/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 In Problems 13-22, use any test ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 13-22, use any test developed so far, including any from Section 9.2, to decide about the convergence or divergence of the series. Give a reason for your conclusion. $$ \sum_{k=1}^{\infty} \frac{k^{2}+1}{k^{2}+5} $$

Short Answer

Expert verified
The series diverges by the Limit Comparison Test.

Step by step solution

01

Analyze the Series Type

The given series is \( \sum_{k=1}^{\infty} \frac{k^2+1}{k^2+5} \). This is a series where each term is a rational function of \( k \). A good first step is to compare this series to a simpler series to test for convergence.
02

Consider the Dominant Terms

Observe that for large \( k \), the term \( \frac{k^2+1}{k^2+5} \) behaves similarly to \( \frac{k^2}{k^2} = 1 \). This suggests that the series behaves similarly to the harmonic series \( \sum_{k=1}^{\infty} 1 \).
03

Apply the Limit Comparison Test

To apply the Limit Comparison Test, use the series \( \sum_{k=1}^{\infty} 1 \) as a reference. Compute the limit:\[ \lim_{k \to \infty} \frac{\frac{k^2 + 1}{k^2 + 5}}{1} = \lim_{k \to \infty} \frac{k^2 + 1}{k^2 + 5} = 1. \]Since this limit is a positive finite number, and the reference series \( \sum_{k=1}^{\infty} 1 \) diverges, by the Limit Comparison Test, the original series also diverges.
04

Conclusion

Based on the Limit Comparison Test, since the series \( \sum_{k=1}^{\infty} 1 \) is divergent and \( \lim_{k \to \infty} \frac{k^2 + 1}{k^2 + 5} = 1 \), the original series \( \sum_{k=1}^{\infty} \frac{k^{2}+1}{k^{2}+5} \) also diverges.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Comparison Test
The limit comparison test is a technique for determining the convergence or divergence of a given series. This test is particularly useful when you have a series that is challenging to evaluate directly. It allows you to compare the series with another simpler series whose behavior is well known.

The basic strategy is straightforward: you take the limit of the ratio of the terms of your series to the terms of the simpler series. Formally, for two series \( \sum a_k \) and \( \sum b_k \), compute the limit \( \lim_{k \to \infty} \frac{a_k}{b_k} \).

If this limit is a positive finite number, then both series either converge or diverge together.
  • If \( \sum b_k \) converges, then \( \sum a_k \) converges.
  • If \( \sum b_k \) diverges, then \( \sum a_k \) diverges.
This is the key to solving the original exercise, as applying the limit comparison test to the series \( \sum_{k=1}^{\infty} \frac{k^{2}+1}{k^{2}+5} \) with the harmonic series \( \sum_{k=1}^{\infty} 1 \), which is known to diverge, allows us to conclude that the original series also diverges.
Divergent Series
A series is divergent if the sum of its terms does not approach a finite limit. In simpler terms, as you add more terms of a divergent series, the sum grows indefinitely without settling at a particular value.

The series derived from the original example, \( \sum_{k=1}^{\infty} 1 \), is perhaps the most famous divergent series: the harmonic series.
  • Despite the fact that each individual term \( \frac{1}{k} \) becomes very small as \( k \) increases, the sum of these terms gets infinitely large.
  • Divergence means the series does not converge to a stable limit.
This concept is crucial in understanding why certain series like \( \sum_{k=1}^{\infty} \frac{k^{2}+1}{k^{2}+5} \) diverge, especially after applying comparison tests with known divergent series like the harmonic series.
Harmonic Series
The harmonic series is a specific mathematical series that is often used as a benchmark to test for divergence. It is expressed as \( \sum_{k=1}^{\infty} \frac{1}{k} \).

Despite each term in the series decreasing and becoming closer to zero as \( k \) increases, the series as a whole never converges to a fixed number; instead, it grows infinitely large.
  • The harmonic series is a classic example of a divergent series.
  • Understanding this series helps when analyzing other series through the limit comparison test.
In the original exercise about convergence, the harmonic series \( \sum_{k=1}^{\infty} \frac{1}{k} \) serves as a tool to determine that \( \sum_{k=1}^{\infty} \frac{k^{2}+1}{k^{2}+5} \) is also divergent. The ratio of the series terms \( \frac{k^{2}+1}{k^{2}+5} \) closely matches the terms \( 1 \) of the harmonic series at large \( k \), confirming their similar divergent behavior.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.