Chapter 9: Problem 16
Evaluate the integral. $$\int \cos ^{1 / 5} x \sin x d x$$
Short Answer
Expert verified
The integral evaluates to \(-\frac{5}{6} (\cos x)^{6/5} + C\).
Step by step solution
01
Recognize the Form of the Integral
The integral is of the form \( \int u^n v \, dx \) where \( u = \cos x \), its power is \( n = \frac{1}{5} \), and \( v = \sin x \). This suggests the use of a simple substitution.
02
Use Substitution
Set \( u = \cos x \). Then, \( du = -\sin x \, dx \), which implies \( -du = \sin x \, dx \). This substitution will simplify the integral.
03
Substitute and Simplify
Replace in the integral: \( \int \cos^{1/5} x \sin x \, dx = \int u^{1/5} (-du) = - \int u^{1/5} du \). This converts the integral to a simple power rule form.
04
Apply the Power Rule for Integration
The integral \( \int u^{1/5} du \) can be solved using the power rule: \( \int u^n \, du = \frac{u^{n+1}}{n+1} + C \). Here, \( n = \frac{1}{5} \), so \( \int u^{1/5} du = \frac{u^{6/5}}{6/5} + C = \frac{5}{6} u^{6/5} + C \).
05
Substitute Back to Original Variables
Replace \( u \) back with \( \cos x \) to get the result in terms of \( x \): \(- \int u^{1/5} \, du = -\frac{5}{6} (\cos x)^{6/5} + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a fundamental technique in calculus that simplifies integrals by changing variables. Here’s the idea: when you recognize that part of the integral is a function whose derivative also appears in the integral, you can make a substitution to simplify the integral into a more manageable form.
In the given exercise, we identified the substitution by setting \( u = \cos x \). This choice transformed the integral into a simpler expression. When we do this substitution, we must also express \( dx \) in terms of \( du \), which is achieved by differentiating \( u = \cos x \), giving us \( du = -\sin x \, dx \). Hence, \( -du = \sin x \, dx \), which fits perfectly into our integral form.
Here’s how it works in steps:
In the given exercise, we identified the substitution by setting \( u = \cos x \). This choice transformed the integral into a simpler expression. When we do this substitution, we must also express \( dx \) in terms of \( du \), which is achieved by differentiating \( u = \cos x \), giving us \( du = -\sin x \, dx \). Hence, \( -du = \sin x \, dx \), which fits perfectly into our integral form.
Here’s how it works in steps:
- Identify the part of the integral that can be substituted, ideally where its derivative is also present elsewhere in the integral.
- Make the substitution and also find an expression for \( dx \) in terms of \( du \).
- Rewrite the integral in terms of \( u \), eliminating \( x \) from the integral.
Power Rule for Integration
The power rule for integration is an extremely useful technique for solving integrals of the form \( \int x^n \, dx \), where \( n eq -1 \). It provides a straightforward way to find antiderivatives by increasing the power of \( x \) by one and then dividing by this new power.
In our solution, the integration became \( \int u^{1/5} \, du \) after substitution. According to the power rule:
Understanding and applying the power rule is crucial for tackling a wide variety of integrals efficiently.
In our solution, the integration became \( \int u^{1/5} \, du \) after substitution. According to the power rule:
- Increase the exponent by one: \( n + 1 = \frac{1}{5} + 1 = \frac{6}{5} \).
- The new integral becomes \( \frac{u^{6/5}}{6/5} + C \), simplifying to \( \frac{5}{6} u^{6/5} + C \).
Understanding and applying the power rule is crucial for tackling a wide variety of integrals efficiently.
Trigonometric Integrals
Trigonometric integrals involve functions like \( \sin x \), \( \cos x \), and other trigonometric identities. Solving these integrals often requires ingenuity, involving substitutions or recognizing trigonometric identities.
In our exercise, \( \cos ^n x \sin x \, dx \) is a form of trigonometric integral. Strategic substitution was key here, which leveraged the derivative relationship between sine and cosine.
In our exercise, \( \cos ^n x \sin x \, dx \) is a form of trigonometric integral. Strategic substitution was key here, which leveraged the derivative relationship between sine and cosine.
- Recognize trigonometric identities to simplify expressions.
- Use substitutions like \( u = \cos x \) to turn the integral into a basic polynomial form that is easier to handle.
- Apply techniques like the power rule post-substitution to evaluate the integral.