/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Express the parametric equations... [FREE SOLUTION] | 91Ó°ÊÓ

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Express the parametric equations as a single vector equation of the form \(\mathbf{r}=x(t) \mathbf{i}+y(t) \mathbf{j}\) or \(\mathbf{r}=x(t) \mathbf{i}+y(t) \mathbf{j}+z(t) \mathbf{k}\)\ $$x=3 \cos t, y=t+\sin t$$

Short Answer

Expert verified
\(\mathbf{r}(t) = 3\cos t\, \mathbf{i} + (t + \sin t)\, \mathbf{j}\).

Step by step solution

01

Understanding the Problem

We are given two parametric equations: \( x = 3 \cos t \) and \( y = t + \sin t \). Our goal is to express these parametric equations as a single vector equation.
02

Identify Components of the Vector Equation

To express the parametric equations as a vector equation of the form \( \mathbf{r} = x(t) \mathbf{i} + y(t) \mathbf{j} \), we identify \( x(t) = 3 \cos t \) and \( y(t) = t + \sin t \).
03

Formulate Vector Equation

Using the components identified, we can write the vector equation: \( \mathbf{r}(t) = 3 \cos t \mathbf{i} + (t + \sin t) \mathbf{j} \).
04

Verify the Vector Equation

Check that the vector equation correctly represents the parametric equations. \( x(t) = 3 \cos t \) corresponds to the \( \mathbf{i} \) component, and \( y(t) = t + \sin t \) corresponds to the \( \mathbf{j} \) component of the vector equation, verifying the solution is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a powerful mathematical tool used to describe a set of related quantities. In simple terms, they define a relationship between variables using a third variable, often called a parameter. For example, consider two parametric equations: \( x = f(t) \) and \( y = g(t) \). Here, \( t \) is the parameter, and \( f(t) \) and \( g(t) \) express \( x \) and \( y \) as functions of \( t \). This method is particularly useful for modeling curves, where the standard \( y=f(x) \) form does not suffice.

When using parametric equations:
  • Each parameter represents a different aspect of the system, allowing complex shapes and paths to be defined.
  • They can help find intersections, tangents, and lengths of curves in calculus.
  • Often used in physics and engineering to describe motion or paths.
Vector Equation
Vector equations combine parametric equations by using vectors to express them as a single statement. In the context of our example, each function, \( x(t) \) and \( y(t) \), becomes a component of a vector. That vector represents a point or a moving particle's position in a two-dimensional space. So, for our given equations, we express them in the form \( \mathbf{r}(t) = x(t) \mathbf{i} + y(t) \mathbf{j} \).

Here's the breakdown:
  • \( \mathbf{i} \) and \( \mathbf{j} \) are unit vectors pointing in the direction of the x-axis and y-axis, respectively.
  • The functions \( x(t) = 3 \cos t \) and \( y(t) = t + \sin t \) tell us how the x and y coordinates change as \( t \) varies.
  • This form captures the trajectory of a point in the plane as \( t \) changes.
Vector equations make understanding and visualizing the movement described by parametric equations easier.
Trigonometric Functions
Trigonometric functions are a category of mathematical functions crucial in studying cycles and periodic phenomena. Handling periodic behavior, like that shown in \( x = 3 \cos t \), is a classic application of these functions. Let's break down their relevance:
  • They are used to describe oscillations, rotations, and waves, essential in physics and engineering.
  • In terms of parametric equations, trig functions help depict curved paths, such as circles or spirals.
  • Functions like \( \cos t \) repeat values over intervals, making them predictable for cyclical movements.
Amidst calculus problem-solving, understanding how these functions operate can simplify solving complex problems involving periodicity.
Calculus Problem Solving
Calculus problem solving revolves around using derivatives and integrals to model and interpret real-world situations. Parametric equations and trigonometric functions are tools often employed in these scenarios. They allow for a more dynamic modeling of motion and change. Whether tracking a particle's motion along a path or analyzing forces in engineering, calculus provides the framework.

To effectively solve calculus problems:
  • Understand the relationships between the parametric expressions and the real-world phenomena they represent.
  • Employ derivatives to study the rate of change, such as analyzing the velocity from displacement.
  • Use vectors to simplify multidimensional problems, allowing a systematic approach to complex movement simulations.
Mastery in calculus involves knowing how and when to apply these mathematical tools effectively.

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