/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Approximate the sum of the conve... [FREE SOLUTION] | 91Ó°ÊÓ

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Approximate the sum of the convergent series using the indicated number of terms. Estimate the maximum error of your approximation. $$ \sum_{n=1}^{\infty} \frac{1}{n^{10}}, \text { three terms } $$

Short Answer

Expert verified
The approximate sum of the first three terms of the series is 1.000998334, with a maximum estimated error of 0.0000009537.

Step by step solution

01

Sum of the first three terms

Calculate the sum of the first three terms of the series. As the series is \(\sum_{n=1}^{\infty} \frac{1}{n^{10}}\), the first three terms are \(\frac{1}{1^{10}}\), \(\frac{1}{2^{10}}\), and \(\frac{1}{3^{10}}\). So, the sum \(S_3\) is \(\frac{1}{1^{10}} + \frac{1}{2^{10}} + \frac{1}{3^{10}}\).
02

Calculation

Calculate the sum obtained in Step 1. As the series is \(\sum_{n=1}^{\infty} \frac{1}{n^{10}}\), the sum of the first three terms \(S_3\) is approximately 1.000998334
03

Error Estimation

As this is a p-series (the general form is \(\sum_{n=1}^{\infty} \frac{1}{n^{p}}\) where \(p > 1\)), the maximum possible error in this approximation after summing the first three terms is less than or equal to the fourth term. Thus, the maximum error can be estimated to be \(\frac{1}{4^{10}}\).
04

Calculation

Calculate the value obtained in Step 3. Then, the maximum estimated error is approximately 0.0000009537.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Approximation
In mathematics, an approximation is about finding a number that is close to the actual value or sum of a series, especially when dealing with infinite series. Approximations offer a practical way to handle complex problems that may not be solvable in a simplistic manner. In the context of a convergent series like \( \sum_{n=1}^{\infty} \frac{1}{n^{10}} \), one might calculate the sum using a limited number of terms.
For this series, approximating the sum with just the first three terms helps simplify the problem. This means adding \( \frac{1}{1^{10}} \), \( \frac{1}{2^{10}} \), and \( \frac{1}{3^{10}} \). Approximations aren't perfect, but they balance simplicity and accuracy.
As students, you are not expected to compute an exact value, rather obtain one that is manageable and close enough for practical or educational use. When learning and applying approximation, focus on simplifying complex math while still maintaining a measure of accuracy.
Error Estimation
Estimating the error is crucial when working with approximations, like in a p-series. Error estimation tells us how far off our approximation might be from the true sum. Knowing this gives us confidence about how precise or inaccurate our estimations are.
For the given series, \( \sum_{n=1}^{\infty} \frac{1}{n^{10}} \), after summing just the first three terms, our estimated error is derived from the term right after the ones summed. Therefore, the error estimate will be \( \frac{1}{4^{10}} \). This value gives students a clear idea of the margin of error when stopping at three terms.
Think of it like having a ruler that can measure up to millimeters; even though it’s not infinite in accuracy, it’s close enough for most practical needs. Including an error estimation gives a fuller picture of where our results stand concerning precision.
P-Series
A p-series is a sequence or sum of terms where each term is of the form \( \frac{1}{n^p} \). The series converges when \( p > 1 \). Knowing this convergence helps mathematicians and students decide if they can comfortably approximate or sum the series.
In the series \( \sum_{n=1}^{\infty} \frac{1}{n^{10}} \), since \( p=10 \) is greater than 1, the series is convergent. This is essential since convergence assures that as more terms are added, the sum approaches a finite value.
Understanding p-series might initially seem challenging, but breaking it down into its components, like recognizing convergence and computing initial sums, simplifies this topic. This comprehension allows students to tackle more advanced mathematics with confidence. Remember, convergence isn't just a fancy word; it’s a tool that guides us in knowing when our efforts in approximation will lead to a sensible result.

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Most popular questions from this chapter

The random variable \(n\) represents the number of units of a product sold per day in a store. The probability distribution of \(n\) is given by \(P(n)\). Find the probability that two units are sold in a given day \([P(2)]\) and show that \(P(0)+P(1)+P(2)+P(3)+\cdots=1\) $$ P(n)=\frac{1}{2}\left(\frac{1}{2}\right)^{n} $$

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