Chapter 1: Problem 35
Sketch the graph of the equation and label the intercepts. Use a graphing utility to verify your results. $$ x=y^{2}-4 $$
Short Answer
Expert verified
The graph of the equation is a parabola that opens to the right. It has an x-intercept at \(-4\) and does not intercept the y-axis. This can be verified with a graphing utility.
Step by step solution
01
Rewriting the Equation
To make the process easier, rewrite the equation as \(y^2 = x + 4\). This shows that the function is a parabola that opens towards the right if y is the subject of the formula.
02
Finding the Intercepts
The y-intercept is found by setting \(x = 0\) in the equation. For this equation, there are no real solutions for y when \(x = 0\), hence the graph does not intercept the y-axis. The x-intercept is found by setting \(y = 0\) in the equation. Here, \(x =0^2-4 = -4\). Thus, the x-intercept is at \(-4\).
03
Sketching the Graph
Now, use the x-intercept and the rotated nature of the parabola to draw the graph. A useful point to plot is the vertex of the parabola, which is \(-4, 0\). The parabola opens to the right, with the vertex at \(-4, 0\).
04
Verification using a Graphing Utility
Finally, use a graphing utility program to verify your results. Input the original equation \(x = y^2 -4\) into the utility. You should observe that the outcome matches the graph you sketched by hand.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabolas
Parabolas are unique U-shaped curves that are the graph of a quadratic function. In the given exercise, the equation \( x = y^2 - 4 \) represents a horizontal parabola because the variable \( y \) is squared, and \( x \) is linear. Parabolas can open upwards, downwards, to the left, or to the right, depending on how the equation is set up. Here, since \( y^2 \) is positive, the parabola opens to the right. This shape implies that for each positive or negative value of \( y \), there is a corresponding value of \( x \), indicating that the function is a relation rather than a function since one \( x \) value can map to multiple \( y \) values. The vertex of the parabola is the point where it changes direction, and for the equation \( y^2 = x + 4 \), the vertex is at the point \((-4, 0)\). This point helps in sketching the parabola accurately and understanding its symmetry.
Intercepts
Intercepts are crucial for understanding where a graph crosses the axes.
- X-intercepts: Points where the graph crosses the x-axis. For this parabola, the x-intercept happens when \( y = 0 \), resulting in \( x = -4 \). Thus, the graph crosses the x-axis at the coordinate \((-4, 0)\).
- Y-intercepts: Points where the graph crosses the y-axis. For this function, setting \( x = 0 \) and solving for \( y \) results in a no-solution scenario, indicating there are no y-intercepts.
Graph Transformation
Graph transformations help us adjust the basic shape to move it across the coordinate plane. In this exercise, the given equation \( y^2 = x + 4 \) can be viewed as a transformation of the simpler equation \( y^2 = x \). Adding 4 to \( x \) shifts the entire graph 4 units to the left.
- Translation: The addition in \( x = y^2 - 4 \) moves the vertex leftwards from the origin to \((-4,0)\).
Graphing Utilities
Graphing utilities are powerful tools that assist in visualizing and confirming mathematical concepts. Programs like Desmos or a graphing calculator can be used to double-check manual graph sketches. To use them for verifying this exercise, you would input \( x = y^2 - 4 \). These utilities accurately plot the shape and position of the parabola, based on its equation. Here’s how you can benefit:
- Check the intercepts you calculated by observing the points where the graph crosses the axes.
- Visualize how the rotation and shifts affect the parabola's orientation compared to a standard form.
- Gain insights into additional features of the graph, like symmetry and vertex location.