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In Exercises find \(d y / d x\). $$y=e^{\left(x-e^{3 x}\right)}$$

Short Answer

Expert verified
\( \frac{dy}{dx} = e^{x-e^{3x}}(1 - 3e^{3x}) \)

Step by step solution

01

Identify the Outer Function

The outer function in this expression is the exponential function, specifically, its base is the natural number: \( y = e^{u} \) where \( u = x - e^{3x} \). This means \( y = e^{x-e^{3x}} \).
02

Differentiate the Outer Function

Use the chain rule to differentiate with respect to \( u \):\[\frac{d}{du}e^{u} = e^{u}\]Thus, the derivative of the outer function is:\[\frac{dy}{du} = e^{x-e^{3x}}\]
03

Differentiate the Inner Function

To apply the chain rule, differentiate the inner function \( u = x - e^{3x} \) with respect to \( x \):\[\frac{du}{dx} = \frac{d}{dx}(x) - \frac{d}{dx}(e^{3x})\]First function (\( x \)) differentiates to 1:\[\frac{d}{dx}(x) = 1\]Second function (\( e^{3x} \)) differentiates using the chain rule:\[\frac{d}{dx}(e^{3x}) = 3e^{3x}\]Therefore,\[\frac{du}{dx} = 1 - 3e^{3x}\]
04

Apply the Chain Rule

Now apply the chain rule to find \( \frac{dy}{dx} \):\[\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} = e^{x-e^{3x}}(1 - 3e^{3x})\]
05

Simplify the Expression

Combine the results from the differentiations:\[\frac{dy}{dx} = e^{x-e^{3x}}(1 - 3e^{3x})\]Thus, the derivative of \( y = e^{x-e^{3x}} \) with respect to \( x \) is:\[\frac{dy}{dx} = e^{x-e^{3x}}(1 - 3e^{3x})\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
In calculus, the chain rule is a powerful tool used to compute the derivative of a composite function. A composite function is essentially a function within another function. The chain rule helps us differentiate such functions by expressing the derivative of the outer function times the derivative of the inner function.

For instance, if we have a composite function of the form \( y = f(g(x)) \), the chain rule states that to find the derivative \( \frac{dy}{dx} \), we multiply the derivative of the outer function \( f' \) with respect to the inner function \( g \), by the derivative of the inner function \( g' \) with respect to \( x \).

The formula is:
  • \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \)

This rule is crucial in solving problems involving chains of functions, simplifying the process significantly.
Exponential Function
An exponential function is one where a constant base is raised to a variable exponent. It's commonly expressed in the form \( y = a^x \), where \( a \) is a positive constant. The exponential function with base \( e \) (approximately 2.718) is particularly important in calculus. Denoted by \( e^x \), it is a natural exponential function due to its unique mathematical properties.

This function's distinctive feature is that its rate of growth is proportional to its current value. This means that the derivative of \( e^x \) is itself:
  • \( \frac{d}{dx}(e^x) = e^x \)

This property is invaluable, making calculations involving exponential growth or decay straightforward and efficient.
When dealing with more complex expressions like \( e^{x-e^{3x}} \), the chain rule comes into play. We treat \( x-e^{3x} \) as the inner function \( u \), thus allowing us to handle the composite nature smoothly.
Derivative Calculation
Calculating derivatives is a foundational aspect of calculus, crucial for understanding the rate at which functions change. In essence, it provides the slope of the tangent line to a curve at any given point. To calculate the derivative, different rules are applied depending on the nature of the function involved.

In this context, we deal with exponential functions alongside the chain rule. The process involves several steps:
  • First, identify the outer function and its derivative. This is typically straightforward for simple functions like \( e^u \), whose derivative remains \( e^u \).
  • Secondly, focus on the inner function, differentiating it with respect to \( x \). This part might involve further sub-differentiations, especially if it includes another composite function.

For our exercise, the inner function \( u = x - e^{3x} \) required us to further explore its components using the chain rule. This results in calculating the derivatives like \( \frac{d}{dx}(e^{3x}) = 3e^{3x} \).

Finally, combine the results:
  • Multiply the derivative of the outer function by the derivative of the inner function to get the final derivative, which in our case is \( e^{x-e^{3x}}(1 - 3e^{3x}) \).

The careful step-by-step approach ensures accurate results, particularly in more complicated functions.

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Most popular questions from this chapter

(a) Find the error in the following calculation: $$\begin{aligned}\lim _{x \rightarrow 1} \frac{x^{3}-x^{2}+x-1}{x^{3}-x^{2}} &=\lim _{x \rightarrow 1} \frac{3 x^{2}-2 x+1}{3 x^{2}-2 x} \\\&=\lim _{x \rightarrow 1} \frac{6 x-2}{6 x-2}=1\end{aligned}$$ (b) Find the correct answer.

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