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Evaluate the integrals assuming that \(n\) is a positive integer and \(b \neq 0.\) $$\int \sqrt[n]{a+b x} d x \quad \,(b \neq 0)$$

Short Answer

Expert verified
\( \int \sqrt[n]{a+bx} \, dx = \frac{n}{b(n+1)} (a+bx)^{\frac{n+1}{n}} + C \) for \( b \neq 0 \).

Step by step solution

01

Use Substitution

Let us use the substitution method to simplify the integral. We set \( u = a + bx \). Therefore, the derivative \( du \) becomes \( b \, dx \), which means \( dx = \frac{du}{b} \). This changes the integral to: \[ \int \sqrt[n]{u} \cdot \frac{1}{b} \, du. \] Simplifying, this becomes: \[ \frac{1}{b} \int u^{\frac{1}{n}} \, du. \]
02

Integrate Using Power Rule

Apply the power integration rule: \( \int x^m \, dx = \frac{x^{m+1}}{m+1} + C \) where \( m eq -1 \). Here, \( m = \frac{1}{n} \), so \( m + 1 = \frac{1}{n} + 1 = \frac{1+n}{n} \). The integral becomes: \[ \frac{1}{b} \left( \frac{u^{\frac{n+1}{n}}}{\frac{n+1}{n}} \right) + C. \] Simplify \( \frac{1}{b} \cdot \frac{n}{n+1} \cdot u^{\frac{n+1}{n}} \).
03

Substitute Back U

Substitute back \( u = a + bx \) into the expression to return to the variable \( x \). The integral becomes: \[ \frac{n}{b(n+1)} (a+bx)^{\frac{n+1}{n}} + C. \] This is the evaluated indefinite integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a powerful technique used to simplify complex integrals. When faced with an integral that seems difficult to solve directly, substitution can make it more manageable.

In this approach, we introduce a new variable, usually denoted as \( u \), to replace a portion of the integrand. This helps convert the integral into a simpler form.

For example, in the original problem \( u = a + bx \) was chosen. This is a strategic choice because it replaces a complex expression with a simpler variable \( u \). The main task is to transform \( dx \) into terms of \( du \), achieved by finding \( du \). Here:
  • We differentiate \( u = a + bx \), resulting in \( du = b \, dx \).
  • Then solve for \( dx \), so \( dx = \frac{du}{b} \).
This substitution changes the original integral in terms of \( x \) into an integral in terms of \( u \), simplifying the problem significantly.
Power Integration Rule
The power integration rule is a fundamental tool in calculus, making the integration of polynomials straightforward. This rule deals with functions of the form \( x^m \).

The general formula is: \[ \int x^m \, dx = \frac{x^{m+1}}{m+1} + C, \] where \( m eq -1 \). This formula originates from reversing the process of differentiation for polynomials.

In the solved exercise, after substituting \( u \) for \( a + bx \), the integral was:
  • \( \,\int u^{\frac{1}{n}} \, du \), which mirrors \( x^m \) with \( m = \frac{1}{n} \).
  • Plug \( m = \frac{1}{n} \) into the power integration rule:

    \[ \int u^{\frac{1}{n}} \, du = \frac{u^{\frac{1+n}{n}}}{\frac{1+n}{n}} + C. \]
This step transforms the integral into a form that can easily be evaluated.
Indefinite Integral
Indefinite integrals represent the family of all antiderivatives of a function. Unlike definite integrals, they do not have upper and lower limits.

The result of an indefinite integral is a general expression plus a constant \( C \). This constant ensures all possible antiderivatives are covered because differentiation introduces potential constants.

In the example problem, after integration, we have:
  • \( \frac{n}{b(n+1)} (a+bx)^{\frac{n+1}{n}} + C \)
Key parts of this expression:
  • The term \( (a+bx)^{\frac{n+1}{n}} \) shows the integration result of \( u \) back-substituted to \( x \).
  • \( \frac{n}{b(n+1)} \) is the factor from the substitution and power rule application.
The presence of \( C \) indicates all possible antiderivatives are accounted for, demonstrating the essence of indefinite integrals.

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