involves checking whether adding infinitely many numbers leads to a finite sum.
P-series
A p-series is a specific kind of series where each term is in the form of \( \frac{1}{n^p} \). The behavior of these series heavily depends on the value of the exponent \( p \). Typically, they're noted in the format\( \sum_{n=1}^{\infty} \frac{1}{n^p} \), where \( n \) is a positive integer.
- If \( p > 1 \), the p-series converges. This is because the terms get small enough, rapidly enough, that their sum approaches a finite limit.
- If \( p \le 1 \), the p-series diverges, meaning its terms add up to infinity instead of settling at a number.
- In the exercise, we're dealing with \( p = 3 \). Therefore, the series \( \sum_{n=1}^{\infty} \frac{1}{n^3} \) converges as it meets the requirement of \( p > 1 \).
Limit of a sequence
The limit of a sequence becomes crucial when discussing convergence. It refers to the value that the terms of a sequence "approach" as the index (or position) increases towards infinity. When examiners or mathematicians study sequences, they often ask, "What happens in the infinite future of this sequence?"
- If the terms approach a particular number and get arbitrarily close to it, that number is called the sequence's limit.
- In mathematical practice, the notation \( \lim_{n \to \infty} a_n \) is used, meaning you observe the behavior of \( a_n \) as \( n \) grows larger and larger.
Infinite Series
An infinite series is a sequence of terms added together, potentially without end. In mathematical expressions, it's often depicted as \( \sum_{n=1}^{\infty} a_n \), which means you're summing all terms from index \( n=1 \) to infinity.
- Infinite series are all about attempting to make sense of what their sum is as more and more terms are added.
- The series can either converge or diverge based on its terms' behavior.