Chapter 6: Problem 29
(a) Use the Mean-Value Theorem to show that if \(f\) is differentiable on an interval \(I,\) and if \(\left|f^{\prime}(x)\right| \leq M\) for all values of \(x\) in \(I,\) then $$|f(x)-f(y)| \leq M|x-y|$$ for all values of \(x\) and \(y\) in \(I\). (b) Use the result in part (a) to show that $$|\sin x-\sin y| \leq|x-y|$$ for all real values of \(x\) and \(y\).
Short Answer
Step by step solution
Understanding the Mean Value Theorem (MVT)
Applying MVT to |f(x) - f(y)|
Bounding the Derivative with M
Verifying the Condition for Sine Function
Applying the Result to Sine Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiability
Derivative
Sine Function
Inequality Proof
- Utilizing the Mean Value Theorem to link the difference \( |f(x) - f(y)| \) with the derivative \( |f'(c)| \, |x - y| \).
- Recognizing that if a derivative is bounded by an upper limit \( M \), so too is the change in the function values constrained as \( \leq M |x - y| \).