Chapter 3: Problem 36
find \(d y / d x\) $$y=\left(\frac{1+x^{2}}{1-x^{2}}\right)^{17}$$
Short Answer
Expert verified
The derivative is \(\frac{68x (1 + x^2)^{16}}{(1 - x^2)^{18}}\).
Step by step solution
01
Identify the Derivative Type
Since the function is in the form of a composite function, we need to use the chain rule to differentiate it. The outer function is a power function and the inner function is a rational function.
02
Apply the Chain Rule
According to the chain rule, if you have a composite function like \(f(g(x))\), then the derivative is \((f(g(x)))' = f'(g(x)) \cdot g'(x)\). Here, \(f(u) = u^{17}\) and \(u = \frac{1 + x^2}{1 - x^2}\).
03
Differentiate the Outer Function
Differentiate \(f(u) = u^{17}\) with respect to \(u\). The derivative is \(17u^{16}\).
04
Differentiate the Inner Function
Differentiate \(u = \frac{1 + x^2}{1 - x^2}\) using the quotient rule. The formula for the quotient rule is \((\frac{v}{w})' = \frac{v'w - vw'}{w^2}\), where \(v = 1 + x^2\) and \(w = 1 - x^2\).
05
Calculate the Derivative of the Inner Function
Using the quotient rule, find \(v' = 2x\) and \(w' = -2x\). Therefore, \(u' = \frac{(2x)(1 - x^2) - (1 + x^2)(-2x)}{(1 - x^2)^2}\).
06
Simplify the Derivative of the Inner Function
Simplify \(u' = \frac{2x - 2x^3 + 2x + 2x^3}{(1 - x^2)^2} = \frac{4x}{(1 - x^2)^2}\).
07
Combine the Results to Find the Final Derivative
Now plug in the derivatives into the chain rule result: \(\frac{d}{dx}(y) = 17u^{16} \cdot u' = 17 \left(\frac{1 + x^2}{1 - x^2}\right)^{16} \cdot \frac{4x}{(1 - x^2)^2}\).
08
Final Simplification of the Derivative
Simplify the expression: \(\frac{d y}{d x} = \frac{68x (1 + x^2)^{16}}{(1 - x^2)^{18}}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus that helps us differentiate composite functions. A composite function is created when one function is applied to the result of another function, written as \(f(g(x))\). To find the derivative of such a function, the chain rule breaks it down into two parts: the derivative of the outer function evaluated at the inner function, and the derivative of the inner function itself.
Consider our function \(y = \left(\frac{1+x^{2}}{1-x^{2}}\right)^{17}\), where the outer function is \(u^{17}\) and the inner function is \(u = \frac{1+x^2}{1-x^2}\). According to the chain rule:
Consider our function \(y = \left(\frac{1+x^{2}}{1-x^{2}}\right)^{17}\), where the outer function is \(u^{17}\) and the inner function is \(u = \frac{1+x^2}{1-x^2}\). According to the chain rule:
- First, differentiate the outer function \(f(u) = u^{17}\), which gives \(17u^{16}\).
- Then, multiply by the derivative of the inner function \(u\), which we need to calculate separately.
Quotient Rule
The quotient rule is a technique used for differentiating functions that are ratios of two differentiable functions. If you have a function \(\frac{v}{w}\), the formula for its derivative is:
When applying the quotient rule:
- \(\left(\frac{v}{w}\right)' = \frac{v'w - vw'}{w^2}\)
When applying the quotient rule:
- First, find \(v' = 2x\) and \(w' = -2x\).
- Substitute into the formula to get \(u' = \frac{(2x)(1-x^2) - (1+x^2)(-2x)}{(1-x^2)^2}\).
- Simplify this expression to \(u' = \frac{4x}{(1-x^2)^2}\).
Composite Function Derivative
Differentiating a composite function requires an understanding of both the chain rule and how to handle complex inner functions. Once you've recognized a function as composite, like \(f(g(x))\), break it down using the chain rule.
For example, from our exercise, the composite function \(\left(\frac{1+x^{2}}{1-x^{2}}\right)^{17}\) consists of a rational function raised to a power. The composite nature requires us to:
For example, from our exercise, the composite function \(\left(\frac{1+x^{2}}{1-x^{2}}\right)^{17}\) consists of a rational function raised to a power. The composite nature requires us to:
- Apply the chain rule to handle the outer power function.
- Simultaneously use the quotient rule to differentiate the inner rational function.
Rational Function Derivative
A rational function is a ratio of two polynomials, like the inner function \(u = \frac{1+x^2}{1-x^2}\) in our problem. Differentiating a rational function can be tricky, but the quotient rule makes this process straightforward.
Using the quotient rule, we reached the simplified derivative expression \(u' = \frac{4x}{(1-x^2)^2}\). Understanding and correctly applying this concept is crucial as it forms the core part of the derivative in our main function.
The derivative of a rational function often involves:
Using the quotient rule, we reached the simplified derivative expression \(u' = \frac{4x}{(1-x^2)^2}\). Understanding and correctly applying this concept is crucial as it forms the core part of the derivative in our main function.
The derivative of a rational function often involves:
- Calculating the derivatives of the numerator and denominator separately.
- Applying the formula to find the overall derivative.
- Simplifying the result to make further calculations more manageable.