Chapter 2: Problem 28
Find the limits. $$\lim _{x \rightarrow 0} \frac{x}{\cos \left(\frac{1}{2} \pi-x\right)}$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 2: Problem 28
Find the limits. $$\lim _{x \rightarrow 0} \frac{x}{\cos \left(\frac{1}{2} \pi-x\right)}$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Find $$\lim _{x \rightarrow \pi / 4} \frac{\tan x-1}{x-\pi / 4}$$
Find the limits. $$\lim _{x \rightarrow 0} \frac{\tan 7 x}{\sin 3 x}$$
Find the limits. $$\lim _{\theta \rightarrow 0} \frac{\sin 3 \theta}{\theta}$$
Find the points of discontinuity, if any. $$f(x)=\left\\{\begin{array}{ll}2 x+3, & x \leq 4 \\ 7+\frac{16}{x}, & x>4\end{array}\right.$$
Given that $$\lim _{x \rightarrow a} f(x)=2, \quad \lim _{x \rightarrow a} g(x)=-4, \quad \lim _{x \rightarrow a} h(x)=0$$ find the limits that exist. If the limit does not exist. explain why. (a) \(\lim _{x \rightarrow a}[f(x)+2 g(x)]\) (b) \(\lim _{x \rightarrow a}[h(x)-3 g(x)+1]\) (c) \(\lim _{x \rightarrow a}[f(x) g(x)]\) (d) \(\lim _{x \rightarrow a}[g(x)]^{2}\) (e) \(\lim _{x \rightarrow a} \sqrt[3]{6+f(x)}\) (f) \(\lim _{x \rightarrow a} \frac{2}{g(x)}\) (g) \(\lim _{x \rightarrow a} \frac{3 f(x)-8 g(x)}{h(x)}\) (h) \(\lim _{x \rightarrow a} \frac{7 g(x)}{2 f(x)+g(x)}\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.