/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A function \(f\) and a value of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A function \(f\) and a value of \(x_{0}\) are given. (a) Find the slope of the tangent to the graph of \(f\) at a general point \(x_{0}\) (b) Use the result in part (a) to find the slope of the tangent line at the given value of \(x_{0}\) $$f(x)=x^{2}+3 x+2 ; x_{0}=2$$

Short Answer

Expert verified
The slope of the tangent line at \( x_0 = 2 \) is 7.

Step by step solution

01

Differentiate the function

To find the slope of the tangent, we first need to differentiate the function. The given function is \( f(x) = x^2 + 3x + 2 \). The derivative \( f'(x) \) will give us the slope of the tangent at any point \( x \). Compute \( f'(x) = \frac{d}{dx}(x^2 + 3x + 2) \).
02

Apply the Power Rule

Apply the power rule to differentiate each term: for \( x^2 \), the derivative is \( 2x \); for \( 3x \), the derivative is \( 3 \); and for the constant \( 2 \), the derivative is \( 0 \). Thus, \( f'(x) = 2x + 3 \).
03

Find the Slope at the General Point

The result from Step 2, \( f'(x) = 2x + 3 \), represents the slope of the tangent line at any general point \( x \).
04

Substitute the Given Value of \( x_0 \)

To find the slope at \( x_0 = 2 \), substitute \( x = 2 \) into the derivative. Calculate \( f'(2) = 2(2) + 3 \).
05

Calculate the Specific Slope

Perform the arithmetic operation: \( f'(2) = 4 + 3 = 7 \). Thus, the slope of the tangent line at \( x_0 = 2 \) is 7.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Tangent Lines
A tangent line is a straight line that just grazes a curve at a particular point without crossing it. It represents the direction the curve is taking at that point. Imagine a curve, like a hill, and placing a straight ruler on it so that the ruler only touches the curve at one point. That line along the ruler is your tangent line.
  • The point where the tangent touches the curve is called the point of tangency.
  • The slope of this tangent line tells us the rate of change of the function at that specific point.
  • Tangent lines are crucial in calculus because they provide linear approximations to functions.
The Power Rule in Differentiation
Differentiation is the process of finding the derivative of a function, which essentially gives us the slope of the function at any point. The power rule is a handy technique for differentiation, especially for simple polynomials. It's a quick method to find derivatives of terms like \( x^n \).
For a function like \( x^n \), apply the power rule by:
  • Bringing down the exponent as a coefficient in front of \( x \).
  • Subtracting one from the original exponent.
For example, when differentiating \( x^2 \), you use the power rule:
  • Bring down the 2 to get \( 2x \).
  • Now the exponent on \( x \) is reduced by one.
The power rule makes finding the derivatives faster, like in the function \( f(x) = x^2 + 3x + 2 \) where each term is quickly differentiated to find the slope function \( f'(x) = 2x + 3 \).
Calculating the Slope of the Tangent
The slope of the tangent at a specific point tells us how steep the curve is at that spot. For a given function, the derivative represents a formula that provides the slope of the tangent for any \( x \). By plugging in the point of interest, we find the slope at that point.
For the function \( f(x)=x^2+3x+2 \), the derivative \( f'(x) = 2x + 3 \) was calculated using the power rule. This derivative gives us a way to find the slope of the tangent line at any point on the function.
  • To find the slope at \( x_0 = 2 \), substitute \( x = 2 \) into \( f'(x) \).
  • This results in the calculation: \( f'(2) = 2(2) + 3 = 7 \).
  • Therefore, the slope of the tangent line at \( x = 2 \) is 7.
This slope tells us that the instant rate of change or the steepness of the curve at \( x = 2 \) is 7. This means for a small step to the right on the curve, the function's output will increase at 7 times that step.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.