Chapter 9: Problem 57
Find the Taylor polynomial of order 4 based at 1 for \(f(x)=1 /(x+1)\).
Short Answer
Expert verified
The Taylor polynomial of order 4 based at 1 is \(\frac{1}{2} - \frac{1}{4}(x-1) + \frac{1}{9}(x-1)^2 - \frac{1}{64}(x-1)^3 + \frac{1}{640}(x-1)^4\).
Step by step solution
01
Identify the function and point of expansion
We need to find the Taylor polynomial of order 4 for the function \(f(x) = \frac{1}{x+1}\) based at \(x = 1\).
02
Calculate the first derivative of the function
The first derivative of \(f(x) = \frac{1}{x+1}\) is \(f'(x) = -\frac{1}{(x+1)^2}\).
03
Calculate the higher-order derivatives
Calculate the next derivatives. For the second derivative, \(f''(x) = \frac{2}{(x+1)^3}\). For the third derivative, \(f'''(x) = -\frac{6}{(x+1)^4}\). For the fourth derivative, \(f^{(4)}(x) = \frac{24}{(x+1)^5}\).
04
Evaluate the derivatives at the point of expansion
Evaluate each derivative at \(x=1\). For \(f(1) = \frac{1}{2}\), \(f'(1) = -\frac{1}{4}\), \(f''(1) = \frac{2}{27}\), \(f'''(1) = -\frac{3}{64}\), and \(f^{(4)}(1) = \frac{3}{128}\).
05
Formulate the Taylor polynomial
The Taylor series of a function \(f(x)\) based at \(x=a\) is given by \(\sum_{n=0}^{N} \frac{f^{(n)}(a)}{n!}(x-a)^n\). Substitute the coefficients and calculate: \ \[ P_4(x) = f(1) + f'(1)(x-1) + \frac{f''(1)}{2!}(x-1)^2 + \frac{f'''(1)}{3!}(x-1)^3 + \frac{f^{(4)}(1)}{4!}(x-1)^4 \] \ \[ P_4(x) = \frac{1}{2} - \frac{1}{4}(x-1) + \frac{1}{9}(x-1)^2 - \frac{1}{64}(x-1)^3 + \frac{1}{640}(x-1)^4 \].
06
Simplify and present the solution
The fourth-order Taylor polynomial for \(f(x) = \frac{1}{x+1}\) based at \(x = 1\) is: \ \[ P_4(x) = \frac{1}{2} - \frac{1}{4}(x-1) + \frac{1}{9}(x-1)^2 - \frac{1}{64}(x-1)^3 + \frac{1}{640}(x-1)^4 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series
A Taylor series is an incredibly useful mathematical tool that lets us represent complex functions as infinite sums of simpler polynomial terms. The idea is to "expand" a function around a specific point by using derivatives. This approach allows us to approximate a given function by altering the order of its polynomial terms.
The formula for a Taylor series at a base point \( a \) for a function \( f(x) \) is:
For instance, in the exercise, a fourth-order Taylor polynomial was found. This polynomial involves calculating up to the fourth derivative of the function \( \frac{1}{x+1}\) and evaluating them at \( x=1 \). The more terms you include in a Taylor series, the closer it approaches the actual function's value.
The formula for a Taylor series at a base point \( a \) for a function \( f(x) \) is:
- \( f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n \)
For instance, in the exercise, a fourth-order Taylor polynomial was found. This polynomial involves calculating up to the fourth derivative of the function \( \frac{1}{x+1}\) and evaluating them at \( x=1 \). The more terms you include in a Taylor series, the closer it approaches the actual function's value.
derivatives
Derivatives are fundamental in calculus, representing the rate at changes occur in a function. They measure how fast a function's value is changing at any point and are essential for constructing Taylor series.
To find Taylor polynomials, we calculate successive derivatives of a function. Each derivative gives us information about the function's curvature and behavior at a given point. For the function \( f(x) = \frac{1}{x+1} \), we need its first four derivatives to craft a fourth-order Taylor polynomial.
To find Taylor polynomials, we calculate successive derivatives of a function. Each derivative gives us information about the function's curvature and behavior at a given point. For the function \( f(x) = \frac{1}{x+1} \), we need its first four derivatives to craft a fourth-order Taylor polynomial.
- First derivative: \( f'(x) = -\frac{1}{(x+1)^2} \)
- Second derivative: \( f''(x) = \frac{2}{(x+1)^3} \)
- Third derivative: \( f'''(x) = -\frac{6}{(x+1)^4} \)
- Fourth derivative: \( f^{(4)}(x) = \frac{24}{(x+1)^5} \)
order 4 polynomial
An order 4 polynomial, also known as a quartic polynomial, includes terms up to \((x-a)^4\). In the context of Taylor polynomials, the order determines how many terms and derivatives are used to approximate a function.
In the exercise provided, an order 4 Taylor polynomial for the function \( f(x) = \frac{1}{x+1} \) was constructed using calculations up to the fourth derivative. The resulting polynomial is given by:
Order 4 polynomials provide a balance between complexity and approximation accuracy, offering sufficient accuracy for many practical applications without the cumbersome calculations of higher orders.
In the exercise provided, an order 4 Taylor polynomial for the function \( f(x) = \frac{1}{x+1} \) was constructed using calculations up to the fourth derivative. The resulting polynomial is given by:
- \( P_4(x) = \frac{1}{2} - \frac{1}{4}(x-1) + \frac{1}{9}(x-1)^2 - \frac{1}{64}(x-1)^3 + \frac{1}{640}(x-1)^4 \)
Order 4 polynomials provide a balance between complexity and approximation accuracy, offering sufficient accuracy for many practical applications without the cumbersome calculations of higher orders.