Chapter 9: Problem 17
Determine whether the given series converges or diverges and, if it converges, find its sum. $$1-\frac{2^{2}}{2 !}+\frac{2^{4}}{4 !}-\frac{2^{6}}{6 !}+\cdots$$
Short Answer
Expert verified
The series converges and its sum is approximately -0.4161.
Step by step solution
01
Identify the Pattern of the Series
Examine the given series: \(1 - \frac{2^2}{2!} + \frac{2^4}{4!} - \frac{2^6}{6!} + \cdots\). Each term follows the general pattern: \((-1)^n \frac{2^{2n}}{(2n)!}\), where \(n = 0, 1, 2, 3,\ldots\).
02
Recognize the Similarity to a Known Series
Notice that the series resembles the exponential function series for \(e^x\): \(e^x = \sum_{n=0}^{\infty}\frac{x^n}{n!}\). Specifically, it relates to the series expansion of \(\cos(x)\), which is \(\cos(x) = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{(2n)!}\).
03
Compare with the Cosine Series
Conclude that our series has the same form as the Taylor series expansion for \(\cos(x)\) with \(x = 2\). Therefore, the series is \(\cos(2)\).
04
Conclude Convergence and Find the Sum
Since the series matches the expansion of \(\cos(2)\) exactly, it converges to the value of \(\cos(2)\). Using a calculator, \(\cos(2) \approx -0.4161\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Series
The cosine series is a way to express the cosine function as an infinite series. This series is particularly useful because it allows us to calculate the cosine of any angle using a sum of terms. The general form of the cosine series is: \[\cos(x) = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{(2n)!}\]This formula is derived from the Taylor series expansion, where each term involves an even power of \(x\) given by \(x^{2n}\), and a factorial in the denominator \((2n)!\). The sign of each term alternates between positive and negative, represented by \((-1)^n\).
- First term: 1 (since \(x^{0}/0! = 1\))
- Second term: \(-\frac{x^2}{2!}\)
- Third term: \(+\frac{x^4}{4!}\)
Taylor Series
The Taylor series is a powerful tool in calculus and provides a polynomial approximation for functions. Named after the mathematician Brook Taylor, this series is used to represent functions as an infinite sum of terms based on the function's derivatives at a single point. The general formula for the Taylor series of a function \(f(x)\) around a point \(a\) is: \[f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots\]For the cosine function, the series is usually centered around 0 (this is known as the Maclaurin series, a special case of the Taylor series). Thus, the cosine series becomes: \[\cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots\]
- The Taylor series allows us to express functions like cosine in terms of polynomials for easier computation.
- It involves derivatives of the function evaluated at the base point.
- Used extensively in numerical methods to approximate function values.
Series Expansion
Series expansion is the process of expressing a function as an infinite sum of terms. This method is essential in calculus because it enables us to solve problems related to differential equations and approximation of functions. A series expansion turns complex functions into simpler polynomial forms that are easier to work with. This is especially beneficial in situations where direct calculation would be challenging.
- The series expansion can be finite or infinite, with the latter being more common in infinite series like the Taylor or Maclaurin series.
- Each term in the series contributes to the approximation of the function.
- Used for functions like exponentials, sines, cosines, and logarithms.