Chapter 1: Problem 62
Find $$\frac{f(x+h)-f(x)}{h}$$ and simplify as much as possible. $$f(x)=1 / x^{2}$$
Short Answer
Expert verified
\( \frac{-2x-h}{x^2(x+h)^2} \)
Step by step solution
01
Substitute f(x) and f(x+h) into the Expression
First, identify \( f(x) \) and \( f(x+h) \). We have \( f(x) = \frac{1}{x^2} \). Now calculate \( f(x+h) \) by replacing \( x \) with \( x+h \) in the function: \( f(x+h) = \frac{1}{(x+h)^2} \). Substitute these into the given expression: \( \frac{f(x+h) - f(x)}{h} = \frac{\frac{1}{(x+h)^2} - \frac{1}{x^2}}{h} \).
02
Simplify the Numerator
To simplify the numerator \( \frac{1}{(x+h)^2} - \frac{1}{x^2} \), first find a common denominator, which is \( x^2(x+h)^2 \). Rewrite each fraction with this common denominator: \( \frac{x^2}{x^2(x+h)^2} - \frac{(x+h)^2}{x^2(x+h)^2} = \frac{x^2 - (x+h)^2}{x^2(x+h)^2} \).
03
Expand and Simplify the Numerator
Expand \((x+h)^2\) as \(x^2 + 2xh + h^2\). Substitute back into the numerator: \(x^2 - (x^2 + 2xh + h^2) = x^2 - x^2 - 2xh - h^2\), simplifying to \(-2xh - h^2\). Thus, the expression becomes \( \frac{-2xh - h^2}{x^2(x+h)^2} \).
04
Factor and Cancel h
Factor \( h \) out of the numerator: \( h(-2x - h) \). This gives \( \frac{h(-2x - h)}{x^2(x+h)^2} \). Now, cancel \( h \) in the numerator and denominator results in \( \frac{-2x - h}{x^2(x+h)^2} \).
05
Final Simplification
The expression \( \frac{-2x - h}{x^2(x+h)^2} \) is already as simplified as possible. This completes the simplification process for \( \frac{f(x+h)-f(x)}{h} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Substitution: The Basics
Function substitution is a foundational concept in calculus and algebra that helps you evaluate a function at different points. In this process, you replace the current input value of a function with another expression to compute a new output.
For example, consider the function given in the exercise: \( f(x) = \frac{1}{x^2} \). To find the function at a new point \( x+h \), substitute \( x \) with \( x+h \).
For example, consider the function given in the exercise: \( f(x) = \frac{1}{x^2} \). To find the function at a new point \( x+h \), substitute \( x \) with \( x+h \).
- Substitution: \( f(x+h) = \frac{1}{(x+h)^2} \)
- Initial Function: \( f(x) = \frac{1}{x^2} \)
Difference Quotient Simplification
The difference quotient, \( \frac{f(x+h) - f(x)}{h} \), is an essential concept in introductory calculus. It represents the average rate of change of the function \( f(x) \) over the interval \( x \) to \( x+h \). Simplifying the difference quotient gives insight into the derivative, which defines the instantaneous rate of change.To simplify, begin by substituting the computed function values, \( f(x) \) and \( f(x+h) \), into the quotient:
- \( \frac{f(x+h) - f(x)}{h} = \frac{\frac{1}{(x+h)^2} - \frac{1}{x^2}}{h} \)
- Numerator: \( \frac{x^2 - (x+h)^2}{x^2(x+h)^2} \)
Rational Expressions Simplification
Rational expressions involve fractions with polynomials in the numerator and the denominator. Simplifying these expressions can be broken into manageable steps that often involve finding a common denominator and canceling out terms when possible.To simplify a rational expression such as \( \frac{1}{(x+h)^2} - \frac{1}{x^2} \), start by identifying a common denominator. In this example, it is \( x^2(x+h)^2 \).
- Rewriting: \( \frac{x^2}{x^2(x+h)^2} - \frac{(x+h)^2}{x^2(x+h)^2} = \frac{x^2 - (x+h)^2}{x^2(x+h)^2} \)
- Expand \( (x+h)^2 \): \( x^2 + 2xh + h^2 \)
- Simplify the numerator: \( x^2 - (x^2 + 2xh + h^2) = -2xh - h^2 \)
- Final Simplification: \( \frac{-2x - h}{x^2(x+h)^2} \)