/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Solve the differential equation,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the differential equation, and then use a graphing utility to generate the integral curves for \(C=-2,-1,0,1,2\) $$\left(x^{2}+4\right) \frac{d y}{d x}+x y=0$$

Short Answer

Expert verified
Solution: \(|y| = C(x^2 + 4)^{-1/2}\) with integral curves for \(C = -2, -1, 0, 1, 2\).

Step by step solution

01

Separate Variables

The given differential equation is \((x^2 + 4) \frac{dy}{dx} + xy = 0\). We first rearrange it to separate the variables.\[(x^2 + 4) \frac{dy}{dx} = -xy\]Then,\[\frac{dy}{y} = -\frac{x}{x^2 + 4} dx\]This separates the variables.
02

Integrate Both Sides

Now, we integrate both sides to find the solution. The left side is the integral of \(\frac{dy}{y}\), and the right side is the integral of \(-\frac{x}{x^2 + 4}\) with respect to \(x\):\[\int \frac{dy}{y} = \int -\frac{x}{x^2 + 4} dx\]The solution to the left side is \(\ln|y| + C_1\). To integrate the right side, let \(u = x^2 + 4\), then \(du = 2x dx\), so \(x dx = \frac{1}{2} du\). The integral becomes:\[-\frac{1}{2} \int \frac{1}{u} du = -\frac{1}{2} \ln|u| + C_2\]Substitute back \(u = x^2 + 4\):\[-\frac{1}{2} \ln|x^2 + 4| + C_2\].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
Separation of variables is a fundamental technique used in solving differential equations, particularly useful when the equation can be written in a form that allows the variables to be distinctly separated on opposite sides of the equality sign. In the context of the original exercise, we start with the equation \((x^2 + 4) \frac{dy}{dx} + xy = 0\). The goal is to manipulate this equation into such a form where all the terms involving the variable \(y\), and its differential \(dy\), are on one side, while terms involving the variable \(x\), and its differential \(dx\), are on the other side. This process leads us to:\[\frac{dy}{y} = -\frac{x}{x^2 + 4} dx\].
This separation makes the problem more tractable, allowing us to integrate each side independently. Key steps in separation of variables often include rearranging terms, multiplying or dividing through by constants or expressions, and ensuring that corresponding differences are accounted for on the appropriate side.
Integration
Integration is the process of finding an integral, which can be thought of as the opposite of differentiation. In solving differential equations, once we have separated the variables, we integrate both sides to find the general solution of the differential equation. For our exercise, we have two integrals to solve: \(\int \frac{dy}{y}\) and \(\int -\frac{x}{x^2 + 4} dx\).
The integral \(\int \frac{dy}{y}\) is straightforward and results in \(\ln|y|\).
  • The integral of \(-\frac{x}{x^2 + 4}\), however, requires a substitution to simplify the integration process.
  • Substitution is a technique where we set \(u = x^2 + 4\), leading to \(du = 2x dx\).
  • This substitution transforms \(x dx\) into \(\frac{1}{2} du\), simplifying the integral to \(-\frac{1}{2} \int \frac{1}{u} du\).
By calculating these integrals, we arrive at a solution expressed in logarithmic form, representative of the general form of the function described by the differential equation.
Integral Curves
Integral curves are essential in visualizing the solutions to differential equations. They represent the family of solutions of differential equations graphically by plotting them on a coordinate system. In our exercise, after finding the general solution \(\ln|y| = -\frac{1}{2} \ln|x^2 + 4| + C\), we consider the constant \(C\) to express different particular solutions or integral curves.
  • Each value of \(C\) will yield a unique curve, moving the integral curve up or down the graph.
  • For example, setting \(C = -2, -1, 0, 1, 2\) generates different curves that show how the solution behaves under various conditions.
Graphical representation with these integral curves can help understand the behavior of the differential equation over the range of \(x\)-values, illustrating, for instance, growth or decay depending on the sign and magnitude of \(C\).
Substitution Method
The substitution method is a powerful technique used to simplify integrals that are not easily solvable in their original form. It involves replacing a variable or expression with another one that makes the integral more manageable. In our differential equation, to integrate \(-\frac{x}{x^2 + 4} dx\), we use substitution as follows:
We let \(u = x^2 + 4\), turning our differential \(du\) into \(2x dx\). This is crucial because it aligns the differential form with the terms we have, achieving \(x dx = \frac{1}{2} du\), allowing the troublesome integral to transform into a simpler one involving \(\frac{1}{u}\).
  • This type of substitution is particularly helpful when dealing with rational functions or polynomials under a root or within a logarithmic function.
  • Substitution often requires finding a derivative to replace the differential in the integral, reshaping the integral to a friendlier format.
After substitution and integrating, you substitute back the original variable to ensure the solution is expressed in terms of the initial variables, thus preserving the contextual nature of the problem. This method reduces complexity and aids in solving difficult integrals efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the differential equation by separation of variables. Where reasonable, express the family of solutions as explicit functions of \(x\) \(\left(1+x^{4}\right) \frac{d y}{d x}=\frac{x^{3}}{y}\)

(a) There is a trick, called the Rule of \(70,\) that can be used to get a quick estimate of the doubling time or halflife of an exponential model. According to this rule. the doubling time or half-life is roughly 70 divided by the percentage growth or decay rate. For example, we showed in Example 2 that with a continued growth rate of \(2 \%\) per year the world population would double every 35 years. This result agrees with the Rule of 70 . since \(70 / 2=35 .\) Explain why this rule works. (b) Use the Rule of 70 to estimate the doubling time of a population that grows exponentially at a rate of \(1 \%\) per year. (c) Use the Rule of 70 to estimate the half-life of a population that decreases exponentially at a rate of \(3.5 \%\) per hour. (d) Use the Rule of 70 to estimate the growth rate that would be required for a population growing exponentially to double every 10 years.

(a) Show that the solution of the initial-value problem $$ \begin{array}{c} y^{\prime}=e^{-x^{2}}, y(0)=0 \text { is } \\ y(x)=\int_{0}^{r} e^{-t^{2}} d t \end{array} $$ (b) Use Euler's Method with \(h=0.05\) to approximate the value of $$ y(1)=\int_{0}^{1} e^{-t^{2}} d t $$ and compare the answer to that produced by a calculating utility with a numerical integration capability.

Solve the differential equation by the method of integrating factors and by separation of variables, and confirm that the two solutions are the same. (a) \(\frac{d y}{d x}-4 x y=0\) (b) \(\frac{d y}{d t}+y=0\)

Solve the initial-value problem by any method. \frac{d y}{d t}=\frac{2 t+1}{2 y \pm 2}, \quad y(0)=-1

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.