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Find the convergence set for the given power series. Hint: First find a formula for the nth term; then use the Absolute Ratio Test. \(1+x+\frac{x^{2}}{\sqrt{2}}+\frac{x^{3}}{\sqrt{3}}+\frac{x^{4}}{\sqrt{4}}+\frac{x^{5}}{\sqrt{5}}+\cdots\)

Short Answer

Expert verified
The series converges for \( x \) in \((-1, 1)\).

Step by step solution

01

Identify the nth term

The given power series is in the form: \(1 + x + \frac{x^2}{\sqrt{2}} + \frac{x^3}{\sqrt{3}} + \cdots \). We need to express the general term of this series. Let's denote this by \( a_n \), which, based on the pattern, is \( a_n = \frac{x^n}{\sqrt{n}} \).
02

Apply the Absolute Ratio Test

The Absolute Ratio Test states that a power series \( \sum a_n \) converges if \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \). First, find \( \frac{a_{n+1}}{a_n} \):\[\frac{a_{n+1}}{a_n} = \frac{\frac{x^{n+1}}{\sqrt{n+1}}}{\frac{x^n}{\sqrt{n}}} = \frac{x^{n+1}}{\sqrt{n+1}} \cdot \frac{\sqrt{n}}{x^n} = x \cdot \frac{\sqrt{n}}{\sqrt{n+1}}\]Now, take the absolute value:\[ \left| \frac{a_{n+1}}{a_n} \right| = \left| x \cdot \frac{\sqrt{n}}{\sqrt{n+1}} \right| = |x| \cdot \frac{\sqrt{n}}{\sqrt{n+1}} \]
03

Evaluate the Limit

We now need to evaluate \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \):\[ \lim_{n \to \infty} |x| \cdot \frac{\sqrt{n}}{\sqrt{n+1}} = |x| \cdot \lim_{n \to \infty} \frac{\sqrt{n}}{\sqrt{n+1}} \]As \( n \to \infty, \frac{\sqrt{n}}{\sqrt{n+1}} \to 1 \). Therefore,\[ \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = |x| \]
04

Find the Convergence Set

According to the Absolute Ratio Test, for the series to converge, the following must be true:\[ |x| < 1 \]Thus, the power series converges when \( x \) is within the interval \( (-1, 1) \). Therefore, the convergence set for the power series is \((-1, 1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Series
A power series is a crucial mathematical concept that involves an infinite sum of terms. Each term is usually composed of a coefficient and a variable raised to a power. The general form could be expressed as:
  • \( \sum_{n=0}^{\infty} c_n (x-a)^n \)
Here, \( c_n \) is the coefficient for each term, \( (x-a) \) denotes the variable and its power, and \( a \) is the center of the series.
In the given problem, the power series is written as:
  • \( 1 + x + \frac{x^2}{\sqrt{2}} + \frac{x^3}{\sqrt{3}} + \cdots \)
This is a power series centered at zero, since it includes terms of the variable \( x \) raised to various powers. Each term becomes increasingly complex, indicating a pattern where the nth term \( a_n = \frac{x^n}{\sqrt{n}} \) follows. Understanding this frame helps in identifying the convergence, which tells us where the series builds up to a finite sum.
Absolute Ratio Test
The Absolute Ratio Test is a method used to determine the convergence or divergence of a power series. It involves examining the ratio of successive terms in an absolute sense. The test states:
  • A series \( \sum a_n \) converges absolutely if \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \).
For the given series, we formulate the ratio of consecutive terms as:
  • \( \frac{a_{n+1}}{a_n} = \frac{x^{n+1}}{\sqrt{n+1}} \cdot \frac{\sqrt{n}}{x^n} \)
After simplification, this ratio is \( x \cdot \frac{\sqrt{n}}{\sqrt{n+1}} \). The absolute value result becomes \( |x| \cdot \frac{\sqrt{n}}{\sqrt{n+1}} \).
As \( n \) approaches infinity, the fraction \( \frac{\sqrt{n}}{\sqrt{n+1}} \) tends toward 1. Therefore, the limit to consider becomes \( |x| \), which is central to determining when the series converges.
Convergence Set
The convergence set of a power series is the range of values for which the series converges. For the series given, we've determined that \( \lim_{n \to \infty} |x| \cdot \frac{\sqrt{n}}{\sqrt{n+1}} = |x| \).
According to the Absolute Ratio Test, convergence happens when the final limit \( |x| < 1 \). This means the series converges absolutely in the interval \((-1, 1)\).
The convergence set is therefore the set of all \( x \) values between \(-1\) and \(1\), excluding the endpoints. This result shows that within this interval, the series will sum to a finite value, providing a useful tool for understanding function behavior near zero. The identification of a convergence set is crucial in analyzing the behavior of series and their applications in mathematical modeling.

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