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In Exercises find \(d y / d x\). $$y=\ln \left|x^{3}-7 x^{2}-3\right|$$

Short Answer

Expert verified
The derivative is \( \frac{dy}{dx} = \frac{3x^2 - 14x}{x^3 - 7x^2 - 3} \).

Step by step solution

01

Identify the Function

Examine the given function, which is a natural logarithm: \( y = \ln \left| x^3 - 7x^2 - 3 \right| \). We'll use the chain rule and the derivative of a logarithmic function.
02

Differentiate the Natural Logarithm

Use the differentiation rule for the natural logarithm: \(\frac{d}{dx}[\ln|u|] = \frac{1}{u} \cdot \frac{du}{dx}\) where \(u = x^3 - 7x^2 - 3\). The derivative of \(\ln|u|\) is then \(\frac{1}{x^3 - 7x^2 - 3} \cdot \frac{d}{dx}[x^3 - 7x^2 - 3]\).
03

Differentiate the Inside Function

Differentiate the expression \(x^3 - 7x^2 - 3\) with respect to \(x\). This gives: \(\frac{d}{dx}[x^3 - 7x^2 - 3] = 3x^2 - 14x\).
04

Apply the Chain Rule

Substitute the derivative of the inside function into the expression from Step 2: \[ \frac{dy}{dx} = \frac{1}{x^3 - 7x^2 - 3} \cdot (3x^2 - 14x) \].
05

Simplify the Expression

The expression for the derivative is: \( \frac{dy}{dx} = \frac{3x^2 - 14x}{x^3 - 7x^2 - 3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Chain Rule
The Chain Rule is a fundamental principle in calculus. It helps us find the derivative of composite functions. When you have a function within another function, the Chain Rule is the tool you'll need.
To grasp the Chain Rule, imagine you have a function like \( y = f(g(x)) \), where \( f \) and \( g \) are both functions of \( x \). To differentiate, you first find the derivative of the outer function \( f \) while keeping the inner function \( g(x) \) unchanged. Then, multiply this by the derivative of the inner function \( g(x) \.\) This is the formula:
  • Step 1: Take the derivative of the outer function, keeping the inner function the same.
  • Step 2: Multiply by the derivative of the inner function.
When these steps are put together, you correctly apply the Chain Rule! In this exercise, we started with the outer function \( \ln|u| \) and applied the Chain Rule to accurately find its derivative.
Understanding the Natural Logarithm Derivative
The natural logarithm, denoted as \( \ln \), is a special logarithm with the base \( e \,\) where \( e \) is an irrational constant approximately equal to 2.71828.
When differentiating a natural logarithm, there’s a special rule to remember. For a function \( u(x) \,\) if you want to find the derivative of \( \ln|u(x)| \,\) the rule is:
  • The derivative is \( \frac{1}{u(x)} \).
  • Then multiply by \( \frac{d}{dx}[u(x)] \).
This is because \( \ln(x) \) has the unique property where \( \frac{d}{dx}[\ln|u|] = \frac{1}{u} \cdot \frac{du}{dx} \.\)
In our problem, the expression inside the logarithm, \( x^3 - 7x^2 - 3 \,\) is just \( u \). By applying this rule, we started with finding \( \frac{1}{u} \) and then multiplied it by the derivative of \( u \,\) which turned out to be \( 3x^2 - 14x \). This results in the derivative of the entire expression.
Mastering Calculus Exercises
Calculus exercises often involve applying multiple rules and concepts. Here, we combined different methods to find the derivative of a complex function:
  • First, we identified the structure of the function, noticing it involved a natural logarithm.
  • Then, we applied the Chain Rule, which is crucial for composite functions, by treating the logarithm's base as the outer function and the polynomial as the inner function.
  • The derivative of the logarithm required a precise approach, using its specific derivative rule.
  • Finally, the solution involved simplifying the expression into a single, manageable derivative.
Working through such exercises builds your skills in recognizing which calculus rules to apply and in structuring your approach to solve any function.
Practicing these exercises enhances your understanding and strengthens your integrative thinking for tackling multi-step calculus problems."

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Most popular questions from this chapter

(a) Show that \(\lim _{x \rightarrow \pi / 2}(\pi / 2-x) \tan x=1\). (b) Show that $$\lim _{x \rightarrow \pi / 2}\left(\frac{1}{\pi / 2-x}-\tan x\right)=0$$ (c) It follows from part (b) that the approximation $$\tan x \approx \frac{1}{\pi / 2-x}$$ (c) It follows from part (b) that the approximation $$\tan x \approx \frac{1}{\pi / 2-x}$$ should be good for values of \(x\) near \(\pi / 2 .\) Use a calculator to find tan \(x\) and \(1 /(\pi / 2-x)\) for \(x=1.57 ;\) compare the results.

A particle is moving along the curve \(16 x^{2}+9 y^{2}=144\) Find all points \((x, y)\) at which the rates of change of \(x\) and y with respect to time are equal. I Assume that \(d x / d t\) and dy/dt are never both zero at the same point. \(]\)

Find the limit. $$\lim _{x \rightarrow+\infty}(\sqrt{x^{2}+x}-x)$$

(a) Use a CAS to show that if \(k\) is a positive constant, then $$\lim _{x \rightarrow+\infty} x\left(k^{1 / x}-1\right)=\ln k$$ (b) Confirm this result using L'Hôpital's rule. [Hint: Express the limit in terms of \(t=1 / x .]\) (c) If \(n\) is a positive integer, then it follows from part (a) with \(x=n\) that the approximation $$n(\sqrt[n]{k}-1) \approx \ln k$$ should be good when \(n\) is large. Use this result and the square root key on a calculator to approximate the values of \(\ln 0.3\) and \(\ln 2\) with \(n=1024,\) then compare the values obtained with values of the logarithms generated directly from the calculator. [Hint: The \(n\) th roots for which \(n\) is a power of 2 can be obtained as successive square roots.]

Use implicit differentiation to find the specified derivative. $$y=\sin x: d x / d y$$

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