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Express the function in piecewise form without using absolute values. [Suggestion: It may help to generate the graph of the function.] (a) \(f(x)=|x|+3 x+1\) (b) \(g(x)=|x|+|x-1|\)

Short Answer

Expert verified
(a) \(f(x)=\begin{cases} 4x + 1,& x \geq 0 \\ 2x + 1,& x < 0 \end{cases}\); (b) \(g(x)=\begin{cases} 2x - 1,& x \geq 1 \\ 1,& 0 \leq x < 1 \\ 1 - 2x,& x < 0 \end{cases}\)

Step by step solution

01

Understand the Absolute Value

The absolute value function \(|x|\) is defined such that \(|x| = x\) for \(x \geq 0\) and \(|x| = -x\) for \(x < 0\). This means for any expression inside an absolute value, there are usually two cases based on the sign of the expression.
02

Analyze for (a) \(f(x)=|x|+3x+1\)

Break the function into cases based on the absolute value of \(x\):- For \(x \geq 0\), \(|x| = x\), hence \(f(x) = x + 3x + 1 = 4x + 1\).- For \(x < 0\), \(|x| = -x\), hence \(f(x) = -x + 3x + 1 = 2x + 1\).
03

Write \(f(x)\) in Piecewise Form

By combining the results from Step 2, the piecewise function for \(f(x)\) is:\[f(x) = \begin{cases} 4x + 1, & \text{if } x \geq 0 \ 2x + 1, & \text{if } x < 0 \end{cases}\]
04

Analyze for (b) \(g(x)=|x|+|x-1|\)

For \(g(x)\), consider the critical points that affect the sign of the expressions inside the absolute values: \(x = 0\) and \(x = 1\).- For \(x \geq 1\), \(|x| = x\) and \(|x-1| = x-1\), so \(g(x) = x + (x - 1) = 2x - 1\).- For \(0 \leq x < 1\), \(|x| = x\) and \(|x-1| = 1-x\), so \(g(x) = x + (1 - x) = 1\).- For \(x < 0\), \(|x| = -x\) and \(|x-1| = 1-x\), so \(g(x) = -x + (1 - x) = 1 - 2x\).
05

Write \(g(x)\) in Piecewise Form

By combining the results from Step 4, the piecewise function for \(g(x)\) is:\[g(x) = \begin{cases} 2x - 1, & \text{if } x \geq 1 \ 1, & \text{if } 0 \leq x < 1 \ 1 - 2x, & \text{if } x < 0 \end{cases}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Absolute Value Function
The absolute value function, denoted as \(|x|\), can initially seem a bit elusive but it's quite simple upon closer examination. Essentially, the absolute value of a number is its distance from zero on the number line. This means it doesn't consider whether the number is positive or negative, only how far it is from zero. For instance, the absolute value of both -5 and 5 is 5.

Mathematically, the absolute value function is expressed as:
  • |x| = x if x \( \geq \) 0
  • |x| = -x if x < 0

So for any expression within an absolute value sign, two scenarios are usually defined: one for when the expression is non-negative, and another for when it's negative. This understanding is fundamental when working with absolute values, especially in piecewise functions.
Introduction to Piecewise Notation
Piecewise notation is a clever way of representing functions that have different expressions over different intervals of their domain. Think of it as a mathematical version of an instruction manual. Depending on the "instruction," or in our case, the particular interval, the function acts differently.

When we use piecewise notation, we express our function with multiple lines, each containing a different formula or expression that is used when certain conditions (or ranges of the variable) are met.

For example, if a function changes its behavior at specific points (like zero or any critical x-values), piecewise notation helps define those changes clearly. Each segment of the function is defined alongside the specific condition under which it applies. This allows a concise representation of complex behavior without overlapping or confusion.
Step-by-Step Solutions for Clarity
Step-by-step solutions break down the process of solving a problem into manageable parts, making it much clearer and easier to follow. In mathematics, this approach is especially helpful when dealing with complex functions or expressions like piecewise and absolute value functions.

By dividing the problem into steps, we can individually analyze the elements involved. For example, when transforming an absolute value function into a piecewise function, we first identify critical points that change how the function behaves.

Then we solve or simplify each segment independently before recombining them. This organized method ensures that no parts are overlooked and offers a thorough understanding of the entire process from start to finish.
Exploring Algebraic Expressions in Depth
Algebraic expressions are the language of algebra, consisting of numbers, variables, and arithmetic operations like addition, subtraction, multiplication, and division. These expressions can range from something as straightforward as \(3x + 2\) to more complex forms involving multiple variables and operations.

In working with piecewise functions, we often need to manipulate or simplify these algebraic expressions to fit the conditions specified by the function's piecewise nature. This could involve substituting values, factoring, or reducing expressions to make the function easier to understand or work with.

Understanding how to handle algebraic expressions is essential when defining piecewise functions, as it allows us to modify each piece of the function to accurately reflect its properties under different conditions.

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Most popular questions from this chapter

Parametric curves can be defined piecewise by using different formulas for different values of the parameter. Sketch the curve that is represented piecewise by the parametric equations $$\begin{aligned}&x=2 t, \quad y=4 t^{2} \quad\left(0 \leq t \leq \frac{1}{2}\right)\\\ &x=2-2 t, \quad y=2 t \quad\left(\frac{1}{2} \leq t \leq 1\right)\end{aligned}$$

The price for a round-trip bus ride from a university to center city is 2.00 dollars, but it is possible to purchase a monthly commuter pass for 25.00 dollars with which each round-trip ride costs an additional 0.25 dollars. (a) Find equations for the cost \(C\) of making \(x\) round-trips per month under both payment plans, and graph the equations for \(0 \leq x \leq 30\) (treating \(C\) as a continuous function of \(x\), even though \(x\) assumes only integer values). (b) How many round-trips per month would a student have to make for the commuter pass to be worthwhile?

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Graph the equation using a graphing utility. (a) \(x=y^{2}+2 y+1\) (b) \(x=\sin y,-2 \pi \leq y \leq 2 \pi\)

In Exercises \(17-20 .\) sketch the graph of the equation by translating, reflecting, compressing, and stretching the graph of \(y=1 / x\) appropriately, and then use a graphing utility to confirm that your sketch is correct. $$y=\frac{1}{x-3}$$

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