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Is $$f(x)=\left\\{\begin{array}{ll}\frac{\sin x}{|x|}, & x \neq 0 \\\1, & x=0\end{array}\right.$$ continuous at \(x=0 ?\)

Short Answer

Expert verified
The function \( f(x) \) is not continuous at \( x=0 \) because the limit does not exist at this point.

Step by step solution

01

Define Continuity at a Point

A function \( f(x) \) is continuous at a point \( x = c \) if the following three conditions are satisfied: 1) \( f(c) \) is defined, 2) \( \lim_{{x \to c}} f(x) \) exists, and 3) \( \lim_{{x \to c}} f(x) = f(c) \). We will check each of these for \( x = 0 \).
02

Check if \( f(0) \) is Defined

In the given piecewise function, \( f(x) = 1 \) when \( x = 0 \). Therefore, \( f(0) = 1 \), so \( f(x) \) is defined at \( x = 0 \).
03

Find \( \lim_{{x \to 0}} f(x) \)

To find the limit as \( x \) approaches 0, we focus on the definition \( f(x) = \frac{\sin x}{|x|} \) for \( x eq 0 \). The two-sided limit as \( x \to 0 \) is \[ \lim_{{x \to 0}} \frac{\sin x}{|x|} = \lim_{{x \to 0}} \frac{\sin x}{x} \left(\text{from the positive side}\right) \text{and } -\lim_{{x \to 0}} \frac{\sin x}{x} \left(\text{from the negative side}\right). \]
04

Evaluate the Limit \( \lim_{{x \to 0}} \frac{\sin x}{x} \)

We know from standard limit results that \( \lim_{{x \to 0}} \frac{\sin x}{x} = 1 \). Therefore, from the right, \( \lim_{{x \to 0^+}} \frac{\sin x}{|x|} = 1 \), and from the left, \( \lim_{{x \to 0^-}} \frac{\sin x}{|x|} = -1 \) because \( |x| = -x \) for negative \( x \).
05

Determine if \( \lim_{{x \to 0}} f(x) \) Exists

The two-sided limit does not exist because the right-hand and left-hand limits are not equal (\( 1 \) and \(-1\), respectively). Hence, \( \lim_{{x \to 0}} f(x) \) does not exist.
06

Conclusion on Continuity at \( x = 0 \)

Since the condition \( \lim_{{x \to 0}} f(x) = f(0) \) does not hold due to the non-existence of the limit, \( f(x) \) is not continuous at \( x = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Functions
Piecewise functions are a type of function that are defined by different expressions or formulas depending on the input value. In simpler terms, it’s like a function that behaves differently in different parts of its domain. Consider it as a set of small functions clumped together, each piece active over a specific interval or range:
  • These functions often have specific rules for different sections of the domain.
  • The boundary points are especially important to check for continuity.
In our exercise, the function is defined as \( f(x) = \frac{\sin x}{|x|} \) when \( x eq 0 \), and equals 1 when \( x = 0 \).
This function changes its rule at \( x = 0 \), which creates a key point where continuity needs to be carefully evaluated. Understanding the behavior at different sections of the domain is crucial for analyzing functions like this one.
Limit of a Function
The limit of a function describes the behavior of the function as the input approaches a certain value. The limit is essentially what the function's output gets closer to as the input value approaches a specified point.
  • It tells us how the function behaves as we near a particular point.
  • A key concept for determining whether a function is continuous at a point.
In our problem, to check the continuity of \( f(x) \) at \( x = 0 \), we need to evaluate \( \lim_{{x \to 0}} f(x) \). This limit will show whether the function smoothly transitions through \( x = 0 \) or if there is a jump or undefined behavior.
Limits are fundamental in calculus as they allow for analysis of points that cannot be evaluated simply by substitution, like when dealing with piecewise functions.
Two-Sided Limits
Two-sided limits consider the behavior of a function as the input approaches a specific point from both the left and the right. For a limit at a point to exist, the function needs to approach the same value from either side of that point.
  • The left-hand limit considers values approaching from the negative side.
  • The right-hand limit considers values coming in from the positive side.
In our exercise, determining the two-sided limit of \( f(x) \) as \( x \) approaches 0 is crucial. From the positive side, the limit is \( 1 \), while from the negative side, it is \( -1 \).
Because these two results are not equal, the overall two-sided limit does not exist when \( x=0 \). This nonexistence of a consistent value signifies a break in the function's continuity at that point.

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